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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#649542#7895. Graph Partitioning 2tumu1tTL 903ms9504kbC++235.5kb2024-10-18 01:34:082024-10-18 01:34:09

Judging History

你现在查看的是最新测评结果

  • [2024-10-18 01:34:09]
  • 评测
  • 测评结果:TL
  • 用时:903ms
  • 内存:9504kb
  • [2024-10-18 01:34:08]
  • 提交

answer

#include <bits/stdc++.h>
typedef long long LL;
using std::cin, std::cout, std::endl, std::vector, std::pair;

template <typename T>
constexpr T power(T a, long long b)
{
    T res = 1;
    for (; b; b >>= 1, a *= a)
        if (b & 1)
            res *= a;
    return res;
}
template <int P>
class Mint
{
public:
    int x;
    static int MOD;
    constexpr Mint() : x() {}
    constexpr Mint(long long _x) : x{norm(_x % getMOD())} {}

    constexpr static void setMOD(int _MOD) { MOD = _MOD; }
    constexpr static int getMOD() { return P > 0 ? P : MOD; }
    constexpr int norm(int x) const { return x >= 0 && x < getMOD() ? x : (x < 0 ? x += getMOD() : x -= getMOD()); }
    constexpr int val() const { return x; }
    explicit constexpr operator int() const { return x; }
    constexpr Mint operator-() const
    {
        Mint res;
        res.x = norm(getMOD() - x);
        return res;
    }
    constexpr Mint inv() const
    {
        assert(x != 0);
        return power(*this, getMOD() - 2);
    }
    constexpr Mint &operator*=(Mint rhs) &
    {
        x = 1LL * x * rhs.x % getMOD();
        return *this;
    }
    constexpr Mint &operator+=(Mint rhs) &
    {
        x = norm(x + rhs.x);
        return *this;
    }
    constexpr Mint &operator-=(Mint rhs) &
    {
        x = norm(x - rhs.x);
        return *this;
    }
    constexpr Mint &operator/=(Mint rhs) & { return *this *= rhs.inv(); }
    friend constexpr Mint operator*(Mint lhs, Mint rhs)
    {
        Mint res = lhs;
        res *= rhs;
        return res;
    }
    friend constexpr Mint operator+(Mint lhs, Mint rhs)
    {
        Mint res = lhs;
        res += rhs;
        return res;
    }
    friend constexpr Mint operator-(Mint lhs, Mint rhs)
    {
        Mint res = lhs;
        res -= rhs;
        return res;
    }
    friend constexpr Mint operator/(Mint lhs, Mint rhs)
    {
        Mint res = lhs;
        res /= rhs;
        return res;
    }
    friend constexpr std::istream &operator>>(std::istream &is, Mint &a)
    {
        long long v;
        is >> v;
        a = Mint(v);
        return is;
    }
    friend constexpr std::ostream &operator<<(std::ostream &os, const Mint &a) { return os << a.val(); }
    friend constexpr bool operator==(Mint lhs, Mint rhs) { return lhs.val() == rhs.val(); }
    friend constexpr bool operator!=(Mint lhs, Mint rhs) { return lhs.val() != rhs.val(); }
};

template <>
int Mint<0>::MOD = 998'244'353;

template <int V, int P>
constexpr Mint<P> Cinv = Mint<P>(V).inv();

constexpr int P = 998'244'353; // 可以修改这里的P 如果需要将变量设为P,需要将P变为0
using Z = Mint<P>;

// 998'244'353

void Solve1(int n, int k)
{
    vector<vector<int>> G(n);
    for (int i = 1; i <= n - 1; i++)
    {
        int x, y;
        cin >> x >> y;
        x -= 1;
        y -= 1;
        G[x].push_back(y);
        G[y].push_back(x);
    }

    auto Dfs = [&](auto self, int at, int from) -> pair<int, vector<Z>>
    {
        vector<Z> Ans(k + 2);
        Ans[1] = 1;
        int subTree = 1;
        for (auto &v : G[at])
        {
            if (v == from)
                continue;
            else
            {
                const auto &[sz, SonAns] = self(self, v, at);
                subTree += sz;
                vector<Z> newAns(k + 2);
                for (int i = 0; i <= k + 1; i++)
                {
                    for (int j = 0; j <= std::min<int>(sz, k + 1) && i + j <= k + 1; j++)
                    {
                        newAns[i + j] += SonAns[j] * Ans[i];
                    }
                }
                Ans = std::move(newAns);
            }
        }
        Ans[0] += Ans[k] + Ans[k + 1];
        return {subTree, Ans};
    };

    cout << Dfs(Dfs, 0, -1).second[0] << endl;
}

void Solve2(int n, int k)
{
    vector<vector<int>> G(n);
    for (int i = 1; i <= n - 1; i++)
    {
        int x, y;
        cin >> x >> y;
        x -= 1;
        y -= 1;
        G[x].push_back(y);
        G[y].push_back(x);
    }

