QOJ.ac

QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#642700#9434. Italian CuisineAndevikingWA 0ms3828kbC++201.7kb2024-10-15 15:50:272024-10-15 15:50:28

Judging History

你现在查看的是最新测评结果

  • [2024-10-15 15:50:28]
  • 评测
  • 测评结果:WA
  • 用时:0ms
  • 内存:3828kb
  • [2024-10-15 15:50:27]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
#define range(x) (x).begin(), (x).end()
const int dir[][2] = {1, 0, -1, 0, 0, 1, 0, -1};
const __int128_t tag = 1;
#define int long long
struct Point {
    ll x, y;
    Point(ll x, ll y)
        : x(x), y(y)
    {
    }
    Point()
    {
        x = 0, y = 0;
    }

    Point operator-(const Point &b)
    {
        return Point(x - b.x, y - b.y);
    }
};
ll cross(Point a, Point b)
{
    return a.x * b.y - a.y * b.x;
}

ll dst2(Point a, Point b)
{
    return (a.x - b.x) * (a.x - b.x) + (a.y - b.y) * (a.y - b.y);
}
void solve()
{
    int n;
    cin >> n;
    int cx, cy, cr;
    cin >> cx >> cy >> cr;
    Point C(cx, cy);
    vector<Point> v(n);
    for (auto &[x, y] : v) {
        cin >> x >> y;
    }
    // reverse(range(v));

    for (int i = 0; i < n; ++i)
        v.push_back(v[i]);

    ll sum = 0;
    int r = 0;
    ll mx = 0;
    for (int i = 0; i < n; ++i) {
        if (r <= i) {
            r = i + 1;
            sum = -cross(v[r], v[i]);
        }
        Point CX(v[i] - C);
        Point CY(v[r + 1] - C);
        // cout << i << ' ' << r + 1 << ' ' << cross(CX, CY) << '\n';
        while (cross(CX, CY) > 0 && tag * cross(CX, CY) * cross(CX, CY) > tag * cr * cr * dst2(v[i], v[r])) {
            r++;
            CX = Point(v[i] - C);
            CY = Point(v[r + 1] - C);
            sum -= cross(v[r], v[r - 1]);
        }

        // cout << i << ' ' << r << ' ' << sum << '\n';
        mx = max(mx, sum - cross(v[i], v[r]));
        sum += cross(v[i + 1], v[i]);
    }

    cout << mx << '\n';
}

signed main()
{
    ios::sync_with_stdio(false);
    cin.tie(0);
    cout.tie(0);

    int t = 1;
    cin >> t;
    while (t--)
        solve();
    return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 0ms
memory: 3576kb

input:

3
5
1 1 1
0 0
1 0
5 0
3 3
0 5
6
2 4 1
2 0
4 0
6 3
4 6
2 6
0 3
4
3 3 1
3 0
6 3
3 6
0 3

output:

5
24
0

result:

ok 3 number(s): "5 24 0"

Test #2:

score: -100
Wrong Answer
time: 0ms
memory: 3828kb

input:

1
6
0 0 499999993
197878055 -535013568
696616963 -535013568
696616963 40162440
696616963 499999993
-499999993 499999993
-499999993 -535013568

output:

550249412925348668

result:

wrong answer 1st numbers differ - expected: '0', found: '550249412925348668'