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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#64969#4231. Rafting Triptriplem5ds#TL 39ms35628kbC++234.9kb2022-11-26 02:30:152022-11-26 02:30:16

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2022-11-26 02:30:16]
  • 评测
  • 测评结果:TL
  • 用时:39ms
  • 内存:35628kb
  • [2022-11-26 02:30:15]
  • 提交

answer

/// Brrrr Brrrr
#pragma GCC optimize("O3")
#pragma GCC optimize ("unroll-loops")
#pragma GCC target("avx,avx2,fma")

#include "bits/stdc++.h"
using namespace std;

#define pb push_back
#define F first
#define S second
#define f(i, a, b)  for(int i = a; i < b; i++)
#define all(a)  a.begin(),a.end()
#define rall(a) a.rbegin(),a.rend()
#define sz(x) (int)(x).size()
#define mp(x,y) make_pair(x,y)
#define popCnt(x) (__builtin_popcountll(x))
#define int ll

using ll = long long;
using ii = pair<int, int>;
using ull = unsigned long long;

const int N = 1e5+5, LG = 18, MOD = (119 << 23) + 1;
const long double PI = acos(-1);
const long double EPS = 1e-7;

const int dx[] = {0,0,1,-1};
const int dy[] = {1,-1,0,0};

int n, m;
char grid[555][555];
bool inCycle[555][555];
bool vis[555][555];
bool isRiver(int i, int j) {
    return grid[i][j] == '>' || grid[i][j] == '<' || grid[i][j] == 'v' || grid[i][j] == '^';
}
vector<vector<ii>> cycles;
int cnt[555][555], cur;
vector<ii> adj[555][555];
bool inStack[555][555];
void dfs(int x, int y) {

    inStack[x][y]=true;
    vis[x][y] = true;
    bool can=true;

    if(grid[x][y] == '>' && isRiver(x,y+1)) {
        if(!vis[x][y+1])
            dfs(x,y+1),can=false;
        adj[x][y+1].pb({x,y});
    }
    if(grid[x][y] == '<' && isRiver(x,y-1)) {
        if(!vis[x][y-1])
            dfs(x,y-1),can=false;
        adj[x][y-1].pb({x,y});
    }
    if(grid[x][y] == '^' && isRiver(x-1,y)) {
        if(!vis[x-1][y])
        dfs(x-1,y), can=false;
        adj[x-1][y].pb({x,y});
    }
    if(grid[x][y] == 'v' && isRiver(x+1,y)) {
        if(!vis[x+1][y])
            dfs(x+1,y),can=false;
        adj[x+1][y].pb({x,y});
    }


    if(can) {
        bool canGo=true;
        if(grid[x][y] == '>' && !isRiver(x,y+1)) {
            canGo=false;
        }
        if(grid[x][y] == '<' && !isRiver(x,y-1)) {
            canGo=false;
        }
        if(grid[x][y] == '^' && !isRiver(x-1,y)) {
            canGo=false;
        }
        if(grid[x][y] == 'v' && !isRiver(x+1,y)) {
            canGo=false;
        }
        cycles.push_back(vector<ii>());
        if(canGo) {
            bool canStack;
            if(grid[x][y] == '>') {
                canStack=inStack[x][y+1];
            }
            if(grid[x][y] == '<') {
                canStack=inStack[x][y-1];
            }
            if(grid[x][y] == '^') {
                canStack=inStack[x-1][y];
            }
            if(grid[x][y] == 'v') {
                canStack=inStack[x+1][y];
            }
            if(!canStack) {
                cycles.pop_back();
            }   else {
                int curX=x,curY=y;
                do{
                    cycles.back().pb({curX,curY});
                    bool ok = true;
                    if(grid[curX][curY] == '>' && isRiver(curX,curY+1))
                        curY += 1, ok = false;
                    else if(grid[curX][curY] == '<' && isRiver(curX,curY-1))
                        curY -= 1, ok = false;
                    else if(grid[curX][curY] == '^' && isRiver(curX-1,curY))
                        curX -= 1, ok = false;
                    else if(grid[curX][curY] == 'v' && isRiver(curX+1,curY))
                        curX += 1, ok = false;
                }while(curX!=x||curY!=y);
            }
        }   else {
            cycles.back().push_back({x,y});
        }
        for(auto p : cycles.back())
            inCycle[p.F][p.S]=true;
    }

