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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#644811#8577. 평균 최대화user100860 180ms676332kbC++239.0kb2024-10-16 15:31:402024-10-16 15:32:14

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  • [2024-10-16 15:32:14]
  • 评测
  • 测评结果:0
  • 用时:180ms
  • 内存:676332kb
  • [2024-10-16 15:31:40]
  • 提交

answer

#include <bits/stdc++.h>

using namespace std;

#define int long long

const int N = 3e5 + 10;

int n, idx, l[N], r[N], a[N], s[N], rx[N], rs[N];

//  #define __int128 int

struct F
{
	__int128 i, j;
	
	F()
	{
		i = j = 0;
	}
	
	F(__int128 a, __int128 b)
	{
		i = a, j = b;
		__int128 d = __gcd(i, j);
		i /= d, j /= d;
	}
	
	bool operator> (const F& f2) const
	{
		return i * f2.j > j * f2.i;
	}
	
	bool operator< (const F& f2) const
	{
		return i * f2.j < j * f2.i;
	}
	
	F operator + (const F& f2) const
	{
		__int128 a = i * f2.j + j * f2.i, b = j * f2.j;
		return {a, b};
	}
	
}ans[N];

int pc;
mt19937 rng(20241015);
namespace Tree
{
	const int R = 20;
	int idx;
	int ls[N * R], rs[N * R], sz[N * R];
	F tass[N * R];
	F val[N * R], sum[N * R];
	
	void init()
	{
		val[0] = sum[0] = {0, 1};
	}
	
	int newnode(F v)
	{
		idx++;
		assert(idx < N * R);
		ls[idx] = rs[idx] = 0, sz[idx] = 1, tass[idx] = {0, 1};
		val[idx] = sum[idx] = v;
		return idx;
	}
	
	inline void pushup(int u)
	{
		if (!u) return;
	    pc++;
		sum[u] = sum[ls[u]] + val[u] + sum[rs[u]];
		sz[u] = sz[ls[u]] + 1 + sz[rs[u]];
	}
	
	inline void apply(int u, const F& dass)
	{
		if (!u) return;
		sum[u] = {dass.i * sz[u], dass.j}, val[u] = dass;
		tass[u] = dass;
	}
	
	inline void pushdown(int u)
	{
		if (!u) return;
		if (tass[u].i == 0) return;
	    pc++;
		apply(ls[u], tass[u]), apply(rs[u], tass[u]);
		tass[u] = {0, 1};
	}
	
	array<int, 2> splitr(int u, int k)
	{
		// [1, k], [k+1, inf)
//		printf("splitr(%lld, %lld)\n", u, k);
		if (!u) return {0, 0};
		pushdown(u);
		if (sz[ls[u]] >= k)
		{
			auto res = splitr(ls[u], k);
			ls[u] = res[1];
			pushup(u);
			return {res[0], u};
		}
		else
		{
			auto res = splitr(rs[u], k - sz[ls[u]] - 1);
			rs[u] = res[0];
			pushup(u);
//			printf("&&&");
			return {u, res[1]};
		}
	}
	
	array<int, 2> splitv(int u, const F& v)
	{
		// [1, v] [v, inf)
		if (!u) return {0, 0};
		pushdown(u);
		if (v > val[u])
		{
			auto res = splitv(ls[u], v);
			ls[u] = res[1];
			pushup(u);
			return {res[0], u};
		}
		else
		{
			auto res = splitv(rs[u], v);
			rs[u] = res[0];
			pushup(u);
			return {u, res[1]};
		}
	}
	
	int merge(int l, int r)
	{
//		printf("merge(%lld, %lld)\n", l, r);
		if (!l) swap(l, r);
		if (!r) return l;
		
		pushdown(l), pushdown(r);
		if (rng() % (sz[l] + sz[r]) < sz[l])
		{
			rs[l] = merge(rs[l], r);
			pushup(l);
			return l;
		}
		else
		{
			ls[r] = merge(l, ls[r]);
			pushup(r);
			return r;
		}
	}
	
