#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define int long long
int a[100010];
int n,m;
struct seg{//楼房重建(pushup(log)),解决计算前缀下最小值/最大值位置数量问题
    #define mx(x) tr[x].mx
    #define num(x)  tr[x].num
    #define tag1(x)  tr[x].tag1
    #define tag2(x)  tr[x].tag2
    struct node{
        int mx;int num;//num(x)表示只考虑这一段(l,r)时的答案
        int tag1;int tag2;
    }tr[400010];
    void build(int p,int l,int r,vector<int>& ve){
        mx(p)=num(p)=tag1(p)=tag2(p)=0;
        if(l==r){
            mx(p)=ve[l];num(p)=1;
            return ;
        }
        int mid=(l+r)>>1;
        build(p<<1,l,mid,ve);build(p<<1|1,mid+1,r,ve);
        pushup1(p);
        num(p)=get(p,l,r);
    }
    void pushup1(int p){
        mx(p)=max(mx(p<<1),mx(p<<1|1));
    }
    int pushup2(int p,int l,int r,int len){
        if(l==r)    return mx(p)>len;
        spread(p);
        if(mx(p)<=len)   return 0;
        int mid=(l+r)>>1;
        if(mx(p<<1|1)>len)    return num(p)-num(p<<1|1)+pushup2(p<<1|1,mid+1,r,len);
        else return pushup2(p<<1,l,mid,len);
    }
    void spread(int p){
        tag1(p<<1)+=tag1(p),tag1(p<<1|1)+=tag1(p);
        mx(p<<1)+=tag1(p);mx(p<<1|1)+=tag1(p);
        tag1(p)=0;
        if(tag2(p)){
            mx(p<<1)=tag2(p),mx(p<<1|1)=tag2(p);num(p<<1)=1,num(p<<1|1)=1;
            tag2(p<<1)=tag2(p),tag2(p<<1|1)=tag2(p);
            tag2(p)=0;
        }
    }
    int get(int p,int l,int r){
        int mid=(l+r)>>1;spread(p);
        return num(p<<1|1)+((mx(p<<1)<=mx(p<<1|1))?0:pushup2(p<<1,l,mid,mx(p<<1|1)));
    }
    void modify(int p,int l,int r,int L,int R,int ad,int t){//0覆盖，1加法
        if(l!=r)    spread(p);
        if(L<=l&&r<=R){
            if(t==0)    {tag2(p)=ad;mx(p)=ad,num(p)=1;}
            else {
                tag1(p)+=ad;
                mx(p)+=ad;
            }
            return ;
        }
        int mid=(l+r)>>1;
        if(mid>=L)  modify(p<<1,l,mid,L,R,ad,t);
        if(mid<R)   modify(p<<1|1,mid+1,r,L,R,ad,t);
        pushup1(p);
        num(p)=get(p,l,r);
    }
    void modify(int l,int r,int num,int t){
        modify(1,1,n,l,r,num,t);
    }
    int queryL(int p,int l,int r,int L,int R,int nz){
        if(l==r){
            return mx(p)>nz?l:-1;
        }   
        spread(p);
        int mid=(l+r)>>1;
        if(mid<R&&mx(p<<1|1)>nz){
            int t=queryL(p<<1|1,mid+1,r,L,R,nz);
            if(t!=-1)   return t;
        }  
        return queryL(p<<1,l,mid,L,R,nz);
    }
    int queryL(int pz,int num){//pz左边第一个比它大的位置
        if(pz==1)   return -1;
        return queryL(1,1,n,1,pz-1,num);
    }

    int ask(int p,int l,int r,int L,int R){
        if(L<=l&&r<=R)  return mx(p);
        spread(p);
        int mid=(l+r)>>1;
        if(mid>=L&&mid<R)   return max(ask(p<<1,l,mid,L,R),ask(p<<1|1,mid+1,r,L,R));
        if(mid>=L)  return  ask(p<<1,l,mid,L,R);
        if(mid<R)   return  ask(p<<1|1,mid+1,r,L,R);
        return -1;
    }

    int ask(int l,int r){
        return ask(1,1,n,l,r);
    }

    int query_stack_num(int p,int l,int r,int L,int R,int nz){
        if(L<=l&&r<=R)  return pushup2(p,l,r,nz);
        int mid=(l+r)>>1;
        if(mid>=L&&mid<R)   {
            int nxtl=max(nz,mx(p>>1|1));
            return max(query_stack_num(p<<1,l,mid,L,R,nxtl),query_stack_num(p<<1|1,mid+1,r,L,R,nz));
        }
        if(mid>=L)  return  query_stack_num(p<<1,l,mid,L,R,nz);
        if(mid<R)   return  query_stack_num(p<<1|1,mid+1,r,L,R,nz);
        return -1;
    }

    int query_stack_num(int l,int r,int nz){
        return query_stack_num(1,1,n,l,r,nz);
    }
};
seg sg;
void solve(){
    cin>>n>>m;
    vector<int> a(n+1);
    for(int i=1;i<=n;i++){
        cin>>a[i];
    }
    struct node{
        int op,l,r,x;
    };
    vector<node> ak(m+1);
    vector<int> ans(m+1,0);
    for(int i=1;i<=m;i++){
        cin>>ak[i].op>>ak[i].l>>ak[i].r>>ak[i].x;
    }
    auto ope=[&](vector<int>& ve,vector<node>& qry)->void {
        sg.build(1,1,n,ve);
        for(int i=1;i<=m;i++){
            auto [op,l,r,x]=qry[i];
            if(op==1){
                sg.modify(l,r,x,1);
            }
            else if(op==2){
                sg.modify(l,r,x,0);
            }
            else if(l!=-1){
                int w=sg.ask(x,x);
                int pz=sg.queryL(x,w);
                ans[i]+=max(r-max(l,pz)+1,0ll);
                if(pz>l) ans[i]+=sg.query_stack_num(l,min(r,pz-1),sg.ask(pz,pz));
            }
        }
    };
    vector<node> qry1(m+1),qry2(m+1);
    for(int i=1;i<=m;i++){
        if(ak[i].op!=3) qry1[i]=qry2[i]=ak[i];
        else{
            auto [op,l,r,x]=ak[i];
            if(x<=r&&x>=l)  {
                ans[i]++;
                qry1[i]={3,l,x-1,x};
                qry2[i]={3,x+1,r,x};
            }
            else if(x<l){
                qry1[i]={3,-1,-1,x};
                qry2[i]={3,l,r,x};
            }
            else{
                qry1[i]={3,l,r,x};
                qry2[i]={3,n+2,n+2,x};
            }
        }
    }
    for(auto& [op,l,r,x]:qry2){
        l=n-l+1,r=n-r+1;swap(l,r);
        if(op==3)   x=n-x+1;
    }
    ope(a,qry1);
    reverse(a.begin()+1,a.end());
    ope(a,qry2);
    for(int i=1;i<=m;i++){
        if(ak[i].op==3) cout<<ans[i]<<'\n';
    }   
}
signed main() {
    ios::sync_with_stdio(false), cin.tie(nullptr);

    int _ = 1;
    cin >> _;
    while (_--) solve();

    return 0;
}
/*
1
10 2
1 3 2 5 2 3 1 6 4 5
1 1 5 2
3 1 10 8
*/
/*
1
10 10
1 3 2 5 2 3 1 6 4 5
3 5 7 8
3 5 7 4
1 1 5 2
3 1 10 4
3 1 10 8
2 8 8 8
3 1 10 8
3 1 10 4
2 4 8 1
3 1 2 10
*/