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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#664562 | #6531. Base Station Construction | Ayaya | TL | 1ms | 9892kb | C++14 | 2.2kb | 2024-10-21 21:12:24 | 2024-10-21 21:12:26 |
Judging History
answer
#include<bits/stdc++.h>
#include<iostream>
#include<algorithm>
#include<cstdio>
#include<cstring>
#include<string>
#include<cmath>
#include<unordered_map>
#include<vector>
#include<bitset>
#include<queue>
#include<set>
#include<map>
#include<ctime>
#include<random>
#include<numeric>
using namespace std;
#define int long long
#define ll long long
#define ull unsigned long long
#define lc (x<<1)
#define rc (x<<1|1)
#define pii pair<int,int>
#define mkp make_pair
#define fi first
#define se second
#define cout (cerr<<">> ",cout)
const int Mx=500005,p=998244353;
int read(){
char ch=getchar();
int Alice=0,Aya=1;
while(ch<'0'||ch>'9'){
if(ch=='-') Aya=-Aya;
ch=getchar();
}
while(ch>='0'&&ch<='9')
Alice=(Alice<<3)+(Alice<<1)+(ch^48),ch=getchar();
return (Aya==1?Alice:-Alice);
}
int n,m;
int cost[Mx];
struct Seg{
int l,r;
bool operator <(const Seg&o)const{
return l==o.l?r<o.r:l<o.l;
}
}a[Mx],c[Mx];
int f[Mx];
int t[Mx];
void Ins(int i,int k){
for(;i<=m+1;i+=(i&-i)) t[i]=min(t[i],k);
}
int Qry(int i){
int res=1e18;
for(;i;i&=(i-1)) res=min(res,t[i]);
return res;
}
void Solve(){
n=read();
for(int i=1;i<=n;i++) cost[i]=read();
m=read();
for(int i=0;i<=m+1;i++) t[i]=1e18;
for(int i=1;i<=m;i++){
a[i].l=read(),a[i].r=read();
}
sort(a+1,a+m+1);
int M=1;
for(int i=2;i<=m;i++){
if(a[i].l==a[M].l) continue;
if(a[i].r<=a[M].r) a[M]=a[i];
else a[++M]=a[i];
}
m=M;
int ans=1e18;
Ins(m+1,0);
for(int i=1;i<=n;i++){
int L=1,R=m,ok=-1;
while(L<=R){
int mid=((L+R)>>1);
if(a[mid].r>=i) R=mid-1,ok=mid;
else L=mid+1;
}
c[i].l=ok;
L=1,R=m,ok=-1;
while(L<=R){
int mid=((L+R)>>1);
if(a[mid].l<=i) L=mid+1,ok=mid;
else R=mid-1;
}
c[i].r=ok;
//cout<<c[i].l<<" "<<c[i].r<<endl;
if(c[i].l==-1||c[i].r==-1){
f[i]=1e18;
continue;
}
int res=1e18;
for(int j=0;j<i;j++){
if(c[j].r+1>=c[i].l) res=min(res,f[j]);
}
f[i]=res+cost[i];
Ins(m+2-(c[i].r+1),f[i]);
if(c[i].r==m) ans=min(ans,f[i]);
}
printf("%lld\n",ans);
}
signed main(){
int T=read();
while(T--) Solve();
return 0;
}
/*
Hello!!
Sample:
-------------------
*/
Details
Tip: Click on the bar to expand more detailed information
Test #1:
score: 100
Accepted
time: 1ms
memory: 9892kb
input:
2 5 3 2 4 1 100 3 1 3 2 4 5 5 5 7 3 4 2 2 3 1 4 2 3 4 5
output:
102 5
result:
ok 2 number(s): "102 5"
Test #2:
score: -100
Time Limit Exceeded
input:
6201 12 88 78 46 95 84 98 55 3 68 42 6 18 19 6 9 10 11 12 12 8 11 8 12 2 3 2 3 1 5 9 9 7 8 6 11 2 4 12 12 2 4 2 9 7 10 8 8 1 7 6 11 5 76 27 48 66 61 2 1 4 3 5 8 64 81 20 6 86 9 4 55 1 7 7 9 1 43 18 81 11 22 9 61 83 14 5 6 2 6 5 8 1 4 9 9 9 9 7 7 2 5 8 9 5 6 4 8 5 8 9 9 6 6 10 66 41 84 7 80 31 22 96 ...
output:
141 48 4 126 303 141 23 170 159 139 153 194 136 89 230 93 287 89 124 130 148 27 1 193 194 93 239 303 236 150 177 57 46 18 24 66 83 160 108 62 35 122 156 77 115 138 54 242 126 28 171 86 311 244 262 87 302 81 86 173 30 129 75 91 90 179 81 196 142 154 77 111 194 247 211 53 66 17 213 101 308 137 177 24 ...