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QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#65735#4878. Easy Problemjapan022022#WA 4ms3404kbC++206.7kb2022-12-03 14:39:392022-12-03 14:39:40

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2022-12-03 14:39:40]
  • 评测
  • 测评结果:WA
  • 用时:4ms
  • 内存:3404kb
  • [2022-12-03 14:39:39]
  • 提交

answer

#include<iostream>
#include<vector>

#include <algorithm>
#include <cassert>
#include <iostream>
#include <vector>


#ifdef _MSC_VER
#include <intrin.h>
#endif

namespace atcoder {

namespace internal {

int ceil_pow2(int n) {
    int x = 0;
    while ((1U << x) < (unsigned int)(n)) x++;
    return x;
}

constexpr int bsf_constexpr(unsigned int n) {
    int x = 0;
    while (!(n & (1 << x))) x++;
    return x;
}

int bsf(unsigned int n) {
#ifdef _MSC_VER
    unsigned long index;
    _BitScanForward(&index, n);
    return index;
#else
    return __builtin_ctz(n);
#endif
}

}  // namespace internal

}  // namespace atcoder


namespace atcoder {

template <class S,
          S (*op)(S, S),
          S (*e)(),
          class F,
          S (*mapping)(F, S),
          F (*composition)(F, F),
          F (*id)()>
struct lazy_segtree {
  public:
    lazy_segtree() : lazy_segtree(0) {}
    explicit lazy_segtree(int n) : lazy_segtree(std::vector<S>(n, e())) {}
    explicit lazy_segtree(const std::vector<S>& v) : _n(int(v.size())) {
        log = internal::ceil_pow2(_n);
        size = 1 << log;
        d = std::vector<S>(2 * size, e());
        lz = std::vector<F>(size, id());
        for (int i = 0; i < _n; i++) d[size + i] = v[i];
        for (int i = size - 1; i >= 1; i--) {
            update(i);
        }
    }

    void set(int p, S x) {
        assert(0 <= p && p < _n);
        p += size;
        for (int i = log; i >= 1; i--) push(p >> i);
        d[p] = x;
        for (int i = 1; i <= log; i++) update(p >> i);
    }

    S get(int p) {
        assert(0 <= p && p < _n);
        p += size;
        for (int i = log; i >= 1; i--) push(p >> i);
        return d[p];
    }

    S prod(int l, int r) {
        assert(0 <= l && l <= r && r <= _n);
        if (l == r) return e();

        l += size;
        r += size;

        for (int i = log; i >= 1; i--) {
            if (((l >> i) << i) != l) push(l >> i);
            if (((r >> i) << i) != r) push((r - 1) >> i);
        }

        S sml = e(), smr = e();
        while (l < r) {
            if (l & 1) sml = op(sml, d[l++]);
            if (r & 1) smr = op(d[--r], smr);
            l >>= 1;
            r >>= 1;
        }

        return op(sml, smr);
    }

    S all_prod() { return d[1]; }

    void apply(int p, F f) {
        assert(0 <= p && p < _n);
        p += size;
        for (int i = log; i >= 1; i--) push(p >> i);
        d[p] = mapping(f, d[p]);
        for (int i = 1; i <= log; i++) update(p >> i);
    }
    void apply(int l, int r, F f) {
        assert(0 <= l && l <= r && r <= _n);
        if (l == r) return;

        l += size;
        r += size;

        for (int i = log; i >= 1; i--) {
            if (((l >> i) << i) != l) push(l >> i);
            if (((r >> i) << i) != r) push((r - 1) >> i);
        }

        {
            int l2 = l, r2 = r;
            while (l < r) {
                if (l & 1) all_apply(l++, f);
                if (r & 1) all_apply(--r, f);
                l >>= 1;
                r >>= 1;
            }
            l = l2;
            r = r2;
        }

        for (int i = 1; i <= log; i++) {
            if (((l >> i) << i) != l) update(l >> i);
            if (((r >> i) << i) != r) update((r - 1) >> i);
        }
    }

    template <bool (*g)(S)> int max_right(int l) {
        return max_right(l, [](S x) { return g(x); });
    }
    template <class G> int max_right(int l, G g) {
        assert(0 <= l && l <= _n);
        assert(g(e()));
        if (l == _n) return _n;
        l += size;
        for (int i = log; i >= 1; i--) push(l >> i);
        S sm = e();
        do {
            while (l % 2 == 0) l >>= 1;
            if (!g(op(sm, d[l]))) {
                while (l < size) {
                    push(l);
                    l = (2 * l);
                    if (g(op(sm, d[l]))) {
                        sm = op(sm, d[l]);
                        l++;
                    }
                }
                return l - size;
            }
            sm = op(sm, d[l]);
            l++;
        } while ((l & -l) != l);
        return _n;
    }

