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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#668069#5576. Advertising ICPCenze114514TL 1ms3728kbC++203.1kb2024-10-23 11:05:172024-10-23 11:05:24

Judging History

你现在查看的是最新测评结果

  • [2024-10-23 11:05:24]
  • 评测
  • 测评结果:TL
  • 用时:1ms
  • 内存:3728kb
  • [2024-10-23 11:05:17]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;

typedef long long ll;

const int MOD = 998244353;

ll pow3(int k) {
    ll res = 1;
    ll base = 3;
    while(k > 0){
        if(k & 1){
            res = res * base % MOD;
        }
        base = base * base % MOD;
        k >>=1;
    }
    return res;
}

int main(){
    ios::sync_with_stdio(false);
    cin.tie(0);
    
    int n, m;
    cin >> n >> m;
    vector<string> grid(n);
    int k =0;
    for(int i=0;i<n;i++) {
        cin >> grid[i];
        for(int j=0;j<m;j++) if(grid[i][j] == '?') k++;
    }
    
    int total_states = pow(3, m);
    vector<int> allowed_states(n);
    vector<vector<int>> states_per_row(n);

    vector<vector<int>> state_cells(n, vector<int>(total_states * m, 0));
    for(int r=0;r<n;r++){
        for(int s=0;s<pow(3, m);s++){
            bool valid = true;
            int tmp = s;
            for(int j=0;j<m;j++){
                int val = tmp %3;
                tmp /=3;
                if(grid[r][j] != '?'){
                    if((grid[r][j] == 'C' && val !=0) || 
                       (grid[r][j] == 'I' && val !=1) || 
                       (grid[r][j] == 'P' && val !=2)){
                           valid = false;
                           break;
                       }
                }
                state_cells[r][s * m + j] = val;
            }
            if(valid){
                states_per_row[r].push_back(s);
            }
        }
    }
    
    vector<vector<vector<int>>> transitions(n, vector<vector<int>>(pow(3, m), vector<int>()));
    for(int r=1;r<n;r++){
        for(auto s_prev : states_per_row[r-1]){
            for(auto s_curr : states_per_row[r]){
                bool forbidden = false;
                for(int j=0; j<m-1 && !forbidden; j++){
                    int cell_prev_j = (s_prev / (int)pow(3, j)) %3;
                    int cell_prev_j1 = (s_prev / (int)pow(3, j+1)) %3;
                    int cell_curr_j = (s_curr / (int)pow(3, j)) %3;
                    int cell_curr_j1 = (s_curr / (int)pow(3, j+1)) %3;
                    if(cell_prev_j ==1 && cell_prev_j1 ==0 && cell_curr_j ==2 && cell_curr_j1 ==0){
                        forbidden = true;
                        break;
                    }
                }
                if(!forbidden){
                    transitions[r][s_prev].push_back(s_curr);
                }
            }
        }
    }
    
    vector<ll> dp_prev(pow(3, m), 0);
    for(auto s : states_per_row[0]){
        dp_prev[s] =1;
    }
    
    for(int r=1;r<n;r++){
        vector<ll> dp_curr(pow(3, m), 0);
        for(auto s_prev : states_per_row[r-1]){
            if(dp_prev[s_prev]==0) continue;
            for(auto s_curr : transitions[r][s_prev]){
                dp_curr[s_curr] = (dp_curr[s_curr] + dp_prev[s_prev]) % MOD;
            }
        }
        dp_prev = move(dp_curr);
    }
    
    ll A =0;
    for(auto s : states_per_row[n-1]){
        A = (A + dp_prev[s]) % MOD;
    }
    
    ll T = pow3(k);
    
    ll answer = (T - A + MOD) % MOD;
    cout << answer;
}

詳細信息

Test #1:

score: 100
Accepted
time: 1ms
memory: 3728kb

input:

3 3
???
?I?
???

output:

243

result:

ok single line: '243'

Test #2:

score: 0
Accepted
time: 0ms
memory: 3724kb

input:

2 2
IC
PC

output:

1

result:

ok single line: '1'

Test #3:

score: -100
Time Limit Exceeded

input:

8 8
????????
????????
????????
????????
????????
????????
????????
????????

output:


result: