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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#643955#8547. Whose Land?MiniLongTL 1ms7732kbC++204.9kb2024-10-16 08:54:252024-10-16 08:54:26

Judging History

你现在查看的是最新测评结果

  • [2024-10-16 08:54:26]
  • 评测
  • 测评结果:TL
  • 用时:1ms
  • 内存:7732kb
  • [2024-10-16 08:54:25]
  • 提交

answer

#include <bits/stdc++.h>
#define _rep(i, x, y) for(int i = x; i <= y; ++i)
#define _req(i, x, y) for(int i = x; i >= y; --i)
#define _rev(i, u) for(int i = head[u]; i; i = e[i].nxt)
#define pb push_back
#define fi first
#define se second
#define mst(f, i) memset(f, i, sizeof f)
using namespace std;
#ifdef ONLINE_JUDGE
#define debug(...) 0
#else
#define debug(...) fprintf(stderr, __VA_ARGS__), fflush(stderr)
#endif
typedef long long ll;
typedef pair<int, int> PII;
namespace fastio{
    #ifdef ONLINE_JUDGE
    char ibuf[1 << 20],*p1 = ibuf, *p2 = ibuf;
    #define get() p1 == p2 && (p2 = (p1 = ibuf) + fread(ibuf, 1, 1 << 20, stdin), p1 == p2) ? EOF : *p1++
    #else
    #define get() getchar()
    #endif
    template<typename T> inline void read(T &t){
        T x = 0, f = 1;
        char c = getchar();
        while(!isdigit(c)){
            if(c == '-') f = -f;
            c = getchar();
        }
        while(isdigit(c)) x = x * 10 + c - '0', c = getchar();
        t = x * f;
    }
    template<typename T, typename ... Args> inline void read(T &t, Args&... args){
        read(t);
        read(args...);
    }
    template<typename T> void write(T t){
        if(t < 0) putchar('-'), t = -t;
        if(t >= 10) write(t / 10);
        putchar(t % 10 + '0');
    }
    template<typename T, typename ... Args> void write(T t, Args... args){
        write(t), putchar(' '), write(args...);
    }
    template<typename T> void writeln(T t){
        write(t);
        puts("");
    }
    template<typename T> void writes(T t){
        write(t), putchar(' ');
    }
    #undef get
};
using namespace fastio;
#define multitest() int T; read(T); _rep(tCase, 1, T)
namespace Calculation{
    const ll mod = 998244353;
    ll ksm(ll p, ll h){ll base = p % mod, res = 1; while(h){if(h & 1ll) res = res * base % mod; base = base * base % mod, h >>= 1ll;} return res;}
    void dec(ll &x, ll y){x = ((x - y) % mod + mod) % mod;}
    void add(ll &x, ll y){x = (x + y) % mod;}
    void mul(ll &x, ll y){x = x * y % mod;}
    ll sub(ll x, ll y){return ((x - y) % mod + mod) % mod;}
    ll pls(ll x, ll y){return ((x + y) % mod + mod) % mod;}
    ll mult(ll x, ll y){return x * y % mod;}
}
using namespace Calculation;
const int N = 1e5 + 5, B = 20;
int n, k, q, dep[N], pre[N], siz[N];
vector<int> G[N];
int id, dfn[N], rev[N], L[N][B + 5], R[N][B + 5];
void dfs(int u, int fa){
    dep[u] = dep[fa] + 1, siz[u] = 1, pre[u] = fa;
    for(auto &v : G[u]) if(v != fa) dfs(v, u);
}
void bfs(int s){
    queue<int> q; q.push(s);
    while(q.size()){
        int u = q.front(); q.pop();
        rev[dfn[u] = ++id] = u;
        for(auto &v : G[u]) if(v != pre[u]) q.push(v);
    }
    _rep(i, 1, n){