	inline void insert(int& rt, const F& v)
	{
		auto res = splitv(rt, v);
		int c = newnode(v);
		rt = merge(merge(res[0], c), res[1]);
	}
	
	inline void assign(int& rt, int pos, const F& v)
	{
		auto res = splitr(rt, pos);
		apply(res[0], v);
		rt = merge(res[0], res[1]);
	}
	
	inline F qsum(int rt, int pos)
	{
	    if (!rt) return {0, 1};
	    pushdown(rt);
	    if (pos <= sz[ls[rt]]) return qsum(ls[rt], pos);
	    else return sum[ls[rt]] + val[rt] + qsum(rs[rt], pos - sz[ls[rt]] - 1);
// 		auto res = splitr(rt, pos);
//		printf("qsum(%lld, %lld)\n", rt, pos);
// 		F ret = sum[res[0]];
// 		rt = merge(res[0], res[1]);
// 		return ret;
	}
	
	const F& kth(int rt, int k)
	{
	    int p = sz[ls[rt]];
	    pushdown(rt);
	    if (k <= p) return kth(ls[rt], k);
	    else if (k > p + 1) return kth(rs[rt], k - sz[ls[rt]] - 1);
	    else return val[rt];
// 		auto res = splitr(rt, k);
// 		auto res2 = splitr(res[0], k - 1);
// 		F ret = val[res2[1]];
// 		rt = merge(merge(res2[0], res2[1]), res[1]);
// 		return ret;	
	}
	
 	void print(int rt)
 	{
 		if (!rt) return;
 		print(ls[rt]), printf("node %lld: sum = %lld/%lld, val = %lld/%lld, tass = %lld/%lld, ls = %lld, rs = %lld\n", rt, sum[rt].i, sum[rt].j, val[rt].i, val[rt].j, tass[rt].i, tass[rt].j, ls[rt], rs[rt]), print(rs[rt]);
 	}
}

int pc2;
int dp[N];
vector<int> son[N];
vector<int> rg[N];
map<array<int, 2>, int> mp;

int build(int l, int r)
{
	idx++, ::l[idx] = l, ::r[idx] = r, mp[{l, r}] = idx;
	int x = idx; rx[x] = r - l + 1, rs[x] = s[r] - s[l - 1];
	for (int i = l; i <= r; i++)
	{
		if (rg[i].empty()) continue;
		int j = rg[i].back(); rg[i].pop_back();
		int y = build(i, j);
		son[x].push_back(y);
		rx[x] -= (j - i + 1), rs[x] -= (s[j] - s[i - 1]);
		i = j;
	}
	return x;
}

template<class T>
void chkmax(T &x, T y)
{
	if (y > x) x = y;
}

int merge(int& a, int b)
{
	if (!b) return a;
	Tree::insert(a, Tree::val[b]);
	Tree::pushdown(b);
	merge(a, Tree::ls[b]), merge(a, Tree::rs[b]);
}

void getp(int rt, int a, int b, F cur, int rk, pair<int, F>& ans)
{
//	printf("getp(%lld, %lld, %lld, {%lld, %lld}, %lld)\n", rt, a, b, cur.i, cur.j, rk);
    if (!rt) return;
    Tree::pushdown(rt);
    F f = cur + Tree::sum[Tree::ls[rt]], d = Tree::val[rt];
    f.i -= b * f.j, f.j *= (rk + Tree::sz[Tree::ls[rt]] - a);
//    printf("f\' = {%lld, %lld}, d = {%lld, %lld}\n", f.i, f.j, d.i, d.j);
    if (f > d) getp(Tree::ls[rt], a, b, cur, rk, ans);
    else
    {
    	f = cur + Tree::sum[Tree::ls[rt]] + Tree::val[rt];
    	f.i -= b * f.j, f.j *= (rk + Tree::sz[Tree::ls[rt]] + 1 - a);
        ans = {rk + Tree::sz[Tree::ls[rt]] + 1, f};
        getp(Tree::rs[rt], a, b, cur + Tree::sum[Tree::ls[rt]] + Tree::val[rt], rk + Tree::sz[Tree::ls[rt]] + 1, ans);
    }
}

