#include <bits/stdc++.h>
using namespace std;
typedef unsigned long long ull;
#define rep(i, j, k) for (int i = (j); i <= (k); ++i)
#define per(i, j, k) for (int i = (j); i >= (k); --i)
#define sz(v) int((v).size())
#define all(v) (v).begin(), (v).end()
#define endl "\n"
#define no cout << "NO" << endl;
#define yes cout << "YES" << endl;
using ll = long long;
using pii = std::pair<int, int>;
using pll = std::pair<ll, ll>;
typedef double db;
const db eps = 1e-8;
#define inf 1e18
#define ret                 \
    {                       \
        cout << -1 << endl; \
        return;             \
    }
template <typename T>
bool gmax(T &x, const T y)
{
    if (x < y)
        return x = y, 1;
    return 0;
}
template <typename T>
bool gmin(T &x, const T y)
{
    if (y < x)
        return x = y, 1;
    return 0;
}
#define maxn 200003
struct node
{
    int name;
    int w, id;
    bool friend operator<(node a, node b)
    {
        return a.w > b.w;
    }
} a[maxn];
vector<int> mp[maxn];
int ans[maxn];
void solve()
{
    map<string, int> m;
    string s;
    int n, k, x, mn = 1e9, cnt = 0;
    cin >> n >> k;
    rep(i, 1, k) cin >> x, gmin(mn, x);
    rep(i, 1, n) cin >> a[i].w >> s, a[i].id = i, a[i].name = (m[s] ? m[s] : ++cnt), m[s]++;
    sort(a + 1, a + 1 + n);
    rep(i, 1, n)
    {
        for (int j = 1; j <= cnt; j++)
        {
            vector<int> &b = mp[j];
            // vector<int>&b=team;
            if (lower_bound(all(b), a[i].w) != b.end())
            {
                int it = lower_bound(all(b), a[i].w) - b.begin();
                it = sz(b) - it;
                //>cout<<i<<" "<<it<<endl;
                if (j == a[i].name && it >= mn)
                    it = mn - 1;
                else
                    gmin(it, mn);
                ans[a[i].id] += it;
            }
        }
        ans[a[i].id]++;
        mp[a[i].name].push_back(a[i].w);
    }
    rep(i, 1, n) cout << ans[i] << endl;
}
signed main()
{
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    cout.tie(NULL);
    int t = 1;
    // cin >> t;
    while (t--)
        solve();
}
// 循环边界
// 二分l和r的范围
// 数组越界
// 在函数内开数组赋初值
// long long
// 尽量用数学语言刻画
// 从直觉到严谨分析，推导
// 冷静，冷静，冷静