        int u = i;
        _rep(j, 0, 20){
            L[u][j] = !L[u][j] ? dfn[i] : min(L[u][j], dfn[i]);
            R[u][j] = !R[u][j] ? dfn[i] : max(R[u][j], dfn[i]);
            u = pre[u];
        }
    }
}
namespace bit{
    int c[N];
    void add(int x, int val){for(; x <= n; x += x & -x) c[x] += val;}
    int ask(int x){int res = 0; for(; x; x -= x & -x) res += c[x]; return res;}
}
vector<PII> h[N];
struct node{
    int l, r, v;
    bool operator<(const node b)const{return r < b.r;}
};
set<node> st;
int col[N];
void modify(int l, int r, int val){
    // debug("modify [%d,%d] val:%d\n", l, r, val);
    _rep(i, l, r){
        if(col[i]) bit::add(n - col[i] + 1, -1);
        col[i] = val;
        bit::add(n - col[i] + 1, 1);
    }
    // auto lit = st.lower_bound(make_pair(l + 1, 0)), rit = st.lower_bound(make_pair(r, 0));
}
void work(int u){
    // debug("work %d\n", u);
    int id = u, cur = 0;
    while(u && cur <= k){
        // debug("u:%d cur:%d [%d,%d]\n", u, cur, L[u][k - cur], R[u][k - cur]);
        if(L[u][k - cur]) modify(L[u][k - cur], R[u][k - cur], id);
        if(k > cur && L[u][k - cur - 1]) modify(L[u][k - cur - 1], R[u][k - cur - 1], id);
        if(u == 1 && cur < k){
            _rep(i, 0, k - cur - 2) if(L[u][i]){
                modify(L[u][i], R[u][i], id);
            }
        }
        u = pre[u], cur++;
    }
    // debug("==============\n");
}
int ans[N];
void clr(){
    _rep(i, 1, n){
        pre[i] = dep[i] = siz[i] = dfn[i] = rev[i] = col[i] = 0;
        h[i].clear(), G[i].clear();
        mst(L[i], 0), mst(R[i], 0);
        bit::c[i] = 0;
    }
    _rep(i, 1, q) ans[i] = 0;
    st.clear();
}
int main(){
    multitest(){
        read(n, k, q);
        _rep(i, 2, n){
            int u, v; read(u, v);
            G[u].pb(v), G[v].pb(u);
        }
        _rep(i, 1, q){
            int l, r; read(l, r);
            h[r].pb({l, i});
        }
        dfs(1, 0), bfs(1);
        _rep(i, 1, n){
            work(i);
            for(auto &[l, id] : h[i]){
                ans[id] = bit::ask(n - l + 1);
            }
        }
        _rep(i, 1, q) writeln(ans[i]);
        clr();
    }
    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 1ms
memory: 7732kb

input:

2
5 1 2
1 2
1 3
2 4
2 5
2 2
2 3
8 2 3
1 2
1 3
2 4
2 5
4 6
5 7
7 8
2 2
2 5
3 4

output:

4
5
7
8
6

result:

ok 5 number(s): "4 5 7 8 6"

Test #2:

score: -100
Time Limit Exceeded

input:

1000
500 1 500
291 2
406 9
207 13
71 15
351 17
442 18
496 19
104 20
208 23
448 34
80 42
187 44
352 45
290 46
116 47
318 50
226 52
129 55
83 59
100 60
54 61
73 65
63 66
454 67
43 71
26 74
68 26
320 75
388 76
425 79
170 81
350 83
48 85
153 86
221 90
290 95
130 96
82 98
124 82
36 99
213 100
121 101
132...

output:

255
386
356
124
315
330
437
8
335
423
398
338
180
242
352
500
145
44
342
261
92
326
38
291
259
71
137
456
171
24
162
453
283
325
250
319
478
460
77
354
56
393
372
217
395
265
188
256
134
68
205
429
436
346
300
462
324
170
291
406
207
480
198
182
489
61
476
127
289
204
282
374
114
406
488
366
121
190...

result: