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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#649249 | #7894. Many Many Heads | Lynia | WA | 3ms | 3624kb | C++23 | 3.0kb | 2024-10-17 22:17:26 | 2024-10-17 22:17:28 |
Judging History
answer
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// ////////////////////
// // //
//
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//
//
// // // //////// /\ /////////
// // // // // // //
// //////// // // // // //
// // // // // // //
////////// //////// // // // /////////////
#pragma GCC optimize(2)
#include <iostream>
#include <iomanip>
#include <algorithm>
#include <map>
#include <set>
#include <queue>
#include <string>
#include <cstring>
#include <cmath>
#include <list>
#include <stack>
#include <array>
#include <unordered_map>
#include <unordered_set>
#include <bitset>
#include <random>
#include <numeric>
#include <functional>
//#include <Windows.h>
using namespace std;
#define fa(i,op,n) for (int i = op; i <= n; i++)
#define fb(j,op,n) for (int j = op; j >= n; j--)
#define pb push_back
#define HashMap unordered_map
#define HashSet unordered_set
#define var auto
#define all(i) i.begin(), i.end()
#define endl '\n'
#define px first
#define py second
#define DEBUG(a) cout<<a<<endl
using VI = vector<int>;
using VL = vector<long long>;
using ll = long long;
using ull = unsigned long long;
using db = double;
using pii = pair<int, int>;
using pll = pair<ll, ll>;
template<class T1, class T2>
ostream& operator<<(ostream& out, const pair<T1, T2>& p) {
out << '(' << p.first << ", " << p.second << ')';
return out;
}
template<typename T>
ostream& operator<<(ostream& out, const vector<T>& ve) {
for (T i : ve)
out << i << ' ';
return out;
}
template<class T1, class T2>
ostream& operator<<(ostream& out, const map<T1, T2>& mp) {
for (auto i : mp)
out << i << '\n';
return out;
}
const int INF = 0x3f3f3f3f;
const ll LNF = 0x3f3f3f3f3f3f3f3f;
const int IINF = 0x7fffffff;
const int iinf = 0x80000000;
const ll LINF = 0x7FFFFFFFFFFFFFFF;
const ll linf = 0x8000000000000000;
int dx[8] = { 1, -1, 0, 0, 1, -1, 1, -1 };
int dy[8] = { 0, 0, 1, -1, 1, -1, -1, 1 };
//#include "Lynia.h"
const int mod = 998244353;
const int N = 1e6 + 10;
void solve(int CASE)
{
string a; cin >> a;
int n = a.size();
a = ' ' + a;
var b = vector<int>(n + 1, -1);
fa(i, 1, n) {
if (a[i] == '(' or a[i] == ')')b[i] = 0;
else b[i] = 1;
}
int l = 1, r = n;
bool L = 0, R = 0;
if (b[1] == b[2])L = 1, l = 3;
if (b[n - 1] == b[n])R = 1, r = n - 2;
if (L and R) {
if (n == 2)cout << "Yes" << endl;
else cout << "No" << endl;
return;
}
fa(i, l, r) {
int x = i, y = r - (i - l);
if (b[x] != b[y] or b[i] == b[i - 1])break;
if (x + 1 == y) {
cout << "Yes" << endl;
return;
}
}
cout << "No" << endl;
return;
}
int main()
{
//SetConsoleOutputCP(CP_UTF8);
ios::sync_with_stdio(0), cin.tie(0), cout.tie(0);
int _ = 1;
cin >> _;
fa(i, 1, _)solve(i);
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 1ms
memory: 3612kb
input:
6 )) ((() [()] ()[()]() ([()]) ([])([])
output:
Yes No Yes No Yes No
result:
ok 6 token(s): yes count is 3, no count is 3
Test #2:
score: 0
Accepted
time: 0ms
memory: 3556kb
input:
2 (([([[([ ]]))])]])]
output:
Yes No
result:
ok 2 token(s): yes count is 1, no count is 1
Test #3:
score: -100
Wrong Answer
time: 3ms
memory: 3624kb
input:
15134 ][ )( )([[ [)([ )][) ]])( ([]([] ]]))][ [([](] ()[))] ][(]]( ([()[) ()[](( [)([)( ]]([[)]] )[()])]] ))[](([] ](([((]] ))[)][)[ [)])([(] [()[]))[ )][(]()] [[((]()] ((]])[[) ])(](]]) )]]()[]( ([)[])]) [[)[()]( ([[)[[() [[)([])) [)[[)[() ))[(([)( ()][)[](]] [()]([[([[ )[]))][)][ )]([]([(][ [])])(...
output:
Yes Yes No Yes Yes No Yes No Yes Yes Yes Yes No Yes No Yes No No Yes Yes No No No No No No Yes Yes No No Yes No No No No Yes No No No No No No No No No Yes Yes No No No No No No No No No No No No Yes Yes No No No No No No No No No Yes No No No No No No No No No No Yes No No No No No No No No No No N...
result:
wrong answer expected YES, found NO [3rd token]