// pair<int, F> getp(int rt, int a, int b)
// {
// 	// max (y - b) / (x - a)
// 	int l = 0, r = Tree::sz[rt];
// 	auto getres = [&](int x)
// 	{
// 		F y1 = Tree::qsum(rt, x);
// 		y1.i -= b * y1.j, y1.j *= (x - a);
// //		y1.reduce();
// 		return y1;
// 	};
// 	int dpc = 0;
// 	while (l < r)
// 	{
// //		int mid1 = (l + r) >> 1, mid2 = mid1 + 1;
//         dpc += 2;
// 		int mid = (l + r) >> 1;
// 		F f = Tree::qsum(rt, mid), d = Tree::kth(rt, mid + 1);
// 		f.i -= b * f.j, f.j *= (mid - a);
// 		if (f > d) r = mid;
// 		else l = mid + 1;
// 	}
// //	printf(")))"), Tree::print(rt);
// //	printf("res(l) = (%lld, %lld/%lld), res(r) = (%lld, %lld/%lld)\n", l, getres(l).i, getres(l).j, r, getres(r).i, getres(r).j);
// 	dpc++;
// 	assert(dpc < 19 * 2 + 1);
// 	pc2 += dpc;
// 	auto resl = getres(l);
// 	return {l, resl};
// }

void dfs(int x)
{
//	printf("dfs(%lld)\n", x);
	dp[x] = 0;
	if (son[x].empty()) for (int i = 1; i <= rx[x]; i++) Tree::insert(dp[x], {rs[x], rx[x]});
	else 
	{
		for (int y : son[x]) 
		{
			dfs(y);
			if (Tree::sz[dp[x]] < Tree::sz[dp[y]]) swap(x, y);
			dp[x] = merge(dp[x], dp[y]);
		}
		if (x == 1) return;
//		Tree::print(dp[x]);
//		 (-rx[x], -rs[x])
//printf("getp(%lld)\n", x);
		pair<int, F> res = {0, {rx[x], rs[x]}};
		getp(dp[x], -rx[x], -rs[x], {0, 1}, 0, res);
//		printf("proc: res = {%lld, %lld/%lld}\n", res.first, res.second.i, res.second.j);
		int p = res.first;
		F v = res.second;
		Tree::assign(dp[x], p, v);
		for (int i = 1; i <= rx[x]; i++) Tree::insert(dp[x], v);
	}
//	Tree::print(dp[x]);
//	cout << "***";
	assert(pc < 3.5e7);
	pair<int, F> res = {0, {2, a[l[x] - 1] + a[r[x] + 1]}};
	getp(dp[x], -2, -(a[l[x] - 1] + a[r[x] + 1]), {0, 1}, 0, res);
	ans[x] = res.second;
//	printf("%lld: (%lld, %lld/%lld)\n", x, res.first, ans[x].i, ans[x].j);
}

bool flag;

void initialize(vector<signed> A)
{
    n = (int)(A.size());
    for (int i = 1; i <= n; i++) a[i] = A[i - 1];
	for (int i = 1; i <= n; i++) s[i] = a[i] + s[i - 1];
    vector<int> s;
    for (int i = n; i >= 1; i--)
    {
    	while (!s.empty() && a[s.back()] > a[i])
    	{
    		int x = s.back(); s.pop_back();
    		if (x != i + 1) rg[i + 1].push_back(x - 1);
    	}
    	if (!s.empty() && s.back() != i + 1) rg[i + 1].push_back(s.back() - 1); 
    	if (!s.empty() && a[s.back()] >= a[i]) s.pop_back();
    	s.push_back(i);
    }
//	for (int i = 1; i <= n; i++)
//		for (int j : rg[i]) printf("[%lld, %lld]\n", i, j);
    
    build(2, n - 1);
//    for (int i = 1; i <= n; i++)
//    	printf("rx[%lld] = %lld, rs[%lld] = %lld\n", i, rx[i], i, rs[i]);
    Tree::init();
    if (!flag) dfs(1);
    
