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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#646232 | #5076. Prof. Pang and Ants | Kevin5307 | WA | 1ms | 3860kb | C++23 | 3.0kb | 2024-10-16 21:48:27 | 2024-10-16 21:48:28 |
Judging History
answer
//Author: Kevin
#include<bits/stdc++.h>
//#pragma GCC optimize("O2")
using namespace std;
#define ll long long
#define ull unsigned ll
#define pb emplace_back
#define mp make_pair
#define ALL(x) (x).begin(),(x).end()
#define rALL(x) (x).rbegin(),(x).rend()
#define srt(x) sort(ALL(x))
#define rev(x) reverse(ALL(x))
#define rsrt(x) sort(rALL(x))
#define sz(x) (int)(x.size())
#define inf 0x3f3f3f3f
#define pii pair<int,int>
#define lb(v,x) (int)(lower_bound(ALL(v),x)-v.begin())
#define ub(v,x) (int)(upper_bound(ALL(v),x)-v.begin())
#define uni(v) v.resize(unique(ALL(v))-v.begin())
#define longer __int128_t
void die(string S){puts(S.c_str());exit(0);}
ll a[100100];
struct block
{
ll A,B,M;
block(){}
block(ll _A,ll _B,ll _M):A(_A),B(_B),M(_M){};
inline ll length(){return (B-A+1)*M;}
inline ll lget(ll x){return (x-1)/M+A;};
inline ll rget(ll x){return lget(length()-x+1);}
inline ll lgetd(ll x){return (x-1)/M*M+M-(x-1);}
inline ll rgetd(ll x){return lgetd(x);}
inline ll lgetd2(ll x){return (x-1)-(x-1)/M*M+1;}
inline ll rgetd2(ll x){return lgetd2(x);}
};
int main()
{
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
int t;
cin>>t;
while(t--)
{
int n;
ll m;
cin>>n>>m;
for(int i=1;i<=n;i++)
{
cin>>a[i];
a[i]++;
}
sort(a+1,a+n+1);
ll l=0,r=1e18;
while(l<r)
{
ll tmp=m;
ll mid=(l+r)/2;
vector<block> vec;
vector<pair<ll,ll>> vect;
for(int i=1;i<=n;i++)
{
vect.pb(a[i],1);
vect.pb(a[i]+(mid+(i&1))/2,-1);
}
int cnt=0;
srt(vect);
for(int i=0;i<sz(vect)-1;i++)
{
cnt+=vect[i].second;
if(!cnt) continue;
if(vect[i].first==vect[i+1].first) continue;
if((vect[i+1].first-vect[i].first)<=m/cnt)
{
vec.pb(vect[i].first,vect[i+1].first-1,cnt);
m-=(vect[i+1].first-vect[i].first)*cnt;
}
else
{
if(m/cnt)
vec.pb(vect[i].first,vect[i].first+m/cnt-1,cnt);
if(m%cnt)
vec.pb(vect[i].first+m/cnt,vect[i].first+m/cnt,m%cnt);
m=0;
}
}
if(m)
{
m=tmp;
l=mid+1;
continue;
}
ll L=0,R=0;
int lp=0,rp=sz(vec)-1;
ll ans=0;
while(lp<sz(vec))
{
if(L==vec[lp].length())
{
L=0;
lp++;
continue;
}
if(R==vec[rp].length())
{
R=0;
rp--;
continue;
}
ll len=min(vec[lp].length()-L,vec[rp].length()-R);
ans=max(ans,vec[lp].lget(L+1)+vec[rp].rget(R+1));
ans=max(ans,vec[lp].lget(L+len)+vec[rp].rget(R+len));
if(vec[lp].M>=vec[rp].M)
if(vec[lp].lgetd(L+1)<vec[rp].rgetd(R+1)&&vec[lp].lgetd(L+1)<=len-1)
ans=max(ans,vec[lp].lget(L+1)+vec[rp].rget(R+1)+1);
if(vec[lp].M<=vec[rp].M)
if(vec[lp].lgetd2(L+len)>vec[rp].rgetd2(R+len)&&vec[rp].rgetd2(R+len)<=len-1)
ans=max(ans,vec[lp].lget(L+len)+vec[rp].rget(R+len)+1);
L+=len;
R+=len;
}
if(ans<=mid)
r=mid;
else
l=mid+1;
m=tmp;
}
cout<<l<<'\n';
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 1ms
memory: 3860kb
input:
3 2 4 1 2 3 10 1 2 3 5 1 1 2 3 4 5
output:
6 9 4
result:
ok 3 number(s): "6 9 4"
Test #2:
score: -100
Wrong Answer
time: 0ms
memory: 3660kb
input:
1 1 100000000000000 1000000000
output:
199999999999999
result:
wrong answer 1st numbers differ - expected: '200000000000000', found: '199999999999999'