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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#644257#8577. 평균 최대화user100867 1288ms118076kbC++238.9kb2024-10-16 12:13:422024-10-16 12:13:43

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你现在查看的是最新测评结果

  • [2024-10-16 12:13:43]
  • 评测
  • 测评结果:7
  • 用时:1288ms
  • 内存:118076kb
  • [2024-10-16 12:13:42]
  • 提交

answer

#include <bits/stdc++.h>

using namespace std;

#define int long long

const int N = 3e5 + 10;

int n, idx, l[N], r[N], a[N], s[N], rx[N], rs[N];

//  #define __int128 int

struct F
{
	__int128 i, j;
	
	F()
	{
		i = j = 0;
	}
	
	F(__int128 a, __int128 b)
	{
		__int128 d = __gcd(a, b);
		i = a / d, j = b / d;
	}
	
	bool operator> (const F& f2) const
	{
		return i * f2.j > j * f2.i;
	}
	
	bool operator< (const F& f2) const
	{
		return i * f2.j < j * f2.i;
	}
	
	F operator + (const F& f2) const
	{
		__int128 a = i * f2.j + j * f2.i, b = j * f2.j;
		return {a, b};
	}
	
	void reduce()
	{
		auto d = __gcd(i, j);
		i /= d, j /= d;
	}
	
}ans[N];

int pc;
mt19937 rng(20241015);
namespace Tree
{
	const int R = 2;
	int idx;
	int ls[N * R], rs[N * R], sz[N * R];
	F tass[N * R];
	F val[N * R], sum[N * R];
	
	void init()
	{
		val[0] = sum[0] = {0, 1};
	}
	
	int newnode(F v)
	{
		idx++;
		assert(idx < N * R);
		ls[idx] = rs[idx] = 0, sz[idx] = 1, tass[idx] = {0, 1};
		val[idx] = sum[idx] = v;
		return idx;
	}
	
	inline void pushup(int u)
	{
		if (!u) return;
	    pc++;
		sum[u] = sum[ls[u]] + val[u] + sum[rs[u]];
		sz[u] = sz[ls[u]] + 1 + sz[rs[u]];
	}
	
	inline void apply(int u, const F& dass)
	{
		if (!u) return;
		sum[u] = {dass.i * sz[u], dass.j}, val[u] = dass;
		tass[u] = dass;
	}
	
	inline void pushdown(int u)
	{
		if (!u) return;
		if (tass[u].i == 0) return;
	    pc++;
		apply(ls[u], tass[u]), apply(rs[u], tass[u]);
		tass[u] = {0, 1};
	}
	
	array<int, 2> splitr(int u, int k)
	{
		// [1, k], [k+1, inf)
//		printf("splitr(%lld, %lld)\n", u, k);
		if (!u) return {0, 0};
		pushdown(u);
		if (sz[ls[u]] >= k)
		{
			auto res = splitr(ls[u], k);
			ls[u] = res[1];
			pushup(u);
			return {res[0], u};
		}
		else
		{
			auto res = splitr(rs[u], k - sz[ls[u]] - 1);
			rs[u] = res[0];
			pushup(u);
//			printf("&&&");
			return {u, res[1]};
		}
	}
	
	array<int, 2> splitv(int u, const F& v)
	{
		// [1, v] [v, inf)
		if (!u) return {0, 0};
		pushdown(u);
		if (v > val[u])
		{
			auto res = splitv(ls[u], v);
			ls[u] = res[1];
			pushup(u);
			return {res[0], u};
		}
		else
		{
			auto res = splitv(rs[u], v);
			rs[u] = res[0];
			pushup(u);
			return {u, res[1]};
		}
	}
	
	int merge(int l, int r)
	{
//		printf("merge(%lld, %lld)\n", l, r);
		if (!l) swap(l, r);
		if (!r) return l;
		
		pushdown(l), pushdown(r);
		if (rng() % (sz[l] + sz[r]) < sz[l])
		{
			rs[l] = merge(rs[l], r);
			pushup(l);
			return l;
		}
		else
		{
			ls[r] = merge(l, ls[r]);
			pushup(r);
			return r;
		}
	}
	
	inline void insert(int& rt, const F& v)
	{
		auto res = splitv(rt, v);
		int c = newnode(v);
		rt = merge(merge(res[0], c), res[1]);
	}
	
	inline void assign(int& rt, int pos, const F& v)
	{
		auto res = splitr(rt, pos);
		apply(res[0], v);
		rt = merge(res[0], res[1]);
	}
	
