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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#642973#6366. Messageyzc358230151WA 3ms99584kbC++142.6kb2024-10-15 17:26:162024-10-15 17:26:18

Judging History

你现在查看的是最新测评结果

  • [2024-10-15 17:26:18]
  • 评测
  • 测评结果:WA
  • 用时:3ms
  • 内存:99584kb
  • [2024-10-15 17:26:16]
  • 提交

answer

/*
	(E)原神https://qoj.ac/download.php?type=attachments&id=1213&r=0
	https://qoj.ac/contest/1213/problem/6366
*/
#include<bits/stdc++.h>
using namespace std;
#define gc getchar
#define pc putchar
#define mkp make_pair
#define pb push_back
typedef long long ll;
char s[200010],t[200010];
int ls,lt;
int w[200010];
bool hd[200010];//段首标记
ll smw[200010];
ll dp[60][200010];int dpcnt;
int fst[26],lst[26];
int L=1,R;
int occ[200010],occcnt;
namespace kmp{
	int nxt[200010];
	char *r;
	void kmp(){
		int le=R-L+1;
		occcnt=0,
		r=t+L-1;
		for(int i=1;i<=le;++i)
			nxt[i]=0;
		nxt[0]=-1,
		nxt[1]=0;
		int j=0;
		for(int i=2;i<=le;++i){
			while((~j)&&r[j+1]!=r[i])
				j=nxt[j];
			nxt[i]=++j;
		}
		j=0;
		for(int i=1;i<=ls;++i){
			while((~j)&&r[j+1]!=s[i])
				j=nxt[j];
			++j;
			if(j==le)
				occ[++occcnt]=i-le+1,
				j=nxt[j];
		}
	}
}
void mkdp(){
	++dpcnt,kmp::kmp();
	int len=R-L+1;
	// printf("doing #%d dp,with area [%d,%d]\n",
	// dpcnt,L,R);
	// printf("occurs:\n");
	// for(int i=1;i<=occcnt;++i)
	// 	printf("[%d,%d],",occ[i],occ[i]+len-1);
	// printf("\n");
	ll mxfr=-1;int pt=1;
	for(int i=1;i<=occcnt;++i){
		// for(;pt<occ[i];++pt)
		// if(L<=fst[s[pt]-'a']||L>lst[s[pt]-'a'])
		// 	printf("maxxed mxfr at pt=%d\n",pt),
		// 	mxfr=max(mxfr,dp[dpcnt-1][pt]);
		// else
		// 	printf("banned mxfr at pt=%d\n",pt),
		// 	mxfr=-1;
		for(;pt<occ[i];++pt)
		if(L<=fst[s[pt]-'a']||L>lst[s[pt]-'a'])
			// printf("maxxed mxfr at pt=%d\n",pt),
			mxfr=max(mxfr,dp[dpcnt-1][pt-1]);
		else
			// printf("banned mxfr at pt=%d\n",pt),
			mxfr=-1;
		mxfr=max(mxfr,dp[dpcnt-1][occ[i]-1]);
		if(~mxfr)
			dp[dpcnt][occ[i]+len-1]=mxfr
			+smw[occ[i]+len-1]-smw[occ[i]-1];
	}
	for(int i=2;i<=ls;++i)
	if(R+1<=fst[s[i]-'a']||R+1>lst[s[i]-'a'])
		dp[dpcnt][i]=
		max(dp[dpcnt][i],dp[dpcnt][i-1]);
}
signed main(){
	scanf("%s%s",s+1,t+1),
	ls=strlen(s+1),
	lt=strlen(t+1);
	for(int i=1;i<=ls;++i)
		scanf("%d",&w[i]),
		smw[i]=smw[i-1]+w[i];
	for(int i=1;i<=lt;++i){
		if(!fst[t[i]-'a'])
			fst[t[i]-'a']=i;
		lst[t[i]-'a']=i;
	}
	memset(dp,~0x3f,sizeof(dp));
	for(int i=0;i<26;++i)
		// printf("'%c' is [%d,%d]",
		// i+'a',fst[i],lst[i]),
		hd[fst[i]]=hd[lst[i]+1]=1;
	hd[lt+1]=1,dp[0][0]=0;
	for(R=1;R<=lt;++R)
	if(hd[R+1])
		mkdp(),
		L=R+1;
	if(dp[dpcnt][ls]>=0)
		printf("%lld",smw[ls]-dp[dpcnt][ls]);
	else
		fputs("-1\n",stdout);
	return 0;
}
/*
必须连续匹配的串。
具体地,新出现的字符在其前划分,其作为段首;
最后的字符在其后划分,其作为段尾。
注意某些字符不能跳过。
*/

Details

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Test #1:

score: 100
Accepted
time: 3ms
memory: 99584kb

input:

ababccb
abc
7 2 2 4 3 2 1

output:

7

result:

ok single line: '7'

Test #2:

score: -100
Wrong Answer
time: 0ms
memory: 99444kb

input:

babab
baab
2 1 3 2 4

output:

-1

result:

wrong answer 1st lines differ - expected: 'You better start from scratch man...', found: '-1'