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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#642508#8577. 평균 최대화user100860 0ms0kbC++177.1kb2024-10-15 14:40:492024-10-15 14:40:49

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  • [2024-10-15 14:40:49]
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  • 测评结果:0
  • 用时:0ms
  • 内存:0kb
  • [2024-10-15 14:40:49]
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answer

#include <bits/stdc++.h>

using namespace std;

#define int long long

const int N = 3e5 + 10, inf = 1e13;

int n, idx, l[N], r[N], a[N], s[N], rx[N], rs[N];

//#define __int128 int

struct F
{
	__int128 i, j;
	
	F()
	{
		i = j = 0;
	}
	
	F(__int128 a, __int128 b)
	{
		__int128 d = __gcd(a, b);
		i = a / d, j = b / d;
	}
	
	bool operator> (const F& f2) const
	{
		return i * f2.j > j * f2.i;
	}
	
	bool operator< (const F& f2) const
	{
		return i * f2.j < j * f2.i;
	}
	
	F operator + (const F& f2) const
	{
		__int128 a = i * f2.j + j * f2.i, b = j * f2.j;
		return {a, b};
	}
	
	void reduce()
	{
		auto d = __gcd(i, j);
		i /= d, j /= d;
	}
	
}ans[N];

namespace Tree
{
	mt19937 rng(20241015);
	
	const int R = 30;
	int idx;
	int ls[N * R], rs[N * R], sz[N * R];
	F tass[N * R];
	F val[N * R], sum[N * R];
	
	void init()
	{
		val[0] = sum[0] = {0, 1};
	}
	
	int newnode(F v)
	{
		idx++;
		assert(idx < N * R);
		ls[idx] = rs[idx] = 0, sz[idx] = 1, tass[idx] = {0, 1};
		val[idx] = sum[idx] = v;
		return idx;
	}
	
	void pushup(int u)
	{
		if (!u) return;
		sum[u] = sum[ls[u]] + val[u] + sum[rs[u]];
		sz[u] = sz[ls[u]] + 1 + sz[rs[u]];
	}
	
	void apply(int u, F dass)
	{
		if (!u) return;
		sum[u] = {dass.i * sz[u], dass.j}, sum[u].reduce(), val[u] = dass;
		tass[u] = dass;
	}
	
	void pushdown(int u)
	{
		if (!u) return;
		if (tass[u].i == 0) return;
		apply(ls[u], tass[u]), apply(rs[u], tass[u]);
		tass[u] = {0, 1};
	}
	
	array<int, 2> splitr(int u, int k)
	{
		// [1, k], [k+1, inf)
//		printf("splitr(%lld, %lld)\n", u, k);
		if (!u) return {0, 0};
		pushdown(u);
		if (sz[ls[u]] >= k)
		{
			auto res = splitr(ls[u], k);
			ls[u] = res[1];
			pushup(u);
			return {res[0], u};
		}
		else
		{
			auto res = splitr(rs[u], k - sz[ls[u]] - 1);
			rs[u] = res[0];
			pushup(u);
//			printf("&&&");
			return {u, res[1]};
		}
	}
	
	array<int, 2> splitv(int u, F v)
	{
		// [1, v] [v, inf)
		if (!u) return {0, 0};
		pushdown(u);
		if (v > val[u])
		{
			auto res = splitv(ls[u], v);
			ls[u] = res[1];
			pushup(u);
			return {res[0], u};
		}
		else
		{
			auto res = splitv(rs[u], v);
			rs[u] = res[0];
			pushup(u);
			return {u, res[1]};
		}
	}
	
	int merge(int l, int r)
	{
//		printf("merge(%lld, %lld)\n", l, r);
		if (!l) swap(l, r);
		if (!r) return l;
		
		pushdown(l), pushdown(r);
		if (rng() % (sz[l] + sz[r]) < sz[l])
		{
			rs[l] = merge(rs[l], r);
			pushup(l);
			return l;
		}
		else
		{
			ls[r] = merge(l, ls[r]);
			pushup(r);
			return r;
		}
	}
	
	void insert(int& rt, F v)
	{
		auto res = splitv(rt, v);
		int c = newnode(v);
		rt = merge(merge(res[0], c), res[1]);
	}
	
	void assign(int& rt, int pos, F v)
	{
		auto res = splitr(rt, pos);
		apply(res[0], v);
		rt = merge(res[0], res[1]);
	}
	
