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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#656965#8022. Walkeryumingsk#WA 1ms3920kbC++201.9kb2024-10-19 13:57:002024-10-19 13:57:01

Judging History

你现在查看的是最新测评结果

  • [2024-10-19 13:57:01]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:3920kb
  • [2024-10-19 13:57:00]
  • 提交

answer

#pragma GCC optimize(3, "Ofast", "inline")
#include <iostream>
#include <bits/stdc++.h>
#define IOS ios::sync_with_stdio(false), cin.tie(0), cout.tie(0)
#define INF 0x3f3f3f3f
#define L_INF 0x7f3f3f3f3f3f3f3f
#define db cout << "debug\n";

using namespace std;
const int Mod = 998244353;
using ll = long long;

double abs2(double a) { return a < 0 ? -a : a; }
double max(double a, double b) { return a > b ? a : b; }
double min(double a, double b) { return a < b ? a : b; }
double n, p1, p2, v1, v2, t, minn, p;

void solve()
{
    cin >> n >> p1 >> v1 >> p2 >> v2;
    if (p2 < p1)
    {
        t = p1;
        p1 = p2;
        p2 = t;
        t = v1;
        v1 = v2;
        v2 = t;
    }
    minn = min((n / 2 - abs2(n / 2 - p1) + n) / v1, (n / 2 - abs2(n / 2 - p2) + n) / v2);
    minn = min(minn, (n * 2 - p2 + p1) / (v1 + v2));
    t = (n + p2 - p1) / (v1 + v2);
    if (t - p1 / v1 >= 0 && t - ((n - p2) / v2) >= 0)
        minn = min(minn, t);
    minn = min(minn, max(p1 / v1, (2 * n - p1 - p2) / v2));
    minn = min(minn, max((n - p2) / v1, (p1 + p2) / v2));
    p = ((2 * n - p2) / v2 + p1 / v1) / (2 / v1 + 1 / v2);
    if (p1 <= p && p <= p2)
        minn = min(minn, (p * 2 - p1) / v1);
    p = ((p2 + n) / v2 + p1 / v1) / (1 / v1 + 2 / v2);
    if (p1 <= p && p <= p2)
        minn = min(minn, (p + p1) / v1);
    cout << fixed << setprecision(10) << minn << '\n';
}
int main()
{
    IOS;
// freopen("in.txt", "r", stdin);
// freopen("out.txt", "w", stdout);
#ifndef ONLINE_JUDGE
    clock_t start_time = clock();
#endif
    int t = 1;
    cin >> t;
    while (t--)
    {
        solve();
    }
#ifndef ONLINE_JUDGE
    cout << "Used " << (double)(clock() - start_time) << " ms" << endl;
#endif
    return 0;
}
// (p*2-p1)/v1==(2*n-p-p2)/v2
// p*(2/v1+1/v2)==(2*n-p2)/v2+p1/v1
// (p+p1)/v1==(p2+n-2*p)/v2
// p*(1/v1+2/v2)==(p2+n)/v2+p1/v1

詳細信息

Test #1:

score: 100
Accepted
time: 0ms
memory: 3916kb

input:

2
10000.0 1.0 0.001 9999.0 0.001
4306.063 4079.874 0.607 1033.423 0.847

output:

5001000.0000000000
3827.8370013755

result:

ok 2 numbers

Test #2:

score: 0
Accepted
time: 0ms
memory: 3904kb

input:

1
10.0 1.0 10.0 9.0 0.1

output:

1.1000000000

result:

ok found '1.1000000', expected '1.1000000', error '0.0000000'

Test #3:

score: 0
Accepted
time: 0ms
memory: 3728kb

input:

1
10.0 8.0 10.0 9.0 0.1

output:

1.2000000000

result:

ok found '1.2000000', expected '1.2000000', error '0.0000000'

Test #4:

score: 0
Accepted
time: 0ms
memory: 3852kb

input:

1
10.0 8.0 0.1 9.0 10

output:

1.1000000000

result:

ok found '1.1000000', expected '1.1000000', error '0.0000000'

Test #5:

score: 0
Accepted
time: 0ms
memory: 3868kb

input:

1
10.0 2.0 0.1 3.0 10

output:

1.3000000000

result:

ok found '1.3000000', expected '1.3000000', error '0.0000000'

Test #6:

score: 0
Accepted
time: 0ms
memory: 3920kb

input:

1
10.0 9.0 0.1 8.0 10.0

output:

1.2000000000

result:

ok found '1.2000000', expected '1.2000000', error '0.0000000'

Test #7:

score: 0
Accepted
time: 0ms
memory: 3912kb

input:

1
10.0 4.0 0.1 6.0 0.1

output:

60.0000000000

result:

ok found '60.0000000', expected '60.0000000', error '0.0000000'

Test #8:

score: 0
Accepted
time: 0ms
memory: 3920kb

input:

1
10.0 4.5 0.1 6.0 0.1

output:

57.5000000000

result:

ok found '57.5000000', expected '57.5000000', error '0.0000000'

Test #9:

score: 0
Accepted
time: 0ms
memory: 3852kb

input:

1
10.0 1.0 1.0 8.0 1.0

output:

6.5000000000

result:

ok found '6.5000000', expected '6.5000000', error '0.0000000'

Test #10:

score: -100
Wrong Answer
time: 1ms
memory: 3908kb

input:

1
10.0 3.0 2.0 7.0 1.0

output:

4.6666666667

result:

wrong answer 1st numbers differ - expected: '4.6000000', found: '4.6666667', error = '0.0144928'