	inline F qsum(int rt, int pos)
	{
	    if (!rt) return {0, 1};
	    pushdown(rt);
	    if (pos <= sz[ls[rt]]) return qsum(ls[rt], pos);
	    else return sum[ls[rt]] + val[rt] + qsum(rs[rt], pos - sz[ls[rt]] - 1);
// 		auto res = splitr(rt, pos);
//		printf("qsum(%lld, %lld)\n", rt, pos);
// 		F ret = sum[res[0]];
// 		rt = merge(res[0], res[1]);
// 		return ret;
	}
	
	const F& kth(int rt, int k)
	{
	    int p = sz[ls[rt]];
	    pushdown(rt);
	    if (k <= p) return kth(ls[rt], k);
	    else if (k > p + 1) return kth(rs[rt], k - sz[ls[rt]] - 1);
	    else return val[rt];
// 		auto res = splitr(rt, k);
// 		auto res2 = splitr(res[0], k - 1);
// 		F ret = val[res2[1]];
// 		rt = merge(merge(res2[0], res2[1]), res[1]);
// 		return ret;	
	}
	
// 	void print(int rt)
// 	{
// 		if (!rt) return;
// 		print(ls[rt]), printf("node %lld: sum = %lld/%lld, val = %lld/%lld, tass = %lld/%lld, ls = %lld, rs = %lld\n", rt, sum[rt].i, sum[rt].j, val[rt].i, val[rt].j, tass[rt].i, tass[rt].j, ls[rt], rs[rt]), print(rs[rt]);
// 	}
}

int pc2;
int dp[N];
vector<int> son[N];
vector<int> rg[N];
map<array<int, 2>, int> mp;

int build(int l, int r)
{
	idx++, ::l[idx] = l, ::r[idx] = r, mp[{l, r}] = idx;
	int x = idx; rx[x] = r - l + 1, rs[x] = s[r] - s[l - 1];
	for (int i = l; i <= r; i++)
	{
		if (rg[i].empty()) continue;
		int j = rg[i].back(); rg[i].pop_back();
		int y = build(i, j);
		son[x].push_back(y);
		rx[x] -= (j - i + 1), rs[x] -= (s[j] - s[i - 1]);
		i = j;
	}
	return x;
}

template<class T>
void chkmax(T &x, T y)
{
	if (y > x) x = y;
}

int merge(int& a, int b)
{
	if (!a) swap(a, b);
	if (!b) return a;
//	printf("merge(%lld, %lld)\n", a, b);
	if (Tree::sz[a] > Tree::sz[b]) swap(a, b);
	Tree::pushdown(a);
	F v = Tree::val[a];
	auto res = Tree::splitv(b, v);
	Tree::ls[a] = merge(Tree::ls[a], res[0]), Tree::rs[a] = merge(Tree::rs[a], res[1]);
	Tree::pushup(a);
	return a;
}

void getp(int rt, int a, int b, F cur, int rk, pair<int, F>& ans)
{
    if (!rt) return;
    F f = cur + Tree::sum[Tree::ls[rt]], d = Tree::val[rt];
    f.i -= b * f.j, f.j *= (rk + Tree::sz[Tree::ls[rt]] + 1 - a);
    if (f > d) getp(Tree::ls[rt], a, b, cur, rk, ans);
    else
    {
    	f = cur + Tree::sum[Tree::ls[rt]] + Tree::val[rt];
    	f.i -= b * f.j, f.j *= (rk + Tree::sz[Tree::ls[rt]] + 1 - a);
        ans = {rk + Tree::sz[Tree::ls[rt]] + 1, f};
        getp(Tree::rs[rt], a, b, cur + Tree::sum[Tree::ls[rt]] + Tree::val[rt], rk + Tree::sz[Tree::ls[rt]] + 1, ans);
    }
}

// pair<int, F> getp(int rt, int a, int b)
// {
// 	// max (y - b) / (x - a)
// 	int l = 0, r = Tree::sz[rt];
// 	auto getres = [&](int x)
// 	{
// 		F y1 = Tree::qsum(rt, x);
// 		y1.i -= b * y1.j, y1.j *= (x - a);
// //		y1.reduce();
// 		return y1;
// 	};
// 	int dpc = 0;
// 	while (l < r)
// 	{
// //		int mid1 = (l + r) >> 1, mid2 = mid1 + 1;
//         dpc += 2;
// 		int mid = (l + r) >> 1;
// 		F f = Tree::qsum(rt, mid), d = Tree::kth(rt, mid + 1);
// 		f.i -= b * f.j, f.j *= (mid - a);
// 		if (f > d) r = mid;
// 		else l = mid + 1;
// 	}
// //	printf(")))"), Tree::print(rt);
// //	printf("res(l) = (%lld, %lld/%lld), res(r) = (%lld, %lld/%lld)\n", l, getres(l).i, getres(l).j, r, getres(r).i, getres(r).j);
// 	dpc++;
// 	assert(dpc < 19 * 2 + 1);
// 	pc2 += dpc;
// 	auto resl = getres(l);
// 	return {l, resl};
// }

