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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#642143 | #8551. DFS Order 5 | youthpaul | WA | 34ms | 3856kb | C++20 | 3.6kb | 2024-10-15 10:52:36 | 2024-10-15 10:52:37 |
Judging History
answer
#include<bits/stdc++.h>
#define fore(i,l,r) for(int i=(int)(l);i<(int)(r);++i)
#define fi first
#define se second
#define endl '\n'
#define ull unsigned long long
#define ALL(v) v.begin(), v.end()
#define Debug(x, ed) std::cerr << #x << " = " << x << ed;
const int INF=0x3f3f3f3f;
const long long INFLL=1e18;
typedef long long ll;
template <typename T>
struct Fenwick {
int n;
std::vector<T> a;
Fenwick(int n_ = 0) {
init(n_);
}
void init(int n_) {
n = n_;
a.assign(n + 5, T{});
}
void update(int p, const T &v) { //在位置 p 加 v
while(p <= n){
a[p] += v;
p += p & -p;
}
}
T query(int p) {
T ans{};
while(p > 0){
ans += a[p];
p -= p & -p;
}
return ans;
}
T rangeSum(int l, int r) {
return query(r) - query(l - 1); //前缀和
}
int find_first(T sum){ //找到第一个 query(p) >= sum 的位置 p
int p = 0;
T val = 0;
for(int i = std::__lg(n); i >= 0; --i)
if((p | 1 << i) <= n && val + a[p | 1 << i] < sum){
p |= 1 << i;
val += a[p];
}
return p + 1;
}
int find_last(T sum){ //找到最后一个 query(p) <= sum 的位置 p
int p = 0;
T val = 0;
for(int i = std::__lg(n); i >= 0; --i)
if((p | 1 << i) <= n && val + a[p | 1 << i] <= sum){
p |= 1 << i;
val += a[p];
}
return p;
}
};
const int N = 100005;
const int K = 17;
std::vector<int> g[N];
int f[N][K + 1];
int h[N];
int dfn[N];
int up[N];
int tot;
int sz[N];
void dfs0(int u, int fa){
h[u] = h[fa] + 1;
f[u][0] = fa;
dfn[u] = ++tot;
sz[u] = 1;
for(int k = 1; (1 << k) <= h[u]; ++k)
f[u][k] = f[f[u][k - 1]][k - 1];
for(auto v : g[u])
if(v != fa){
dfs0(v, u);
sz[u] += sz[v];
}
up[u] = tot;
}
int lca(int u, int v){
if(h[u] < h[v]) std::swap(u, v);
for(int k = K; k >= 0; --k)
if(h[u] - (1 << k) >= h[v])
u = f[u][k];
if(u == v) return u;
for(int k = K; k >= 0; --k)
if(f[u][k] != f[v][k]){
u = f[u][k];
v = f[v][k];
}
return f[u][0];
}
int main(){
std::ios::sync_with_stdio(false);
std::cin.tie(nullptr);
std::cout.tie(nullptr);
int n, q;
std::cin >> n >> q;
fore(i, 1, n){
int u, v;
std::cin >> u >> v;
g[u].push_back(v);
g[v].push_back(u);
}
dfs0(1, 0);
Fenwick<int> fen(n);
while(q--){
int m;
std::cin >> m;
std::vector<int> a(m);
fore(i, 0, m) std::cin >> a[i];
std::vector<int> p;
auto check = [&]() -> bool {
if(m == 1) return true;
p.push_back(dfn[a[0]]);
fen.update(dfn[a[0]], 1);
if(a[0] != 1){
p.push_back(1);
fen.update(1, 1);
}
fore(i, 1, m){
int u = a[i - 1], w = a[i];
if(fen.rangeSum(dfn[w], up[w])) return false;
if(f[w][0] == u){
fen.update(dfn[w], 1);
p.push_back(dfn[w]);
continue;
}
if(fen.rangeSum(dfn[u], up[u]) != sz[u]) return false;
if(lca(u, f[w][0]) == f[w][0] && lca(u, w) != w){
fen.update(dfn[w], 1);
p.push_back(dfn[w]);
continue;
}
return false;
}
return true;
};
std::cout << (check() ? "Yes" : "No") << endl;
for(auto x : p) fen.update(x, -1);
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 1ms
memory: 3568kb
input:
6 7 1 2 1 3 2 4 3 5 2 6 2 4 1 2 4 2 2 4 3 2 4 4 2 4 5 2 4 6 6 1 2 6 4 3 5
output:
No No Yes No No Yes Yes
result:
ok 7 tokens
Test #2:
score: -100
Wrong Answer
time: 34ms
memory: 3856kb
input:
10 100000 7 2 1 7 7 10 8 6 8 7 1 3 4 5 9 5 5 8 8 8 9 7 2 8 1 6 1 4 8 3 5 2 6 7 10 3 9 9 1 1 1 8 10 3 2 9 3 8 7 3 7 5 6 2 8 5 9 1 6 3 4 6 2 1 3 5 8 9 2 4 9 1 3 2 1 5 5 8 5 1 7 9 10 5 2 9 2 6 4 10 6 3 8 3 4 5 8 2 8 4 9 4 10 1 2 4 3 3 6 3 1 3 6 1 1 6 8 3 1 3 7 3 2 3 9 1 5 4 3 7 8 10 9 4 2 3 10 2 5 4 3 ...
output:
No No No Yes No No No No Yes No No No No No No Yes No No No No No No No No No No No No No No No Yes No No No No No No Yes No No No No No Yes Yes No No No No No No No No No No No No No No No No No No No No No No No No Yes No No Yes Yes No No No No Yes No No No No No No No No No No No No No No No No N...
result:
wrong answer 899th words differ - expected: 'No', found: 'Yes'