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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#643086#7627. PhonyhhdhhWA 0ms13980kbC++234.4kb2024-10-15 18:40:542024-10-15 18:40:55

Judging History

你现在查看的是最新测评结果

  • [2024-10-15 18:40:55]
  • 评测
  • 测评结果:WA
  • 用时:0ms
  • 内存:13980kb
  • [2024-10-15 18:40:54]
  • 提交

answer

#include<bits/stdc++.h>

#include <ext/pb_ds/assoc_container.hpp>  
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
// #define endl '\n'
#define rep(i, a, b) for(LL i = (a); i <= (b); i++)
#define per(i, a, b) for(LL i = (a); i >= (b); i--)
#define rept(i, a, ne) for(LL i = (a); ~i ; i=ne[i])
#define debug(x) cout<<#x<<": "<<x<<endl
#define fi first
#define sec second
mt19937_64 rnd(chrono::steady_clock::now().time_since_epoch().count());
typedef long long LL;
typedef long double  LD;
typedef unsigned long long ULL;
typedef vector<LL> VI;
typedef pair<LL,LL>PII;
const LL N=1e6+10;
LL a[N];
vector<LL>ve[N];
LL b[N];
LL c[N];
LL d[N];
void add(LL x,LL s)//不能0开始
{
    x++;
    for(;x<N;x+=x&-x)
        c[x]+=s;
}
LL ask(LL x)
{
    x++;
    LL su=0;
    for(;x;x-=x&-x)
        su+=c[x];
    return su;
}
LL kth(LL s)//kth(k)
{
    s--;
    LL x=0;

    per(i,20,0)
    if(x+(1<<i)<N&&c[x+(1<<i)]<=s)
    x+=(1<<i),s-=c[x];//注意顺序
        
    return x;
}
void slove()
{
    LL n,m,k;
    cin>>n>>m>>k;
    map<LL,LL,greater<LL>>s1,s2;
    rep(i,1,n)
    {
        cin>>a[i];
        s1[a[i]/k]=0;
        s2[a[i]%k]=0;
    }
    sort(a+1,a+1+n,greater<LL>());
    LL n1=0;
    LL n2=0;
    for(auto &[x,y]:s1)
    {
        b[++n1]=x;
        y=n1;
    }
    b[++n1]=-1e18;
    for(auto &[x,y]:s2)
    {
        d[++n2]=x;
        y=n2;
    }
    rep(i,1,n)
    {
        LL x=s1[a[i]/k],y=s2[a[i]%k];
        ve[x].push_back(y);

    } 
    rep(i,1,n1-1)
    sort(ve[i].begin(),ve[i].end(),greater<LL>());   
    LL sum=0;
    LL np=0;
    b[0]=b[1];
    LL p=0;

    rep(i,1,m)
    {
        // debug(i);
        char c;
        cin>>c;
        if(c=='A')
        {
            LL x;
            cin>>x;
            if(x<=sum-p)
            {
                LL ans=d[kth(x+p)]+b[np]*k;
                cout<<ans<<endl;
            }
            else
            {
                if(x>sum)
                {
                    if(b[np+1]+1==b[np]&&ve[np+1].size()+sum>=x)
                    {
                        x-=sum;
                        x=(LL)ve[np+1].size()-x;
                        cout<<d[ve[np+1][x]]+(b[np]-1)*k<<endl;
                    }
                    else
                    {
                        cout<<a[x]<<endl;
                    }     
                }
                else
                {
                    x-=sum-p;
                    // debug(x);
                    // debug(d[kth(p)]);
                    LL ans=d[kth(p)]+(b[np]-1)*k;
                    cout<<ans<<endl;
                }
            }
        }
        else
        {
            LL x;
            cin>>x;
            while(x)
            {
                // debug(b[np]);
                // debug(x);
                if(p==0)
                {
                    LL o=sum?x/sum:0;
                    x-=min(b[np]-b[np+1],o)*sum;
                    b[np]-=min(b[np]-b[np+1],o);
                    
                    if(b[np]==b[np+1])
                    {
                        ++np;
                        sum+=ve[np].size();
                        for(auto x:ve[np])
                        add(x,1);
                    }
                }
                LL o=sum-p;
                p+=min(o,x);
                x-=min(o,x);
                if(p==sum)
                {
                    b[np]--;
                    p=0;
                }
            }
            if(b[np]==b[np+1]+1)
            {
                LL o=kth(p);
                while(ve[np+1].size())
                { 
                    if(ve[np+1].back()<=o)
                    {
                        sum++;
                        p++;
                        add(ve[np+1].back(),1);  
                        ve[np+1].pop_back();
                    }
                    else 
                    break;
                }
            }
            // debug(p);
            // debug(sum);
            // debug(np);
            // debug(b[np]);
            // cout<<endl;
        }
    }
}

int main()
{
    ios::sync_with_stdio(0);
    cin.tie(0);
//	cout << fixed << setprecision(9);
    LL t=1;
//	cin>>t;
    while(t--)
    {
        slove();
    }


    return 0;
}
//#pragma GCC optimize(2)

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 13980kb

input:

3 5 5
7 3 9
A 3
C 1
A 2
C 2
A 3

output:

3
4
-1

result:

ok 3 lines

Test #2:

score: -100
Wrong Answer
time: 0ms
memory: 13892kb

input:

5 8 8
294 928 293 392 719
A 4
C 200
A 5
C 10
A 2
C 120
A 1
A 3

output:

294
200
184
0
-8

result:

wrong answer 3rd lines differ - expected: '191', found: '184'