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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#646197 | #7906. Almost Convex | frankly6 | TL | 0ms | 0kb | C++20 | 2.1kb | 2024-10-16 21:40:08 | 2024-10-16 21:40:08 |
answer
#include<iostream>
#include<algorithm>
#include<cmath>
#include<cstring>
using namespace std;
typedef double ld;
typedef pair<int,int> PII;
const int MX=2020;
int N, cnt;
bool ins[MX];
bool vis[MX][MX];
int read()
{
int r=0, f=1; char ch=getchar();
while(ch<'0'||ch>'9') {if(ch=='-') f=-1; ch=getchar();}
while(ch>='0'&&ch<='9') {r=r*10+ch-'0'; ch=getchar();}
return r*f;
}
ld py, px;
struct point
{
ld x, y; int id;
point operator - (const point &a)const {return {x-a.x,y-a.y,id};}
point operator + (const point &a)const {return {x+a.x,y+a.y,id};}
ld operator ^ (const point &a)const {return x*a.y-y*a.x;}
bool operator < (const point &a)const
{
// return (x-px)*(a.y-py)-(y-py)*(a.x-px)>0;
ld t1=atan2(y-py,x-px);
ld t2=atan2(a.y-py,a.x-px);
// cout << "t1=" << t1 << ", t2=" << t2 << '\n';
return t1<t2;
}
}p[MX], np[MX], s1[MX];
int t1;
int main()
{
freopen("testdata.in","r",stdin);
N=read(); int id=1;
for(int i=1;i<=N;i++)
{
scanf("%lf%lf",&p[i].x,&p[i].y);
p[i].id=i;
if(p[i].x<p[id].x||(p[i].x==p[id].x&&p[i].y<p[id].y)) id=i;
}
swap(p[1],p[id]); py=p[1].y; px=p[1].x;
sort(p+2,p+1+N);
// for(int i=1;i<=N;i++) cout << "(" << p[i].x << "," << p[i].y << "), "; cout << '\n';
s1[++t1]=p[1];
for(int i=2;i<=N;i++)
{
while(t1>=2&&((s1[t1]-s1[t1-1])^(p[i]-s1[t1]))<=0) t1--;
s1[++t1]=p[i];
}
for(int i=1;i<=t1;i++) ins[s1[i].id]=1;
s1[++t1]=p[1];
for(int i=1;i<t1;i++) vis[s1[i].id][s1[i+1].id]=1;
int ans=0;
memcpy(np,p,sizeof(p));
for(int i=1;i<=N;i++)
{
// if(i%100==0) cout << "i=" << i << '\n';
int id=np[i].id;
if(ins[id]) continue;
py=np[i].y, px=np[i].x;
sort(p+1,p+1+N);
p[N+1]=p[1];
for(int j=1;j<=N;j++)
{
int nxt=(p[j+1].id==id)?p[j+2].id:p[j+1].id;
ans+=vis[p[j].id][nxt];
}
}
cout << ans+1 << '\n';
return (0-0);
}
詳細信息
Test #1:
score: 0
Time Limit Exceeded
input:
7 1 4 4 0 2 3 3 1 3 5 0 0 2 4