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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#658482#7735. Primitive RootAlucardWA 5ms3588kbC++141.8kb2024-10-19 16:53:282024-10-19 16:53:30

Judging History

你现在查看的是最新测评结果

  • [2024-10-19 16:53:30]
  • 评测
  • 测评结果:WA
  • 用时:5ms
  • 内存:3588kb
  • [2024-10-19 16:53:28]
  • 提交

answer

#include<bits/stdc++.h>
#define rep(i, n) for(int i = 0; i < (n); ++i)
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef vector<int> vi;
typedef pair<int, int> pii;
typedef pair<ll, int> pli;
typedef array<int, 3> ai3;
const ll inf = 0x3f3f3f3f3f3f3f3fll;
const int Mod = 998244353;
const int inv[5] = {0, 1, (Mod+1) / 2, (Mod+1) / 3};
inline int sign(int a){ return (a&1) ? (Mod-1) : 1; }
inline void uadd(int &a, int b){ a += b-Mod; a += (a>>31) & Mod; }
inline void usub(int &a, int b){ a -= b, a += (a>>31) & Mod; }
inline void umul(int &a, int b){ a = (int)(1ll * a * b % Mod); }
inline int add(int a, int b){ a += b-Mod; a += (a>>31) & Mod; return a; }
inline int sub(int a, int b){ a -= b, a += (a>>31) & Mod; return a; }
inline int mul(int a, int b){ a = (int)(1ll * a * b % Mod); return a; }
int qpow(int b, int p){ int ret = 1; while(p){ if(p&1) umul(ret, b); umul(b, b), p >>= 1; } return ret; }
const int fN = 111;
int fact[fN], invfact[fN], pw2[fN], invpw2[fN];
void initfact(int n){
	pw2[0] = 1; for(int i = 1; i <= n; ++i) pw2[i] = mul(pw2[i-1], 2);
	invpw2[0] = 1; for(int i = 1; i <= n; ++i) invpw2[i] = mul(invpw2[i-1], (Mod+1) / 2);
	fact[0] = 1; for(int i = 1; i <= n; ++i) fact[i] = mul(fact[i-1], i);
	invfact[n] = qpow(fact[n], Mod-2); for(int i = n; i > 0; --i) invfact[i-1] = mul(invfact[i], i);
}
int binom(int n, int m){ return (m < 0 || m > n) ? 0 : mul(fact[n], mul(invfact[m], invfact[n-m])); }
const double pi = acos(-1);
inline void chmax(int &a, int b){ (b>a) ? (a=b) : 0; }
inline void chmin(int &a, int b){ (b<a) ? (a=b) : 0; }

int main(){
	ios::sync_with_stdio(false);
	cin.tie(0);

	int T;
	cin >> T;
	while(T--){
		ll P, m;
		cin >> P >> m;
		ll k = (m / P);
ll ret=k+(m%P!=0);
if(m==0)ret+=(((P-1)^m)%P==1);
		cout << ret << "\n";
	}

	return 0;
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 0ms
memory: 3504kb

input:

3
2 0
7 11
1145141 998244353

output:

1
2
872

result:

ok 3 lines

Test #2:

score: -100
Wrong Answer
time: 5ms
memory: 3588kb

input:

47595
2 0
2 1
2 2
2 3
2 4
2 5
2 6
2 7
2 8
2 9
2 10
2 11
2 12
2 13
2 14
2 15
2 16
2 17
2 18
2 19
2 20
2 21
2 22
2 23
2 24
2 25
2 26
2 27
2 28
2 29
2 30
2 31
2 32
2 33
2 34
2 35
2 36
2 37
2 38
2 39
2 40
2 41
2 42
2 43
2 44
2 45
2 46
2 47
2 48
2 49
2 50
2 51
2 52
2 53
2 54
2 55
2 56
2 57
2 58
2 59
2 60...

output:

1
1
1
2
2
3
3
4
4
5
5
6
6
7
7
8
8
9
9
10
10
11
11
12
12
13
13
14
14
15
15
16
16
17
17
18
18
19
19
20
20
21
21
22
22
23
23
24
24
25
25
26
26
27
27
28
28
29
29
30
30
31
31
32
32
33
33
34
34
35
35
36
36
37
37
38
38
39
39
40
40
41
41
42
42
43
43
44
44
45
45
46
46
47
47
48
48
49
49
50
50
51
51
52
52
53
5...

result:

wrong answer 3rd lines differ - expected: '2', found: '1'