	F qsum(int& rt, int pos)
	{
		auto res = splitr(rt, pos);
//		printf("qsum(%lld, %lld)\n", rt, pos);
		F ret = sum[res[0]];
		rt = merge(res[0], res[1]);
		return ret;
	}
	
	void print(int rt)
	{
		if (!rt) return;
		print(ls[rt]), printf("node %lld: sum = %lld/%lld, val = %lld/%lld, tass = %lld/%lld, ls = %lld, rs = %lld\n", rt, sum[rt].i, sum[rt].j, val[rt].i, val[rt].j, tass[rt].i, tass[rt].j, ls[rt], rs[rt]), print(rs[rt]);
	}
}

int dp[N];
vector<int> son[N];
vector<int> rg[N];
map<array<int, 2>, int> mp;

int build(int l, int r)
{
	idx++, ::l[idx] = l, ::r[idx] = r, mp[{l, r}] = idx;
	int x = idx; rx[x] = r - l + 1, rs[x] = s[r] - s[l - 1];
	for (int i = l; i <= r; i++)
	{
		if (rg[i].empty()) continue;
		int j = rg[i].back(); rg[i].pop_back();
		int y = build(i, j);
		son[x].push_back(y);
		rx[x] -= (j - i + 1), rs[x] -= (s[j] - s[i - 1]);
		i = j;
	}
	return x;
}

template<class T>
void chkmax(T &x, T y)
{
	if (y > x) x = y;
}

int merge(int& a, int& b)
{
//	printf("merge(%lld, %lld)\n", a, b);
	if (Tree::sz[a] < Tree::sz[b]) swap(a, b);
	if (!b) return a;
	Tree::pushdown(b);
	Tree::insert(a, Tree::val[b]);
	merge(a, Tree::ls[b]), merge(a, Tree::rs[b]);
	return a;
}

pair<int, F> getp(int& rt, int a, int b)
{
	// max (y - b) / (x - a)
	int l = 0, r = Tree::sz[rt];
	auto getres = [&](int x)
	{
		F y1 = Tree::qsum(rt, x);
		y1.i -= b * y1.j, y1.j *= (x - a);
//		y1.reduce();
		return y1;
	};
	while (l + 1 < r)
	{
		int mid1 = l + (r - l + 1) / 3, mid2 = r - (r - l) / 3;
		F y1 = getres(mid1), y2 = getres(mid2);
		if (y1 < y2) l = mid1 + 1;
		else r = mid2;
	}
//	printf(")))"), Tree::print(rt);
//	printf("res(l) = (%lld, %lld/%lld), res(r) = (%lld, %lld/%lld)\n", l, getres(l).i, getres(l).j, r, getres(r).i, getres(r).j);
	auto resl = getres(l), resr = getres(r);
	resl.reduce(), resr.reduce();
	if (resl > resr) return {l, resl};
	else return {r, resr};
}

void dfs(int x)
{
//	printf("dfs(%lld)\n", x);
	dp[x] = 0;
	if (son[x].empty()) for (int i = 1; i <= rx[x]; i++) Tree::insert(dp[x], {rs[x], rx[x]});
	else 
	{
		for (int y : son[x]) dfs(y), dp[x] = merge(dp[x], dp[y]);
//		Tree::print(dp[x]);
//		 (-rx[x], -rs[x])
		auto res = getp(dp[x], -rx[x], -rs[x]);
//		printf("proc: res = {%lld, %lld/%lld}\n", res.first, res.second.i, res.second.j);
		int p = res.first;
		F v = res.second;
		Tree::assign(dp[x], p, v);
		for (int i = 1; i <= rx[x]; i++) Tree::insert(dp[x], v);
	}
//	Tree::print(dp[x]);
//	cout << "***";
	auto res = getp(dp[x], -2, -(a[l[x] - 1] + a[r[x] + 1]));
	ans[x] = res.second;
//	printf("%lld: (%lld, %lld/%lld)\n", x, res.first, ans[x].i, ans[x].j);
}