    template <bool (*g)(S)> int min_left(int r) {
        return min_left(r, [](S x) { return g(x); });
    }
    template <class G> int min_left(int r, G g) {
        assert(0 <= r && r <= _n);
        assert(g(e()));
        if (r == 0) return 0;
        r += size;
        for (int i = log; i >= 1; i--) push((r - 1) >> i);
        S sm = e();
        do {
            r--;
            while (r > 1 && (r % 2)) r >>= 1;
            if (!g(op(d[r], sm))) {
                while (r < size) {
                    push(r);
                    r = (2 * r + 1);
                    if (g(op(d[r], sm))) {
                        sm = op(d[r], sm);
                        r--;
                    }
                }
                return r + 1 - size;
            }
            sm = op(d[r], sm);
        } while ((r & -r) != r);
        return 0;
    }

  private:
    int _n, size, log;
    std::vector<S> d;
    std::vector<F> lz;

    void update(int k) { d[k] = op(d[2 * k], d[2 * k + 1]); }
    void all_apply(int k, F f) {
        d[k] = mapping(f, d[k]);
        if (k < size) lz[k] = composition(f, lz[k]);
    }
    void push(int k) {
        all_apply(2 * k, lz[k]);
        all_apply(2 * k + 1, lz[k]);
        lz[k] = id();
    }
};

}  // namespace atcoder

using namespace std;
struct dat{
	long long val;
	int len;
};
dat op(dat a,dat b){return dat{a.val+b.val,a.len+b.len};}
dat e(){return dat{0LL,0};}
dat mp(long long f,dat x){return dat{x.val+f*x.len,x.len};}
long long cmp(long long f,long long g){return f+g;}
long long id(){return 0LL;}
int N,M;
long long ans[1<<17];
int main()
{
	ios::sync_with_stdio(false);
	cin.tie(nullptr);
	int T;cin>>T;
	for(;T--;)
	{
		cin>>N>>M;
		vector<pair<int,pair<int,int> > >AC;
		AC.reserve(N+M);
		vector<dat>init(N,dat{0LL,1});
		atcoder::lazy_segtree<dat,op,e,long long,mp,cmp,id>segsum(init),segcnt(init);
		for(int i=0;i<N;i++)
		{
			int a;cin>>a;
			AC.push_back(make_pair(a,make_pair(i,-1)));
		}
		for(int i=0;i<M;i++)
		{
			int l,r,c;cin>>l>>r>>c;
			l--;
			AC.push_back(make_pair(c,make_pair(l,r)));
			segcnt.apply(l,r,1LL);
		}
		sort(AC.begin(),AC.end());
		for(int i=0;i<AC.size();i++)
		{
			if(AC[i].second.second==-1)
			{
				int idx=AC[i].second.first;
				ans[idx]=segsum.get(idx).val+segcnt.get(idx).val*AC[i].first;
			}
			else
			{
				int l=AC[i].second.first,r=AC[i].second.second;
				segcnt.apply(l,r,-1LL);
				segsum.apply(l,r,(long long)AC[i].first);
			}
		}
		for(int i=0;i<N;i++)cout<<ans[i]<<(i+1==N?"\n":" ");
	}
}

Details

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Test #1:

score: 100
Accepted
time: 4ms
memory: 3396kb

input:

1
4 3
3 3 2 2
1 2 2
3 3 3
2 2 4

output:

2 5 2 0

result:

ok 4 number(s): "2 5 2 0"

Test #2:

score: -100
Wrong Answer
time: 2ms
memory: 3404kb

input:

200
10 10
441129649 175970039 478629746 150210377 473385687 400931249 155714650 270352812 293555449 444876725
1 1 114317839
1 1 158354349
1 4 13054554
1 3 562005243
1 3 114310710
1 1 481426141
1 2 150800722
1 1 224503966
2 3 106234607
1 2 6235654
10 10
216212720 595995796 317909277 459839404 7779474...

output:

1663837092 566606286 712229617 13054554 0 0 0 0 0 0
695919054 444907672 198220395 146074643 87715048 22244507 0 0 0 0
566992511 432089962 2319403141 1087055465 1093348069 653652153 0 0 0 0
1253986048 1301823452 522595402 847575469 8162439 319103714 244998554 151716100 47402821 0
364262503 714861568 ...

result:

wrong answer 1st numbers differ - expected: '1108783988', found: '1663837092'