#include<iostream>
#include<string.h>
#include<algorithm>
#include<math.h>
#include<vector>
#include<map>
#include<queue>
#include<set> 
#include<stack>
#include<bitset>
#include<unordered_map>
#include<iomanip>
#include<cassert>
#include<array>
#define fi first
#define se second
#define endl '\n'
#define pb push_back
#define ep emplace_back 
#define debug(x) cout<<x<<'\n'
#define RES cout<<res<<'\n'
#define ANS cout<<ans<<'\n'
#define YES	cout<<"YES"<<'\n'
#define NO cout<<"NO"<<'\n'
#define Yes	cout<<"Yes"<<'\n'
#define No cout<<"No"<<'\n'
#define me(a,x) memset(a,x,sizeof(a))
#define L(i,j,k) for(int i=(j);i<=(k);++i)
#define R(i,j,k) for(int i=(j);i>=(k);--i)
#define r23 cout<<233<<endl;return;
#define int long long 
using namespace std;
typedef long long ll;
typedef pair<int,int> PII;
typedef pair<PII,int> PIII;
typedef unsigned long long ull;
const int N=1e5+5,P=131,mod=998244353;
int qmi(int a,int b){
	int res=1;
	while(b){
		if(b&1)res=res*a%mod;
		a=a*a%mod;
		b>>=1;
	}
	return res;
}
int inv(int a,int b){
	return qmi(a,b-2);
}

void solve(){
	int n,a,b;
	cin>>n>>a>>b;
	n=3*(n-1);
	if(a+b-2<=n-a+n-b){
		n-=(a+b-2);
		L(i,1,n/2)cout<<'L';
		L(i,1,n/2)cout<<'U';
		if(n&1)cout<<'U';
		L(i,1,a-1)cout<<'D';
		L(i,1,b-1)cout<<'R'; 
	}else{
		n-=(n-a+n-b);
		L(i,1,n/2)cout<<'R';
		L(i,1,n/2)cout<<'D';
		if(n&1)cout<<'R';
		L(i,1,n-a)cout<<'L';
		L(i,1,n-b)cout<<'U'; 
	}
	
}
signed main(){
	ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
	int T=1;
	//cin>>T;
	while(T--){
		solve();
	}
}