void initialize(vector<signed> A)
{
    n = (int)(A.size());
    for (int i = 1; i <= n; i++) a[i] = A[i - 1];
	for (int i = 1; i <= n; i++) s[i] = a[i] + s[i - 1];
    vector<int> s;
    for (int i = n; i >= 1; i--)
    {
    	while (!s.empty() && a[s.back()] > a[i])
    	{
    		int x = s.back(); s.pop_back();
    		if (x != i + 1) rg[i + 1].push_back(x - 1);
    	}
    	if (!s.empty() && s.back() != i + 1) rg[i + 1].push_back(s.back() - 1); 
    	if (!s.empty() && a[s.back()] >= a[i]) s.pop_back();
    	s.push_back(i);
    }
//	for (int i = 1; i <= n; i++)
//		for (int j : rg[i]) printf("[%lld, %lld]\n", i, j);
    
    build(2, n - 1);
//    for (int i = 1; i <= n; i++)
//    	printf("rx[%lld] = %lld, rs[%lld] = %lld\n", i, rx[i], i, rs[i]);
    Tree::init();
    dfs(1);
    
//    for (int i = 1; i <= n; i++)
//    	for (int j = 0; j <= sz[i]; j++)
//    		printf("dp[%lld][%lld] = %lld\n", i, j, dp[i][j]);
    
//    for (int i = 1; i <= n; i++)
//    	for (int j : son[i]) printf("[%lld, %lld] -> [%lld, %lld]\n", l[i], r[i], l[j], r[j]);
}

array<long long, 2> maximum_average(signed i, signed j)
{
	i++, j++;
	if (j == i + 1) return {a[i] + a[j], 2};
	assert(mp.find({i + 1, j - 1}) != mp.end());
	int id = mp[{i + 1, j - 1}];
	return {ans[id].i, ans[id].j};
}

//signed main()
//{
//	int n; cin >> n;
//	vector<signed> A;
//	for (int i = 1, ai; i <= n; i++) cin >> ai, A.push_back(ai); 
//	initialize(A);
//	while (1)
//	{
//		int l, r; cin >> l >> r;
//		auto res = maximum_average(l, r);
//		cout << res[0] << ' ' << res[1] << endl;
//	}
//}

詳細信息

Subtask #1:

score: 0
Time Limit Exceeded

Test #1:

score: 0
Time Limit Exceeded

input:

10
2 4 3 9 9 9 9 9 9 1
2
0 2
0 9

output:

Unauthorized output

result:


Subtask #2:

score: 0
Skipped

Dependency #1:

0%

Subtask #3:

score: 0
Skipped

Dependency #2:

0%

Subtask #4:

score: 0
Time Limit Exceeded

Test #15:

score: 0
Time Limit Exceeded

input:

300000
1 2 4 4 4 4 3 2 4 4 3 4 4 4 4 4 4 4 4 4 3 4 3 4 4 4 4 4 4 4 4 3 3 4 4 4 3 4 3 4 4 4 4 4 4 4 4 4 4 3 3 4 4 4 3 4 4 3 4 4 4 4 4 4 4 3 2 4 4 4 4 4 4 4 4 4 4 4 4 4 3 4 4 4 4 4 4 4 4 4 4 4 2 4 4 2 4 4 3 4 4 4 2 3 4 4 4 4 4 4 3 2 4 4 4 2 4 4 4 4 4 4 4 4 4 4 4 2 4 4 4 4 4 4 3 4 4 3 4 4 4 4 4 4 4 4 4...

output:

Unauthorized output

result:


Subtask #5:

score: 0
Skipped

Dependency #3:

0%

Subtask #6:

score: 0
Time Limit Exceeded

Test #28:

score: 0
Time Limit Exceeded

input:

300000
1 300000 300001 299999 300003 299998 300005 299997 300007 299996 300009 299995 300011 299994 300013 299993 300015 299992 300017 299991 300019 299990 300021 299989 300023 299988 300025 299987 300027 299986 300029 299985 300031 299984 300033 299983 300035 299982 300037 299981 300039 299980 3000...

output:

Unauthorized output

result:


Subtask #7:

score: 0
Skipped

Dependency #4:

0%

Subtask #8:

score: 0
Skipped

Dependency #1:

0%