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QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#646368#6434. Paimon SortinglongyinAC ✓94ms5012kbC++202.1kb2024-10-16 22:30:142024-10-16 22:30:15

Judging History

你现在查看的是最新测评结果

  • [2024-10-16 22:30:15]
  • 评测
  • 测评结果:AC
  • 用时:94ms
  • 内存:5012kb
  • [2024-10-16 22:30:14]
  • 提交

answer

#include <bits/stdc++.h>
#define int long long
#define endl "\n"
using namespace std;

using ll = long long;
const int INF = 1e9;
const int MOD = 1e9 + 7;
const int N = 1e6 + 5;

struct BIT {
    vector<int> tr;
    int n;
    BIT(int n = N - 1) : n(n) {
        tr.resize(n + 1, 0);
    }
    int lowbit(int x) {
        return x & -x;
    }
    void add(int x, int k) {
        for (int i = x; i <= n; i += lowbit(i)) {
            tr[i] += k;
        }
    }
    ll sum(int x) {
        ll res = 0;
        for (int i = x; i >= 1; i -= lowbit(i)) {
            res += tr[i];
        }
        return res;
    }
};

int a[N];

int check(vector<int> arr) {
    int ans = 0;
    for (int i = 0; i < arr.size(); i++) {
        int cnt = 0;
        for (int j = 0; j < arr.size(); j++) {
            if (arr[i] < arr[j]) {
                cnt++;
                swap(arr[i], arr[j]);
            }
        }
        ans += cnt;
    } 
    return ans;
}

void solve() {
    int n;
    cin >> n;
    for (int i = 1; i <= n; i++) {
        cin >> a[i];
    }
    
    int ans = 0;
    BIT bit(n);
    vector<bool> vis(n + 1, false);
    for (int i = 1, mx = a[i], flag = 0, cnt = 0; i <= n; i++) {
        if (!vis[a[i]]) 
            bit.add(a[i], 1);
        vis[a[i]] = true;
        if (i > 1 && a[i] == mx)
            flag = 1;
        cnt += flag - (flag ? a[i] > mx : 0);
        if (a[i] > mx) {
            ans += cnt + 1;
            ans += bit.sum(n) - bit.sum(mx);
            cnt = 0;
            flag = 0;
            mx = a[i];
        }
        else {
            ans += bit.sum(n) - bit.sum(a[i]);
        }
        cout << ans << " \n"[i == n];
    }
    // for (int i = 1; i <= n; i++) {
    //     vector<int> arr(i);
    //     for (int j = 0; j < i; j++) {
    //         arr[j] = a[j + 1];
    //     }
    //     cout << check(arr) << " \n"[i == n];
    // }
}

signed main() {
    ios::sync_with_stdio(false); cin.tie(nullptr); cout.tie(nullptr);

    int T = 1;
    cin >> T;

    while (T--) {
        solve();
    }

    return 0;
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 0ms
memory: 3596kb

input:

3
5
2 3 2 1 5
3
1 2 3
1
1

output:

0 2 3 5 7
0 2 4
0

result:

ok 3 lines

Test #2:

score: 0
Accepted
time: 94ms
memory: 5012kb

input:

6107
19
10 13 8 8 11 18 12 9 15 19 6 13 11 11 17 9 14 2 18
12
1 8 10 2 10 2 6 1 5 9 5 7
16
14 4 2 15 12 14 10 3 2 9 15 4 12 9 5 15
10
3 2 5 6 7 8 6 1 6 4
18
6 5 12 12 11 2 10 10 5 10 13 15 13 10 17 7 11 2
1
1
2
1 1
3
2 1 2
17
11 15 3 10 7 15 15 10 5 17 3 3 14 13 11 11 2
3
2 2 3
7
6 1 7 5 3 5 1
7
2 1...

output:

0 2 4 6 7 9 11 16 17 19 28 31 36 41 43 51 55 67 68
0 2 4 6 6 8 10 14 17 18 22 25
0 1 3 5 7 8 11 16 22 26 26 31 33 37 42 42
0 1 3 5 7 9 11 17 19 23
0 1 3 3 4 8 10 12 16 18 27 29 30 34 36 42 46 55
0
0 0
0 1 1
0 2 4 6 9 9 9 11 15 21 27 33 35 38 42 46 55
0 0 3
0 1 3 5 8 10 14
0 1 3 4 6 9 9
0 1 1 3 7 11 ...

result:

ok 6107 lines