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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#648941 | #7882. Linguistics Puzzle | AlphaZe | WA | 3ms | 3932kb | C++20 | 3.6kb | 2024-10-17 21:02:37 | 2024-10-17 21:02:37 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
#define pii pair<int, int>
#define x first
#define y second
#define ll long long
const int N = 55;
int ff[505]; char f[N];
int n; bool fl;
pii str[N * N], num[N * N];
int nm1[N * N], nm2[N * N];
int ton[N][4], ton2[N][4];
int a[N];
ll pown2[4], has[N], has2[N];
map<ll, vector<int>> mp;
int vis[N], fvis[N]; // 字母->数字
void calc(int x, int id) {
int fi = x / n, se = x % n;
num[id] = make_pair(fi, se);
if (!fi) ++ton[se][0];
else {
if (fi == se) ++ton[fi][3];
else ++ton[fi][1], ++ton[se][2];
}
}
void calcstr(int id) {
int fi = str[id].x, se = str[id].y;
if (fi == -1) ++ton2[se][0];
else if (fi == se) ++ton2[fi][3];
else ++ton2[fi][1], ++ton2[se][2];
}
bool cmp(int x, int y) {
return mp[has[x]].size() < mp[has[y]].size();
}
bool cmp2(pii a, pii b) {
return vis[a.x] * n + vis[a.y] < vis[b.x] * n + vis[b.y];
}
bool check() {
for (int i = 1; i <= n * n; ++i)
nm2[i] = ((str[i].x == -1) ? 0 : (vis[str[i].x] * n)) + vis[str[i].y];
sort(nm2 + 1, nm2 + n * n + 1);
// for (int i = 1; i <= n * n; ++i) printf("%d ", nm2[i]); putchar('\n');
for (int i = 1; i <= n * n; ++i)
if (nm1[i] != nm2[i]) {
// printf("nm1[%d] = %d, nm2[%d] = %d; \n", i, nm1[i], i, nm2[i]);
return false;
}
return true;
}
void print() {
for (int i = 0; i < n; ++i) fvis[vis[i]] = i;
for (int i = 0; i < n; ++i) printf("%c", f[fvis[i]]); putchar('\n');
}
void dfs(int step) {
if (fl) return;
if (step == n) {
// puts("sb");
if (check()) {
print();
fl = 1;
}
return;
}
for (auto x : mp[has[a[step]]]) {
if (vis[x]) continue;
vis[x] = step;
dfs(step + 1);
vis[x] = 0;
}
}
void work() {
scanf("%d", &n);
for (int i = 0; i < n; ++i)
for (int j = 0; j < 4; ++j) ton[i][j] = ton2[i][j] = 0;
for (int i = 1; i <= n * n; ++i) {
char s[4];
scanf("%s", s + 1);
int len = strlen(s + 1);
if (len == 1) str[i].x = -1, str[i].y = ff[s[1]];
else str[i].x = ff[s[1]], str[i].y = ff[s[2]];
calcstr(i);
}
for (int i = 0; i < n; ++i)
for (int j = 0; j < n; ++j)
calc(i * j, i * n + j + 1), nm1[i * n + j + 1] = i * j;
sort(nm1 + 1, nm1 + n * n + 1);
// for (int i = 1; i <= n * n; ++i) printf("%d ", nm1[i]); putchar('\n');
pown2[0] = 1; for (int i = 1; i < 4; ++i) pown2[i] = pown2[i - 1] * (n * n + 1);
for (int i = 0; i < n; ++i) {
has[i] = 0;
for (int j = 0; j < 4; ++j) has[i] += pown2[j] * ton[i][j];
// printf("i = %d, {%d, %d}, hash = %lld; {%d, %d, %d, %d} \n", i, num[i].x, num[i].y, has[i], ton[i][0], ton[i][1], ton[i][2], ton[i][3]);
}
for (int i = 0; i < n; ++i) {
has2[i] = vis[i] = 0;
for (int j = 0; j < 4; ++j) has2[i] += pown2[j] * ton2[i][j];
// printf("i = %d, {%d, %d}, hash = %lld; {%d, %d, %d, %d} \n", i, str[i].x, str[i].y, has2[i], ton2[i][0], ton2[i][1], ton2[i][2], ton2[i][3]);
mp[has2[i]].push_back(i);
}
for (int i = 0; i < n; ++i) a[i] = i;
sort(a, a + n, cmp);
dfs(1); mp.clear(); if (!fl) puts("sb"); fl = 0;
}
int main() {
for (int i = 'a'; i <= 'z'; ++i) ff[i] = i - 'a', f[i - 'a'] = i;
for (int i = 'A'; i <= 'Z'; ++i) ff[i] = i - 'A' + 26, f[i - 'A' + 26] = i;
int Tt; scanf("%d", &Tt);
while (Tt--) work();
}
详细
Test #1:
score: 100
Accepted
time: 0ms
memory: 3860kb
input:
2 3 a b a b b b b c cc 4 d d d d d c b a d b cd cb d a cb bc
output:
bca dcba
result:
ok OK
Test #2:
score: 0
Accepted
time: 0ms
memory: 3888kb
input:
2 4 d a a bc ba bc b a a a d a a cb c c 4 a b da b b d ad b db b a c da b c b
output:
abcd bdac
result:
ok OK
Test #3:
score: -100
Wrong Answer
time: 3ms
memory: 3932kb
input:
50 3 b b b a a c b b cc 4 d ab c ad d b ba ab c b d d d d d a 5 a aa aa ab ab ae b b e c c c ba c c c c dd d d dd c e c e 6 a ca a a a a a a ce a a b ba ba bc bc bd be e c c ca a cd cd be d d dc dc e e a eb f f 7 a a a a a a a a cf a a a a b b b b c c c cf a dd d dc d dd e f ed ee ee fb eg eg eg eg ...
output:
bca dabc cadbe abcdef aefdcgb fcheabgd bhgfedcia jhcgfideba fjbadkegcih klhgjbaedcif igkjmclfedhba nflijahgmbdcek anmlfijbgkhdceo nofmlkjchdbegipa sb sb sb sb sb sb sb sb sb sb sb sb sb sb sb sb sb sb sb sb sb sb sb sb sb sb sb sb sb sb sb sb sb sb sb sb
result:
wrong answer invalid length at case #15