    inStack[x][y]=false;
}

void addC(int i, int j, int v) {
    if(grid[i][j] != '#') return;
    cur -= cnt[i][j] > 0;
    cnt[i][j] += v;
    cur += cnt[i][j] > 0;
}
void add(int i, int j, int v) {
    f(k,0,4) {
        int nx = i + dx[k];
        int ny = j + dy[k];
        addC(nx,ny,v);
    }
}
int dfsTree(int i, int j) {
    if(vis[i][j])return 0;
    vis[i][j]=true;
    int ans = 0;
    for(auto v : adj[i][j]) if(!inCycle[v.F][v.S]){
        add(v.F, v.S, +1);
        ans = max(ans, dfsTree(v.F, v.S));
        add(v.F, v.S, -1);
    }

    return max(ans, cur);
}
void doWork() {

    cin >> n >> m;

    for(int i = 1; i <= n; i++) {
        for(int j = 1; j <= m; j++) {
            cin >> grid[i][j];
        }
    }

    for(int i = 1; i <= n; i++)
    for(int j = 1; j <= m; j++)
    if(isRiver(i,j) && !vis[i][j]) {
        dfs(i,j);
    }


    int ans = 0;
    memset(vis,0,sizeof vis);
    for(auto c : cycles) {
        for(auto p : c) {
            inCycle[p.F][p.S]=true;
            add(p.F,p.S,+1);
        }
        for(auto p : c)ans = max(ans, dfsTree(p.F,p.S));
        for(auto p : c)
            add(p.F,p   .S,-1);
    }
    cout << ans << '\n';
}
int32_t main() {
#ifdef ONLINE_JUDGE
    ios_base::sync_with_stdio(0);
    cin.tie(0);
#endif // ONLINE_JUDGE

    int t = 1;
//    cin >> t;
    while (t--) {
        doWork();
    }
    return 0;
}

///Look at my code ya codeomk


Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 6ms
memory: 11132kb

input:

5 6
v<<<#v
v#v<.>
>>v<<<
..v##^
#<<<.^

output:

4

result:

ok single line: '4'

Test #2:

score: 0
Accepted
time: 2ms
memory: 13292kb

input:

4 5
>v<<.
^<..#
#...#
.#>^#

output:

2

result:

ok single line: '2'

Test #3:

score: 0
Accepted
time: 1ms
memory: 13528kb

input:

4 6
>>v#>v
^#>>^v
^<<#v<
.#^<<#

output:

5

result:

ok single line: '5'

Test #4:

score: 0
Accepted
time: 6ms
memory: 13628kb

input:

6 6
^.>>>>
^.....
^....v
^....v
#....v
<<<<#v

output:

2

result:

ok single line: '2'

Test #5:

score: 0
Accepted
time: 2ms
memory: 12616kb

input:

6 7
^>>>>>v
^.....v
^.#^..v
^.#^<.v
^.....v
^<<<<<<

output:

2

result:

ok single line: '2'

Test #6:

score: 0
Accepted
time: 6ms
memory: 10984kb

input:

3 7
>v<<<<#
^<#####
#^<<<<<

output:

6

result:

ok single line: '6'

Test #7:

score: 0
Accepted
time: 5ms
memory: 13360kb

input:

3 5
><.v#
##.^#
...#.

output:

3

result:

ok single line: '3'

Test #8:

score: 0
Accepted
time: 2ms
memory: 13528kb

input:

7 3
###
#>#
###
...
###
#>.
###

output:

4

result:

ok single line: '4'

Test #9:

score: 0
Accepted
time: 2ms
memory: 13620kb

input:

2 2
>.
.#

output:

0

result:

ok single line: '0'

Test #10:

score: 0
Accepted
time: 2ms
memory: 13348kb

input:

2 2
..
.v

output:

0

result:

ok single line: '0'

Test #11:

score: 0
Accepted
time: 17ms
memory: 26612kb

input:

498 498
<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<...

output:

41195

result:

ok single line: '41195'

Test #12:

score: 0
Accepted
time: 39ms
memory: 35628kb

input:

500 500
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>...

output:

24926

result:

ok single line: '24926'

Test #13:

score: -100
Time Limit Exceeded

input:

500 500
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>...

output:


result: