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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#664014#4377. BackpackicealsoheatAC ✓293ms3904kbC++205.3kb2024-10-21 18:56:362024-10-21 18:56:37

Judging History

你现在查看的是最新测评结果

  • [2024-10-21 18:56:37]
  • 评测
  • 测评结果:AC
  • 用时:293ms
  • 内存:3904kb
  • [2024-10-21 18:56:36]
  • 提交

answer

#pragma GCC optimize(3)  //O2优化开启
#include<bits/stdc++.h>
using namespace std;
#define int long long
typedef long long ll;
typedef unsigned long long ull;
typedef pair<int,int> PII;
const int mod=998244353;
const int MX=0x3f3f3f3f3f3f3f3f; 
//inline int read()                     //快读
//{
//    int xr=0,F=1; char cr;
//    while(cr=getchar(),cr<'0'||cr>'9') if(cr=='-') F=-1;
//    while(cr>='0'&&cr<='9')
//        xr=(xr<<3)+(xr<<1)+(cr^48),cr=getchar();
//    return xr*F;
//}
//void write(int x)                     //快写
//{
//    if(x<0) putchar('-'),x=-x;
//    if(x>9) write(x/10); putchar(x%10+'0');
//}
// 比 unordered_map 更快的哈希表
// #include <ext/pb_ds/assoc_container.hpp>
// using namespace __gnu_pbds;
// const int RANDOM = chrono::high_resolution_clock::now().time_since_epoch().count();
// struct chash {
//     int operator()(int x) const { return x ^ RANDOM; }
// };
// typedef gp_hash_table<int, int, chash> hash_t;

template<int P>
struct MInt {
    int x;
    constexpr MInt() : x{} {}
    constexpr MInt(ll x) : x{norm(x % getMod())} {}

    static int Mod;
    constexpr static int getMod() {
        if (P > 0) {
            return P;
        } else {
            return Mod;
        }
    }
    constexpr static void setMod(int Mod_) {
        Mod = Mod_;
    }
    constexpr int norm(int x) const {
        if (x < 0) {
            x += getMod();
        }
        if (x >= getMod()) {
            x -= getMod();
        }
        return x;
    }
    constexpr int val() const {
        return x;
    }
    explicit constexpr operator int() const {
        return x;
    }
    constexpr MInt operator-() const {
        MInt res;
        res.x = norm(getMod() - x);
        return res;
    }
    constexpr MInt inv() const {
        assert(x != 0);
        return power(*this, getMod() - 2);
    }
    constexpr MInt &operator*=(MInt rhs) & {
        x = 1LL * x * rhs.x % getMod();
        return *this;
    }
    constexpr MInt &operator+=(MInt rhs) & {
        x = norm(x + rhs.x);
        return *this;
    }
    constexpr MInt &operator-=(MInt rhs) & {
        x = norm(x - rhs.x);
        return *this;
    }
    constexpr MInt &operator/=(MInt rhs) & {
        return *this *= rhs.inv();
    }
    friend constexpr MInt power(MInt a, ll b) {
        MInt res = 1;
        for (; b; b /= 2, a *= a) {
            if (b % 2) {
                res *= a;
            }
        }
        return res;
    }
    friend constexpr MInt operator*(MInt lhs, MInt rhs) {
        MInt res = lhs;
        res *= rhs;
        return res;
    }
    friend constexpr MInt operator+(MInt lhs, MInt rhs) {
        MInt res = lhs;
        res += rhs;
        return res;
    }
    friend constexpr MInt operator-(MInt lhs, MInt rhs) {
        MInt res = lhs;
        res -= rhs;
        return res;
    }
    friend constexpr MInt operator/(MInt lhs, MInt rhs) {
        MInt res = lhs;
        res /= rhs;
        return res;
    }
    friend constexpr std::istream &operator>>(std::istream &is, MInt &a) {
        ll v;
        is >> v;
        a = MInt(v);
        return is;
    }
    friend constexpr std::ostream &operator<<(std::ostream &os, const MInt &a) {
        return os << a.val();
    }
    friend constexpr bool operator==(MInt lhs, MInt rhs) {
        return lhs.val() == rhs.val();
    }
    friend constexpr bool operator!=(MInt lhs, MInt rhs) {
        return lhs.val() != rhs.val();
    }
};