    auto Dfs = [&](auto self, int at, int from) -> pair<int, std::map<int, Z>>
    {
        std::map<int, Z> Ans;
        Ans[1] = 1;
        int subTree = 1;
        for (auto &v : G[at])
        {
            if (v == from)
                continue;
            else
            {
                const auto &[sz, SonAns] = self(self, v, at);
                subTree += sz;
                std::map<int, Z> newAns;
                for (auto &[i, d1] : Ans)
                {
                    for (auto &[j, d2] : SonAns)
                    {
                        if (i + j > k + 1)
                            break;
                        newAns[i + j] += d1 * d2;
                    }
                }
                Ans = std::move(newAns);
            }
        }
        if (auto it = Ans.find(k); it != Ans.end())
            Ans[0] += Ans[k];
        if (auto it = Ans.find(k + 1); it != Ans.end())
            Ans[0] += Ans[k + 1];
        return {subTree, Ans};
    };

    cout << Dfs(Dfs, 0, -1).second[0] << endl;
}

void Solve()
{
    int n, k;
    cin >> n >> k;
    if (k * k < n)
        Solve1(n, k);
    else
        Solve2(n, k);
    return;
}

int main()
{
    std::ios::sync_with_stdio(false);
    cin.tie(nullptr);
    cout.tie(nullptr);

    int testcases = 1;
    cin >> testcases;
    for (int i = 1; i <= testcases; i++)
        Solve();
}

詳細信息

Test #1:

score: 100
Accepted
time: 1ms
memory: 3620kb

input:

2
8 2
1 2
3 1
4 6
3 5
2 4
8 5
5 7
4 3
1 2
1 3
2 4

output:

2
1

result:

ok 2 lines

Test #2:

score: 0
Accepted
time: 44ms
memory: 4004kb

input:

5550
13 4
10 3
9 1
10 8
3 11
8 5
10 7
9 6
13 5
9 7
2 7
5 12
4 8
8 2
4 1
3 4
7 8
2 5
6 7
4 8
2 3
11 1
11 10
1 4
9 10
8 4
3 6
5 7
6 1
10 2
11 7
11 1
17 2
14 16
13 15
17 3
15 11
1 6
13 2
13 17
4 8
14 10
8 14
14 5
9 12
14 2
12 17
17 6
15 7
14 6
2 14
2 13
2 4
8 4
3 11
7 3
14 1
11 9
13 3
5 10
6 8
3 10
14 ...

output:

0
3
112
0
1
0
1
0
0
0
1
0
1
0
0
1
0
140
0
0
0
814
1
6
1
1
2
2
0
612
0
1
0
0
0
1
1
0
0
121
4536
0
0
1718
0
0
1
0
444
1
1908
1813
3
74
0
1
0
46
0
0
0
0
0
0
0
0
0
1
0
1
1
1
239
0
0
0
1
0
0
0
1
0
1
0
0
1
1
0
0
0
1
0
0
0
48
0
2
0
0
0
1
364
0
206
0
0
76
0
1
0
0
2
0
1
2
0
0
1
0
0
4
0
1
1
0
0
1
1
1
0
0
1
1
...

result:

ok 5550 lines

Test #3:

score: 0
Accepted
time: 903ms
memory: 9504kb

input:

3
99990 259
23374 69108
82204 51691
8142 67119
48537 97966
51333 44408
33147 68485
21698 86824
15746 58746
78761 86975
58449 61819
69001 68714
25787 2257
25378 14067
64899 68906
29853 31359
75920 85420
76072 11728
63836 55505
43671 98920
77281 25176
40936 66517
61029 61440
66908 52300
92101 59742
69...

output:

259200
247
207766300

result:

ok 3 lines

Test #4:

score: 0
Accepted
time: 146ms
memory: 9200kb

input:

3
99822 332
11587 83046
63424 60675
63423 73718
74622 40130
5110 26562
28361 80899
30886 70318
8708 11068
34855 96504
7904 75735
31904 42745
87892 55105
82374 81319
77407 82147
91475 12343
13470 95329
58766 95716
83232 44156
75907 92437
69785 93598
47857 33018
62668 31394
24238 72675
98254 43583
180...

output:

315881300
4505040
185631154

result:

ok 3 lines

Test #5:

score: 0
Accepted
time: 142ms
memory: 9176kb

input:

3
99021 1000
41739 4318
72541 76341
31227 15416
49232 13808
50837 51259
74464 11157
92684 84646
95226 64673
74155 82511
33301 31373
5901 29318
38227 98893
96752 57411
35167 42401
24344 90803
6956 33753
51120 24535
29594 2646
70305 32961
93079 38070
49273 48987
62799 77986
94353 84447
74970 31546
263...

output:

917568
1
1213

result:

ok 3 lines

Test #6:

score: -100
Time Limit Exceeded

input:

3
100000 10000
15556 26349
14984 68012
43040 63434
32168 60646
70509 38559
26238 29031
45952 19431
29510 54395
5676 59515
28220 41438
46902 56640
8221 80059
77225 66558
17473 87324
20819 35098
29515 12641
84108 41157
11223 66562
25999 95852
3790 63605
20963 15799
217 58841
61619 13324
3406 60525
693...

output:

1
1

result: