QOJ.ac

QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#668230#7685. Barkley IIxDarkbluexWA 85ms3784kbC++172.6kb2024-10-23 12:52:022024-10-23 12:52:03

Judging History

你现在查看的是最新测评结果

  • [2024-10-23 12:52:03]
  • 评测
  • 测评结果:WA
  • 用时:85ms
  • 内存:3784kb
  • [2024-10-23 12:52:02]
  • 提交

answer

#include <bits/stdc++.h>
constexpr int N = 5e5 + 5;
constexpr int INF = 1e9;

struct Tree {
    int ls, rs;
    int val;
}t[N * 45];
int idx;

void pushup(int p) {
    t[p].val = t[t[p].ls].val + t[t[p].rs].val;
}

int build(int l, int r) {
    int p = ++idx;
    if (l == r) {
        return p;
    }
    int mid = l + r >> 1;
    t[p].ls = build(l, mid);
    t[p].rs = build(mid + 1, r);
    return p;
}

int modify(int now, int l, int r, int x, int val) {
    int p = ++idx;
    t[p] = t[now];
    if (l == r) {
        t[p].val = val;
        return p;
    }
    int mid = l + r >> 1;
    if (x <= mid) t[p].ls = modify(t[now].ls, l, mid, x, val);
    else t[p].rs = modify(t[now].rs, mid + 1, r, x, val);
    pushup(p);
    return p;
}

int query(int p, int l, int r, int ql, int qr) {
    if (ql > qr) return 0;
    if (!p) return 0;
    if (l >= ql && qr >= r) {
        return t[p].val;
    }
    int mid = l + r >> 1, ans = 0;
    if (ql <= mid) ans += query(t[p].ls, l, mid, ql, qr);
    if (qr > mid) ans += query(t[p].rs, mid + 1, r, ql, qr);
    return ans;
}

void solve() {
    int n, m;
    std::cin >> n >> m;

    idx = 0;

    std::vector<int> a(n + 1, 0);
    std::vector<std::vector<int>> pos(m + 1);
    std::vector<int> allnum;
    allnum.emplace_back(1);
    for (int i = 1; i <= n; i++) {
        std::cin >> a[i];
        pos[a[i]].emplace_back(i);
        allnum.emplace_back(a[i]);
    }
    
    std::sort(allnum.begin(), allnum.end());
    allnum.erase(std::unique(allnum.begin(), allnum.end()), allnum.end());

    std::vector<int> root(n + 1, 0);
    root[0] = build(1, n);

    
    std::vector<int> pre(m + 1, 0);
    for (int i = 1; i <= n; i++) {
        if (!pre[a[i]]) {
            root[i] = modify(root[i - 1], 1, n, i, 1);
            pre[a[i]] = i;
        } else {
            int tmp = modify(root[i - 1], 1, n, pre[a[i]], 0);
            root[i] = modify(tmp, 1, n, i, 1);
            pre[a[i]] = i;
        }
    }

    int ans = -1;
    for (auto mex : allnum) {
        for (int i = -1, len = (int)pos[mex].size(); i < len; i++) {
            int l = (i >= 0) ? pos[mex][i] : 0, r = (i + 1 < len) ? pos[mex][i + 1] : n + 1;
            ans = std::max(ans, ((l + 1 > r - 1) ? 0 : query(root[r - 1], 1, n, l + 1, r - 1)) - mex);
        }
    }

    std::cout << ans << '\n';

}

int main() {
    std::ios::sync_with_stdio(false);
    std::cin.tie(nullptr), std::cout.tie(nullptr);

    int T;
    std::cin >> T;

    while (T--) {
        solve();
    }
    return 0;
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 1ms
memory: 3784kb

input:

2
5 4
1 2 2 3 4
5 10000
5 2 3 4 1

output:

2
3

result:

ok 2 number(s): "2 3"

Test #2:

score: -100
Wrong Answer
time: 85ms
memory: 3572kb

input:

50000
10 19
12 6 1 12 11 15 4 1 13 18
10 8
8 7 6 7 6 2 2 3 4 8
10 6
3 2 6 6 5 2 3 4 5 6
10 11
6 3 7 9 2 1 2 10 10 4
10 6
6 1 2 6 1 1 3 4 2 1
10 9
8 5 3 9 1 7 5 5 1 1
10 5
1 4 3 2 5 4 5 3 5 2
10 14
3 8 12 10 4 2 3 13 7 3
10 14
5 5 12 2 8 1 13 9 8 5
10 7
5 5 6 6 1 5 3 7 3 4
10 7
5 1 4 6 1 6 4 3 7 5
10...

output:

3
5
4
4
2
3
3
7
3
3
4
5
2
3
6
6
7
3
7
6
5
5
6
2
6
8
6
2
5
5
6
1
2
2
4
5
3
3
7
3
2
5
6
1
3
3
2
3
1
4
6
6
4
7
2
4
5
3
6
6
6
3
7
3
6
3
3
4
7
6
6
7
4
3
3
4
4
6
3
3
6
6
4
5
5
9
4
5
7
5
3
5
1
2
5
6
6
8
4
3
4
5
5
3
7
4
3
2
3
4
3
5
4
4
2
6
6
4
4
5
7
4
5
7
4
7
3
7
6
6
6
5
4
2
5
4
2
3
4
4
2
6
4
5
4
3
5
6
6
6
...

result:

wrong answer 1st numbers differ - expected: '6', found: '3'