//    for (int i = 1; i <= n; i++)
//    	for (int j = 0; j <= sz[i]; j++)
//    		printf("dp[%lld][%lld] = %lld\n", i, j, dp[i][j]);
    
//    for (int i = 1; i <= n; i++)
//    	for (int j : son[i]) printf("[%lld, %lld] -> [%lld, %lld]\n", l[i], r[i], l[j], r[j]);
}

array<long long, 2> maximum_average(signed i, signed j)
{
	i++, j++;
	if (j == i + 1) return {a[i] + a[j], 2};
	assert(mp.find({i + 1, j - 1}) != mp.end());
	int id = mp[{i + 1, j - 1}];
	if (flag) return {idx, ans[id].j};
	return {ans[id].i, ans[id].j};
}

//signed main()
//{
//	cin.tie(0)->sync_with_stdio(0);
//	
//	int n; cin >> n;
//	vector<signed> A;
// 	for (int i = 1, ai; i <= n; i++) cin >> ai, A.push_back(ai); 
////	for (int i = 1, ai; i <= n; i++) A.push_back(min(i, n - i + 1));
//	initialize(A);
//	printf("idx = %lld, pc = %lld, pc2 = %lld, time = %lld\n", idx, pc, pc2, (int)clock());
//	int l, r;
//	while (cin >> l >> r)
//	{
//		auto res = maximum_average(l, r);
//		cout << res[0] << ' ' << res[1] << '\n';
//	}
//}

Details

Tip: Click on the bar to expand more detailed information

Subtask #1:

score: 0
Time Limit Exceeded

Test #1:

score: 0
Time Limit Exceeded

input:

10
2 4 3 9 9 9 9 9 9 1
2
0 2
0 9

output:

Unauthorized output

result:


Subtask #2:

score: 0
Skipped

Dependency #1:

0%

Subtask #3:

score: 0
Skipped

Dependency #2:

0%

Subtask #4:

score: 0
Time Limit Exceeded

Test #15:

score: 0
Time Limit Exceeded

input:

300000
1 2 4 4 4 4 3 2 4 4 3 4 4 4 4 4 4 4 4 4 3 4 3 4 4 4 4 4 4 4 4 3 3 4 4 4 3 4 3 4 4 4 4 4 4 4 4 4 4 3 3 4 4 4 3 4 4 3 4 4 4 4 4 4 4 3 2 4 4 4 4 4 4 4 4 4 4 4 4 4 3 4 4 4 4 4 4 4 4 4 4 4 2 4 4 2 4 4 3 4 4 4 2 3 4 4 4 4 4 4 3 2 4 4 4 2 4 4 4 4 4 4 4 4 4 4 4 2 4 4 4 4 4 4 3 4 4 3 4 4 4 4 4 4 4 4 4...

output:

Unauthorized output

result:


Subtask #5:

score: 0
Skipped

Dependency #3:

0%

Subtask #6:

score: 0
Time Limit Exceeded

Test #28:

score: 17
Accepted
time: 180ms
memory: 676332kb

input:

300000
1 300000 300001 299999 300003 299998 300005 299997 300007 299996 300009 299995 300011 299994 300013 299993 300015 299992 300017 299991 300019 299990 300021 299989 300023 299988 300025 299987 300027 299986 300029 299985 300031 299984 300033 299983 300035 299982 300037 299981 300039 299980 3000...

output:

0 0

result:

ok correct!

Test #29:

score: 0
Time Limit Exceeded

input:

262143
1 36 17 55 17 36 16 94 16 36 17 55 17 36 15 173 15 36 17 55 17 36 16 94 16 36 17 55 17 36 14 332 14 36 17 55 17 36 16 94 16 36 17 55 17 36 15 173 15 36 17 55 17 36 16 94 16 36 17 55 17 36 13 651 13 36 17 55 17 36 16 94 16 36 17 55 17 36 15 173 15 36 17 55 17 36 16 94 16 36 17 55 17 36 14 332 ...

output:

Unauthorized output

result:


Subtask #7:

score: 0
Skipped

Dependency #4:

0%

Subtask #8:

score: 0
Skipped

Dependency #1:

0%