template<int V, int P>
constexpr MInt<P> CInv = MInt<P>(V).inv();

constexpr int P = 998244353;            //这里为自动模数
using mint = MInt<P>;           //mint是其定理的类型

int n,m;

bitset<1028>dp[1028];

bitset<1028>dpp[1028];

void icealsoheat(){
    
    cin>>n>>m;
    for(int i=0;i<1024;i++)dp[i]=0;

    dp[0]=1;

    int ans=-1;

    for(int i=1;i<=n;i++){

        int v,w;
        cin>>v>>w;

        for(int j=0;j<1024;j++){

            dpp[j]=dp[j];

        }

        for(int j=0;j<1024;j++){
            dpp[j]|=dp[j^w]<<v;
            
            if(dpp[j][m]){
                ans=max(ans,j);
            }

        }

        swap(dpp,dp);

    }

    cout<<ans<<"\n";

}
signed main(){
    ios::sync_with_stdio(false);          //int128不能用快读!!!!!!
    cin.tie();
    cout.tie();
    int _yq;
    _yq=1;
    cin>>_yq;
    while(_yq--){
        icealsoheat();
    }
}
//
//⠀⠀⠀             ⠀⢸⣿⣿⣿⠀⣼⣿⣿⣦⡀
//⠀⠀⠀⠀⠀⠀⠀⠀⠀⣀⠀⠀⠀ ⠀⢸⣿⣿⡟⢰⣿⣿⣿⠟⠁
//⠀⠀⠀⠀⠀⠀⠀⢰⣿⠿⢿⣦⣀⠀⠘⠛⠛⠃⠸⠿⠟⣫⣴⣶⣾⡆
//⠀⠀⠀⠀⠀⠀⠀⠸⣿⡀⠀⠉⢿⣦⡀⠀⠀⠀⠀⠀⠀ ⠛⠿⠿⣿⠃
//⠀⠀⠀⠀⠀⠀⠀⠀⠙⢿⣦⠀⠀⠹⣿⣶⡾⠛⠛⢷⣦⣄⠀
//⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣿⣧⠀⠀⠈⠉⣀⡀⠀ ⠀⠙⢿⡇
//⠀⠀⠀⠀⠀⠀⢀⣠⣴⡿⠟⠋⠀⠀⢠⣾⠟⠃⠀⠀⠀⢸⣿⡆
//⠀⠀⠀⢀⣠⣶⡿⠛⠉⠀⠀⠀⠀⠀⣾⡇⠀⠀⠀⠀⠀⢸⣿⠇
//⢀⣠⣾⠿⠛⠁⠀⠀⠀⠀⠀⠀⠀⢀⣼⣧⣀⠀⠀⠀⢀⣼⠇
//⠈⠋⠁⠀⠀⠀⠀⠀⠀⠀⠀⢀⣴⡿⠋⠙⠛⠛⠛⠛⠛⠁
//⠀⠀⠀⠀⠀⠀⠀⠀⠀⣀⣾⡿⠋⠀
//⠀⠀⠀⠀⠀⠀⠀⠀⢾⠿⠋⠀
//

详细

Test #1:

score: 100
Accepted
time: 293ms
memory: 3904kb

input:

10
1023 401
179 441
416 951
420 984
1013 984
683 914
407 984
96 523
374 190
974 190
739 441
518 523
194 984
415 523
149 441
235 984
809 441
469 441
436 919
437 919
7 919
818 984
962 190
37 919
371 523
417 914
431 914
213 190
340 441
254 919
223 951
123 190
339 951
322 441
218 441
284 919
533 190
187...

output:

1021
1011
-1
1023
1023
1023
1023
1023
1023
513

result:

ok 10 lines