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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#667264#7627. PhonyMiniLongWA 1ms3856kbC++144.0kb2024-10-22 21:57:412024-10-22 21:57:51

Judging History

你现在查看的是最新测评结果

  • [2024-10-22 21:57:51]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:3856kb
  • [2024-10-22 21:57:41]
  • 提交

answer

#include <bits/stdc++.h>
#define _rep(i, x, y) for(int i = x; i <= y; ++i)
#define _req(i, x, y) for(int i = x; i >= y; --i)
#define _rev(i, u) for(int i = head[u]; i; i = e[i].nxt)
#define pb push_back
#define fi first
#define se second
#define mst(f, i) memset(f, i, sizeof f)
using namespace std;
#ifdef ONLINE_JUDGE
#define debug(...) 0
#else
#define debug(...) fprintf(stderr, __VA_ARGS__), fflush(stderr)
#endif
typedef long long ll;
typedef pair<ll, ll> PII;
namespace fastio{
    #ifdef ONLINE_JUDGE
    char ibuf[1 << 20],*p1 = ibuf, *p2 = ibuf;
    #define get() p1 == p2 && (p2 = (p1 = ibuf) + fread(ibuf, 1, 1 << 20, stdin), p1 == p2) ? EOF : *p1++
    #else
    #define get() getchar()
    #endif
    template<typename T> inline void read(T &t){
        T x = 0, f = 1;
        char c = getchar();
        while(!isdigit(c)){
            if(c == '-') f = -f;
            c = getchar();
        }
        while(isdigit(c)) x = x * 10 + c - '0', c = getchar();
        t = x * f;
    }
    template<typename T, typename ... Args> inline void read(T &t, Args&... args){
        read(t);
        read(args...);
    }
    template<typename T> void write(T t){
        if(t < 0) putchar('-'), t = -t;
        if(t >= 10) write(t / 10);
        putchar(t % 10 + '0');
    }
    template<typename T, typename ... Args> void write(T t, Args... args){
        write(t), putchar(' '), write(args...);
    }
    template<typename T> void writeln(T t){
        write(t);
        puts("");
    }
    template<typename T> void writes(T t){
        write(t), putchar(' ');
    }
    #undef get
};
using namespace fastio;
#define multitest() int T; read(T); _rep(tCase, 1, T)
namespace Calculation{
    const ll mod = 998244353;
    ll ksm(ll p, ll h){ll base = p % mod, res = 1; while(h){if(h & 1ll) res = res * base % mod; base = base * base % mod, h >>= 1ll;} return res;}
    void dec(ll &x, ll y){x = ((x - y) % mod + mod) % mod;}
    void add(ll &x, ll y){x = (x + y) % mod;}
    void mul(ll &x, ll y){x = x * y % mod;}
    ll sub(ll x, ll y){return ((x - y) % mod + mod) % mod;}
    ll pls(ll x, ll y){return ((x + y) % mod + mod) % mod;}
    ll mult(ll x, ll y){return x * y % mod;}
}
using namespace Calculation;
const int N = 5e5 + 5;
ll n, m, k, pos, t, tag, cur, a[N];
set<PII> st;
ll lst, now;
ll ask(ll k){//第k小的数
    auto it = st.begin();
    _rep(i, 1, k - 1) it = next(it);
    return (*it).fi;
}
void update(ll t){
    ll len = n - pos + 1;
    if(t >= now){
        t -= now, now = 0, lst = (*st.begin()).fi - tag * k;
        while(t > 0 && pos > 1){
            if(lst < a[pos - 1]){
                st.insert({a[pos - 1] + tag * k, pos - 1});
                pos--, len++;
                continue;
            }
            ll o = ((lst - a[pos - 1]) / k + 1) * len;
            if(o > t) break;
            tag += ((lst - a[pos - 1]) / k + 1);
            st.insert({a[pos - 1] + tag * k, pos - 1});
            t -= o;
            pos--, len++;
        }
        if(pos == 1){
            tag += t / n; t %= n;
            lst = (*st.begin()).fi - tag * k;
        }
    }
    if(t){
        if(!now) tag++, now = len - t;
        else now -= t;
        lst = ask(now + 1) - tag * k;
        while(pos > 1 && a[pos - 1] > lst) st.insert({a[pos - 1] + tag * k, pos - 1}), pos--, len++;
    }
}

ll getrk(ll rk){
    ll len = n - pos + 1;
    if(rk > len) return a[pos - (rk - len)];
    if(rk <= now) return ask(now - rk + 1) - (tag - 1) * k;
    ll t = rk - now;
    t = len - t + 1;
    return ask(t) - tag * k;
}
int main(){
    read(n, m, k);
    _rep(i, 1, n) read(a[i]);
    sort(a + 1, a + 1 + n);
    st.insert({a[n], n}), pos = n;
    // debug("eee\n");
    while(m--){
        char ch[2]; ll x;
        scanf("%s", ch); 
        // debug("eee\n"); 
        read(x);
        if(ch[0] == 'C'){
            update(x);
        }
        if(ch[0] == 'A'){
            writeln(getrk(x));
        }
    }
    return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 1ms
memory: 3836kb

input:

3 5 5
7 3 9
A 3
C 1
A 2
C 2
A 3

output:

3
4
-1

result:

ok 3 lines

Test #2:

score: -100
Wrong Answer
time: 1ms
memory: 3856kb

input:

5 8 8
294 928 293 392 719
A 4
C 200
A 5
C 10
A 2
C 120
A 1
A 3

output:

294
160
312
-96
30

result:

wrong answer 2nd lines differ - expected: '200', found: '160'