void dfs(int x)
{
//	printf("dfs(%lld)\n", x);
	dp[x] = 0;
	if (son[x].empty()) for (int i = 1; i <= rx[x]; i++) Tree::insert(dp[x], {rs[x], rx[x]});
	else 
	{
		for (int y : son[x]) dfs(y), dp[x] = merge(dp[x], dp[y]);
		if (x == 1) return;
//		Tree::print(dp[x]);
//		 (-rx[x], -rs[x])
//printf("getp(%lld)\n", x);
		pair<int, F> res = {0, {rx[x], rs[x]}};
		getp(dp[x], -rx[x], -rs[x], {0, 1}, 0, res);
//		printf("proc: res = {%lld, %lld/%lld}\n", res.first, res.second.i, res.second.j);
		int p = res.first;
		F v = res.second;
		Tree::assign(dp[x], p, v);
		for (int i = 1; i <= rx[x]; i++) Tree::insert(dp[x], v);
	}
//	Tree::print(dp[x]);
//	cout << "***";
	pair<int, F> res = {0, {2, a[l[x] - 1] + a[r[x] + 1]}};
	getp(dp[x], -2, -(a[l[x] - 1] + a[r[x] + 1]), {0, 1}, 0, res);
	ans[x] = res.second;
//	printf("%lld: (%lld, %lld/%lld)\n", x, res.first, ans[x].i, ans[x].j);
}

void initialize(vector<signed> A)
{
    n = (int)(A.size());
    for (int i = 1; i <= n; i++) a[i] = A[i - 1];
	for (int i = 1; i <= n; i++) s[i] = a[i] + s[i - 1];
    vector<int> s;
    for (int i = n; i >= 1; i--)
    {
    	while (!s.empty() && a[s.back()] > a[i])
    	{
    		int x = s.back(); s.pop_back();
    		if (x != i + 1) rg[i + 1].push_back(x - 1);
    	}
    	if (!s.empty() && s.back() != i + 1) rg[i + 1].push_back(s.back() - 1); 
    	if (!s.empty() && a[s.back()] >= a[i]) s.pop_back();
    	s.push_back(i);
    }
//	for (int i = 1; i <= n; i++)
//		for (int j : rg[i]) printf("[%lld, %lld]\n", i, j);
    
    build(2, n - 1);
//    for (int i = 1; i <= n; i++)
//    	printf("rx[%lld] = %lld, rs[%lld] = %lld\n", i, rx[i], i, rs[i]);
    Tree::init();
    dfs(1);
    
//    for (int i = 1; i <= n; i++)
//    	for (int j = 0; j <= sz[i]; j++)
//    		printf("dp[%lld][%lld] = %lld\n", i, j, dp[i][j]);
    
//    for (int i = 1; i <= n; i++)
//    	for (int j : son[i]) printf("[%lld, %lld] -> [%lld, %lld]\n", l[i], r[i], l[j], r[j]);
}

array<long long, 2> maximum_average(signed i, signed j)
{
	i++, j++;
	if (j == i + 1) return {a[i] + a[j], 2};
	assert(mp.find({i + 1, j - 1}) != mp.end());
	int id = mp[{i + 1, j - 1}];
	return {ans[id].i, ans[id].j};
}

//signed main()
//{
//	cin.tie(0)->sync_with_stdio(0);
//	
//	int n; cin >> n;
//	vector<signed> A;
//// 	for (int i = 1, ai; i <= n; i++) cin >> ai, A.push_back(ai); 
//	for (int i = 1, ai; i <= n; i++) A.push_back(min(i, n - i + 1));
//	initialize(A);
//	printf("idx = %lld, pc = %lld, pc2 = %lld, time = %lld\n", idx, pc, pc2, (int)clock());
////	int l, r;
////	while (cin >> l >> r)
////	{
////		auto res = maximum_average(l, r);
////		cout << res[0] << ' ' << res[1] << '\n';
////	}
//}

詳細信息

Subtask #1:

score: 0
Wrong Answer

Test #1:

score: 5
Accepted
time: 11ms
memory: 87784kb

input:

10
2 4 3 9 9 9 9 9 9 1
2
0 2
0 9

output:

9 3
60 9

result:

ok correct!

