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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#666555 | #8339. Rooted Tree | tilenn | TL | 250ms | 5484kb | C++14 | 2.7kb | 2024-10-22 19:01:56 | 2024-10-22 19:02:03 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
#define endl '\n'
typedef long long LL;
template<class T>
T qmi(T a,LL k){
T res = 1;
while(k){
if(k & 1)res *= a;
a *= a;
k >>= 1;
}
return res;
}
struct MInt{
int v;
const static int Mod;
MInt() : v() {}
MInt(LL _v) : v(norm(_v % Mod)) {}
static int getMod(){
return Mod;
}
int norm(int x) const {
if(x < 0){
x += Mod;
}else if(x >= Mod){
x -= Mod;
}
return x;
}
int val() const {return v;}
MInt operator-() const {
MInt res;
res.v = norm(Mod - v);
return res;
}
MInt inv() const {
return qmi(*this,Mod - 2);
}
MInt &operator*=(MInt rhs) & {
v = 1LL * v * rhs.v % Mod;
return *this;
}
MInt &operator+=(MInt rhs) & {
v = norm(v + rhs.v);
return *this;
}
MInt &operator-=(MInt rhs) & {
v = norm(v - rhs.v);
return *this;
}
MInt &operator/=(MInt rhs) & {
return *this *= rhs.inv();
}
friend MInt operator*(MInt lhs, MInt rhs) {
return 1LL * lhs.val() * rhs.val();
}
friend MInt operator+(MInt lhs, MInt rhs) {
return lhs.val() + rhs.val();
}
friend MInt operator-(MInt lhs, MInt rhs) {
return lhs.val() - rhs.val();
}
friend MInt operator/(MInt lhs, MInt rhs) {
return 1LL * lhs.val() * rhs.inv().val();
}
friend std::istream &operator>>(std::istream &is, MInt &a) {
LL v;
is >> v;
a = MInt(v);
return is;
}
friend std::ostream &operator<<(std::ostream &os, const MInt &a) {
return os << a.val();
}
friend bool operator<(MInt lhs,MInt rhs) {
return lhs.val() < rhs.val();
}
friend bool operator==(MInt lhs, MInt rhs) {
return lhs.val() == rhs.val();
}
friend bool operator!=(MInt lhs, MInt rhs) {
return lhs.val() != rhs.val();
}
};
const int MInt::Mod = 1e9 + 9;
using Z = MInt;
void solve(){
int m,k;
cin >> m >> k;
vector<Z> dp(k + 1);
Z res = 0;
for(int i = 1;i <= k;i++){
res += dp[i - 1] / (1 + (i - 1) * (m - 1));
dp[i] = dp[i - 1] - (dp[i - 1] / (1 + (i - 1) * (m - 1))) + (dp[i - 1] / (1 + (i - 1) * (m - 1)) + 1) * m;
}
res += dp[k];
cout << res << endl;
//1,m,2m - 1,3m - 2,4m - 3... km + k - 1
}
int main(){
ios::sync_with_stdio(false);
cin.tie(NULL),cout.tie(NULL);
int t = 1;
//cin >> t;
while(t--){
solve();
}
return 0;
}
Details
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Test #1:
score: 100
Accepted
time: 0ms
memory: 3556kb
input:
6 2
output:
18
result:
ok 1 number(s): "18"
Test #2:
score: 0
Accepted
time: 0ms
memory: 3816kb
input:
2 6
output:
600000038
result:
ok 1 number(s): "600000038"
Test #3:
score: 0
Accepted
time: 250ms
memory: 5484kb
input:
83 613210
output:
424200026
result:
ok 1 number(s): "424200026"
Test #4:
score: -100
Time Limit Exceeded
input:
48 6713156