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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#648920 | #7882. Linguistics Puzzle | AlphaZe | WA | 2ms | 3904kb | C++20 | 3.6kb | 2024-10-17 20:57:43 | 2024-10-17 20:57:44 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
#define pii pair<int, int>
#define x first
#define y second
#define ll long long
const int N = 55;
char ff[505]; int f[N];
int n; bool fl;
pii str[N * N], num[N * N];
int nm1[N * N], nm2[N * N];
int ton[N][4], ton2[N][4];
int a[N];
ll pown2[4], has[N], has2[N];
map<ll, vector<int>> mp;
int vis[N], fvis[N]; // 字母->数字
void calc(int x, int id) {
int fi = x / n, se = x % n;
num[id] = make_pair(fi, se);
if (!fi) ++ton[se][0];
else {
if (fi == se) ++ton[fi][3];
else ++ton[fi][1], ++ton[se][2];
}
}
void calcstr(int id) {
int fi = str[id].x, se = str[id].y;
if (fi == -1) ++ton2[se][0];
else if (fi == se) ++ton2[fi][3];
else ++ton2[fi][1], ++ton2[se][2];
}
bool cmp(int x, int y) {
return mp[has[x]].size() < mp[has[y]].size();
}
bool cmp2(pii a, pii b) {
return vis[a.x] * n + vis[a.y] < vis[b.x] * n + vis[b.y];
}
bool check() {
for (int i = 1; i <= n * n; ++i)
nm2[i] = ((str[i].x == -1) ? 0 : (vis[str[i].x] * n)) + vis[str[i].y];
sort(nm2 + 1, nm2 + n * n + 1);
// for (int i = 1; i <= n * n; ++i) printf("%d ", nm2[i]); putchar('\n');
for (int i = 1; i <= n * n; ++i)
if (nm1[i] != nm2[i]) {
// printf("nm1[%d] = %d, nm2[%d] = %d; \n", i, nm1[i], i, nm2[i]);
return false;
}
return true;
}
void print() {
for (int i = 0; i < n; ++i) fvis[vis[i]] = i;
for (int i = 0; i < n; ++i) printf("%c", f[fvis[i]]); putchar('\n');
}
void dfs(int step) {
if (fl) return;
if (step == n) {
// puts("sb");
if (check()) {
print();
fl = 1;
}
return;
}
for (auto x : mp[has[a[step]]]) {
if (vis[x]) continue;
vis[x] = step;
dfs(step + 1);
vis[x] = 0;
}
}
void work() {
scanf("%d", &n);
for (int i = 0; i < n; ++i)
for (int j = 0; j < 4; ++j) ton[i][j] = ton2[i][j] = 0;
for (int i = 1; i <= n * n; ++i) {
char s[4];
scanf("%s", s + 1);
int len = strlen(s + 1);
if (len == 1) str[i].x = -1, str[i].y = ff[s[1]];
else str[i].x = ff[s[1]], str[i].y = ff[s[2]];
calcstr(i);
}
for (int i = 0; i < n; ++i)
for (int j = 0; j < n; ++j)
calc(i * j, i * n + j + 1), nm1[i * n + j + 1] = i * j;
sort(nm1 + 1, nm1 + n * n + 1);
// for (int i = 1; i <= n * n; ++i) printf("%d ", nm1[i]); putchar('\n');
pown2[0] = 1; for (int i = 1; i < 4; ++i) pown2[i] = pown2[i - 1] * (n * n + 1);
for (int i = 0; i < n; ++i) {
has[i] = 0;
for (int j = 0; j < 4; ++j) has[i] += pown2[j] * ton[i][j];
// printf("i = %d, {%d, %d}, hash = %lld; {%d, %d, %d, %d} \n", i, num[i].x, num[i].y, has[i], ton[i][0], ton[i][1], ton[i][2], ton[i][3]);
}
for (int i = 0; i < n; ++i) {
has2[i] = vis[i] = 0;
for (int j = 0; j < 4; ++j) has2[i] += pown2[j] * ton2[i][j];
// printf("i = %d, {%d, %d}, hash = %lld; {%d, %d, %d, %d} \n", i, str[i].x, str[i].y, has2[i], ton2[i][0], ton2[i][1], ton2[i][2], ton2[i][3]);
mp[has2[i]].push_back(i);
}
for (int i = 0; i < n; ++i) a[i] = i;
sort(a, a + n, cmp);
dfs(1); mp.clear(); fl = 0;
}
int main() {
for (int i = 'a'; i <= 'z'; ++i) ff[i] = i - 'a', f[i - 'a'] = i;
for (int i = 'A'; i <= 'Z'; ++i) ff[i] = i - 'A' + 26, f[i - 'A' + 26] = i;
int Tt; scanf("%d", &Tt);
while (Tt--) work();
}
詳細信息
Test #1:
score: 100
Accepted
time: 1ms
memory: 3864kb
input:
2 3 a b a b b b b c cc 4 d d d d d c b a d b cd cb d a cb bc
output:
bca dcba
result:
ok OK
Test #2:
score: 0
Accepted
time: 0ms
memory: 3904kb
input:
2 4 d a a bc ba bc b a a a d a a cb c c 4 a b da b b d ad b db b a c da b c b
output:
abcd bdac
result:
ok OK
Test #3:
score: -100
Wrong Answer
time: 2ms
memory: 3864kb
input:
50 3 b b b a a c b b cc 4 d ab c ad d b ba ab c b d d d d d a 5 a aa aa ab ab ae b b e c c c ba c c c c dd d d dd c e c e 6 a ca a a a a a a ce a a b ba ba bc bc bd be e c c ca a cd cd be d d dc dc e e a eb f f 7 a a a a a a a a cf a a a a b b b b c c c cf a dd d dc d dd e f ed ee ee fb eg eg eg eg ...
output:
bca dabc cadbe abcdef aefdcgb fcheabgd bhgfedcia jhcgfideba fjbadkegcih klhgjbaedcif igkjmclfedhba nflijahgmbdcek anmlfijbgkhdceo nofmlkjchdbegipa
result:
wrong output format Unexpected end of file - token expected