Test #2:

score: 0
Wrong Answer
time: 7ms
memory: 87796kb

input:

15
4596730 8340349 4612555 5692442 3914918 5213545 5248236 1276073 3844119 2943960 9231647 5091649 2239006 9139001 4735414
100
7 8
5 6
2 4
0 4
8 9
10 11
3 4
0 1
10 11
10 11
3 4
4 5
12 13
0 2
2 4
11 12
12 14
2 3
7 8
12 14
6 7
4 5
11 12
10 11
7 12
8 9
8 9
0 2
2 3
12 14
7 9
7 9
12 13
10 11
9 11
13 14
8...

output:

5120192 2
10461781 2
14219915 3
27156994 5
6788079 2
14323296 2
9607360 2
12937079 2
14323296 2
14323296 2
9607360 2
9128463 2
11378007 2
17549634 3
14219915 3
7330655 2
16113421 3
10304997 2
5120192 2
16113421 3
6524309 2
9128463 2
7330655 2
14323296 2
24626454 6
6788079 2
6788079 2
17549634 3
1030...

result:

wrong answer Wrong Answer on query #25: 24626454/6 != 20782335/5

Subtask #2:

score: 0
Skipped

Dependency #1:

0%

Subtask #3:

score: 0
Skipped

Dependency #2:

0%

Subtask #4:

score: 7
Accepted

Test #15:

score: 7
Accepted
time: 1288ms
memory: 114268kb

input:

300000
1 2 4 4 4 4 3 2 4 4 3 4 4 4 4 4 4 4 4 4 3 4 3 4 4 4 4 4 4 4 4 3 3 4 4 4 3 4 3 4 4 4 4 4 4 4 4 4 4 3 3 4 4 4 3 4 4 3 4 4 4 4 4 4 4 3 2 4 4 4 4 4 4 4 4 4 4 4 4 4 3 4 4 4 4 4 4 4 4 4 4 4 2 4 4 2 4 4 3 4 4 4 2 3 4 4 4 4 4 4 3 2 4 4 4 2 4 4 4 4 4 4 4 4 4 4 4 2 4 4 4 4 4 4 3 4 4 3 4 4 4 4 4 4 4 4 4...

output:

1041675 278497
23 7
3 2
8 2
6 2
8 2
8 2
7 2
5 2
21 6
224 60
8 2
6 2
7 2
42 11
13 4
8 2
7 2
8 2
8 2
8 2
8 2
8 2
8 2
8 2
7 2
10 3
7 2
7 2
38 10
8 2
7 2
8 2
8 2
8 2
8 2
8 2
8 2
7 2
6 2
18 5
8 2
7 2
8 2
7 2
10 3
7 2
7 2
46 12
8 2
7 2
8 2
8 2
8 2
8 2
8 2
8 2
8 2
8 2
7 2
6 2
18 5
8 2
7 2
8 2
7 2
14 4
8 2
...

result:

ok correct!

Subtask #5:

score: 0
Skipped

Dependency #3:

0%

Subtask #6:

score: 0
Time Limit Exceeded

Test #28:

score: 0
Time Limit Exceeded

input:

300000
1 300000 300001 299999 300003 299998 300005 299997 300007 299996 300009 299995 300011 299994 300013 299993 300015 299992 300017 299991 300019 299990 300021 299989 300023 299988 300025 299987 300027 299986 300029 299985 300031 299984 300033 299983 300035 299982 300037 299981 300039 299980 3000...

output:

Unauthorized output

result:


Subtask #7:

score: 0
Wrong Answer

Dependency #4:

100%
Accepted

Test #44:

score: 0
Wrong Answer
time: 432ms
memory: 118076kb

input:

300000
1 18 20 20 20 18 20 19 19 20 20 20 20 20 20 20 20 20 20 20 20 20 13 20 18 20 20 20 20 20 20 20 16 20 20 20 20 20 20 19 18 20 20 20 20 20 18 20 20 20 20 19 20 20 20 20 20 20 20 20 20 20 14 19 20 20 19 20 20 20 19 19 20 18 18 12 20 19 20 20 20 20 20 20 20 11 20 20 14 20 19 19 20 20 20 20 20 20 ...

output:

599375 30647
96 5
19 2
40 2
38 2
40 2
38 2
349 18
39 2
38 2
38 2
57 3
292 15
40 2
39 2
40 2
40 2
40 2
40 2
40 2
40 2
40 2
40 2
40 2
40 2
40 2
33 2
1039 54
428 23
38 2
33 2
174 9
51 3
40 2
38 2
40 2
40 2
40 2
40 2
40 2
36 2
604 31
207 11
40 2
36 2
40 2
40 2
40 2
40 2
39 2
37 2
155 8
136 7
173 9
40 2
...

result:

wrong answer Wrong Answer on query #1: 599375/30647 != 398307/20360

Subtask #8:

score: 0
Skipped

Dependency #1:

0%