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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#641304 | #8720. BFS 序 0 | neetman | WA | 100ms | 37844kb | C++14 | 2.9kb | 2024-10-14 19:44:12 | 2024-10-14 19:44:13 |
Judging History
answer
#include<algorithm>
#include<iostream>
#include<cstdio>
using namespace std;
const int N = 3e5 + 5;
int n, m, q, tot, top;
int fa[N][20], head[N], dep[N], idx[N];
int vis[N], sta[N*2], maxn[N];
struct edge{
int u, v;
}e[N];
int cnt;
void addedge(int x, int y){
e[++cnt].u = head[x];
e[cnt].v = y;
head[x] = cnt;
}
void dfs(int x){
for(int i = 1; fa[x][i] = fa[fa[x][i-1]][i-1]; i ++);
for(int i = head[x]; i; i = e[i].u){
int to = e[i].v;
dep[to] = dep[x] + 1;
dfs(to);
}
idx[x] = ++tot;
}
int lca(int x, int y){
if(dep[x] != dep[y]){
if(dep[x] < dep[y]) swap(x, y);
for(int i = 19; ~i; i --){
if(dep[fa[x][i]] >= dep[y])
x = fa[x][i];
}
}
if(x == y) return x;
for(int i = 19; ~i; i --)
if(fa[x][i] != fa[y][i]){
x = fa[x][i];
y = fa[y][i];
}
return fa[x][0];
}
int main(){
ios::sync_with_stdio(0),cin.tie(0);
cin >> n;
for(int i = 2; i <= n; i ++){
cin >> fa[i][0];
addedge(fa[i][0], i);
}
dep[1] = 1;
dfs(1);
cin >> q;
bool jud;
while(q --){
cin >> m; jud = 1;
for(int i = 1; i <= m; i ++){
cin >> sta[i];
maxn[sta[i]] = dep[sta[i]];
}
top = m;
// cout << "q = " << q << " jud = " << jud << '\n';
for(int i = m - 1; i; i --){
int LCA = lca(sta[i], sta[top]);
// cout << "TEST!! " << sta[i] << " " << sta[top] << " " << maxn[sta[i]] << " " << maxn[sta[top]] << '\n';
if(LCA == sta[i]){
sta[++top] = sta[i];
continue;
}
if(LCA == sta[top]){
if(maxn[sta[top]] < maxn[sta[i]])
jud = 0;
maxn[sta[top]] = maxn[sta[i]];
}
else{
if(maxn[sta[top]] < maxn[sta[i]])
jud = 0;
sta[++top] = LCA;
maxn[sta[top]] = maxn[sta[i]];
}
}
if(jud) cout << "Yes\n";
else cout << "No\n";
for(int i = 1; i <= top; i ++)
maxn[sta[i]] = vis[sta[i]] = 0;
// sort(sta + 1, sta + 1 + m, [](int x, int y){
// return idx[x] < idx[y];
// });
// siz = m;
// for(int i = 1; i < m; i ++){
// int LCA = lca(sta[i], sta[i + 1]);
// if(!is[LCA]){
// sta[++siz] = LCA;
// is[LCA] = 1;
// }
// if(!nex[sta[i]])
// }
// for(int i = 1; i <= siz; i ++){
// is[sta[i]] = nex[sta[i]] = L[sta[i]] = R[sta[i]] = in[sta[i]] = 0;
// }
}
return 0;
}
/*
6
1 1 3 2 4
10
4 3 6 2 5
1 4
3 2 4 5
5 2 5 4 6 3
3 1 4 2
3 5 6 3
5 4 5 2 6 1
4 4 3 2 5
4 4 6 2 3
3 3 2 6
*/
Details
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Test #1:
score: 100
Accepted
time: 2ms
memory: 11756kb
input:
6 1 1 3 2 4 10 4 3 6 2 5 1 4 3 2 4 5 5 2 5 4 6 3 3 1 4 2 3 5 6 3 5 4 5 2 6 1 4 4 3 2 5 4 4 6 2 3 3 3 2 6
output:
No Yes Yes No No No No No No Yes
result:
ok 10 token(s): yes count is 3, no count is 7
Test #2:
score: -100
Wrong Answer
time: 100ms
memory: 37844kb
input:
300000 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1...
output:
Yes No No No Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes No Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes No Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes Yes No No Yes Yes Yes Yes Yes...
result:
wrong answer expected NO, found YES [1st token]