QOJ.ac
QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#668944 | #7735. Primitive Root | potential | WA | 6ms | 3628kb | C++20 | 1.0kb | 2024-10-23 16:41:19 | 2024-10-23 16:41:20 |
Judging History
answer
# include <bits/stdc++.h>
using namespace std;
# define IOS ios::sync_with_stdio(0), cin.tie(0), cout.tie(0);
# define int long long
# define lowbit(x) (x & (-x))
# define fi first
# define se second
# define all(x) x.begin(), x.end()
// # define endl '\n'
inline int Read();
typedef pair<int, int> PII;
const int INF = 0x3f3f3f3f;
const int MOD = 998244353;
const int N = 1e6 + 10;
map <int, int> mp;
vector <int> v;
void Solve(){
int p, m;
cin >> p >> m;
if(m < p){
cout << 1 <<"\n";
return;
}
int t =max(0ll, m - p);
int ans = max(0ll, t / p);
if(t % p){
if((((ans + 1) * p) ^ (p - 1)) <= t) ans ++;
}
ans ++;
cout << ans <<"\n";
}
signed main(){
IOS;
int T = 1;
cin >> T;
while (T--)
Solve();
return 0;
}
inline int Read(){
int x = 0, f = 1; char c = getchar();
while (c < '0' || c > '9'){ if (c == '-') f = -1; c = getchar();}
while (c >= '0' && c <= '9') x = x * 10 + c - '0', c = getchar();
return x * f;
}
详细
Test #1:
score: 100
Accepted
time: 0ms
memory: 3628kb
input:
3 2 0 7 11 1145141 998244353
output:
1 2 872
result:
ok 3 lines
Test #2:
score: -100
Wrong Answer
time: 6ms
memory: 3572kb
input:
47595 2 0 2 1 2 2 2 3 2 4 2 5 2 6 2 7 2 8 2 9 2 10 2 11 2 12 2 13 2 14 2 15 2 16 2 17 2 18 2 19 2 20 2 21 2 22 2 23 2 24 2 25 2 26 2 27 2 28 2 29 2 30 2 31 2 32 2 33 2 34 2 35 2 36 2 37 2 38 2 39 2 40 2 41 2 42 2 43 2 44 2 45 2 46 2 47 2 48 2 49 2 50 2 51 2 52 2 53 2 54 2 55 2 56 2 57 2 58 2 59 2 60...
output:
1 1 1 1 2 2 3 3 4 4 5 5 6 6 7 7 8 8 9 9 10 10 11 11 12 12 13 13 14 14 15 15 16 16 17 17 18 18 19 19 20 20 21 21 22 22 23 23 24 24 25 25 26 26 27 27 28 28 29 29 30 30 31 31 32 32 33 33 34 34 35 35 36 36 37 37 38 38 39 39 40 40 41 41 42 42 43 43 44 44 45 45 46 46 47 47 48 48 49 49 50 50 51 51 52 52 53...
result:
wrong answer 3rd lines differ - expected: '2', found: '1'