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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#665571#7739. Knapsack369Pai#RE 0ms3820kbC++14989b2024-10-22 14:08:352024-10-22 14:08:35

Judging History

你现在查看的是最新测评结果

  • [2024-10-22 14:08:35]
  • 评测
  • 测评结果:RE
  • 用时:0ms
  • 内存:3820kb
  • [2024-10-22 14:08:35]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;

int n, m, k;
int dp[5005][10005];
struct node {int w, v;} a[5005];
priority_queue<pair<int, int>, vector<pair<int, int>>, greater<>> q;
long long sum, ans;

int main() {
	scanf("%d%d%d", &n, &m, &k);
	for (int i = 1; i <= n; i++) scanf("%d%d", &a[i].w, &a[i].v);
	sort(a + 1, a + n + 1, [](const node &x, const node &y) {return x.v > y.v;});
	for (int i = n; i >= 1; i--) {
		for (int j = 0; j < a[i].v; j++) dp[i][j] = dp[i + 1][j];
		for (int j = a[i].w; j <= m; j++)
			dp[i][j] = max(dp[i + 1][j], dp[i + 1][j - a[i].w] + a[i].v);
	}
	for (int i = 1; i <= k; i++) sum += a[i].v, q.emplace(a[i].w, i);
	ans = sum + dp[k + 1][m];
	for (int W = m, p = k; !q.empty() && W > 0; ) {
		int id = q.top().second;
		q.pop();
		if (a[id].w > W) break;
		W -= a[id].w;
		if (p < n) {
			p++;
			sum += a[p].v;
			q.emplace(a[p].w, p);
		}
		ans = max(ans, sum + dp[p + 1][W]);
	}
	printf("%lld\n", ans);
	return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 0ms
memory: 3780kb

input:

4 10 1
9 10
10 1
3 5
5 20

output:

35

result:

ok 1 number(s): "35"

Test #2:

score: 0
Accepted
time: 0ms
memory: 3820kb

input:

5 13 2
5 16
5 28
7 44
8 15
8 41

output:

129

result:

ok 1 number(s): "129"

Test #3:

score: -100
Runtime Error

input:

10 50 1
44 182173741
38 163268500
36 114173760
30 521894533
25 89514235
12 516184197
42 971377551
35 28242326
31 480227821
31 388523197

output:


result: