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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#641294 | #8720. BFS 序 0 | neetman | WA | 0ms | 11892kb | C++14 | 3.0kb | 2024-10-14 19:42:13 | 2024-10-14 19:42:14 |
Judging History
answer
#include<algorithm>
#include<iostream>
#include<cstdio>
using namespace std;
const int N = 3e5 + 5;
int n, m, q, tot, top;
int fa[N][20], head[N], dep[N], idx[N];
int vis[N], sta[N*2], maxn[N];
struct edge{
int u, v;
}e[N];
int cnt;
void addedge(int x, int y){
e[++cnt].u = head[x];
e[cnt].v = y;
head[x] = cnt;
}
void dfs(int x){
for(int i = 1; fa[x][i] = fa[fa[x][i-1]][i-1]; i ++);
for(int i = head[x]; i; i = e[i].u){
int to = e[i].v;
dep[to] = dep[x] + 1;
dfs(to);
}
idx[x] = ++tot;
}
int lca(int x, int y){
if(dep[x] != dep[y]){
if(dep[x] < dep[y]) swap(x, y);
for(int i = 19; ~i; i --){
if(dep[fa[x][i]] >= dep[y])
x = fa[x][i];
}
}
if(x == y) return x;
for(int i = 19; ~i; i --)
if(fa[x][i] != fa[y][i]){
x = fa[x][i];
y = fa[y][i];
}
return fa[x][0];
}
int main(){
ios::sync_with_stdio(0),cin.tie(0);
cin >> n;
for(int i = 2; i <= n; i ++){
cin >> fa[i][0];
addedge(fa[i][0], i);
}
dep[1] = 1;
dfs(1);
cin >> q;
bool jud;
while(q --){
cin >> m; jud = 1;
for(int i = 1; i <= m; i ++){
cin >> sta[i];
maxn[sta[i]] = dep[sta[i]];
if(vis[sta[i]])
jud = 0;
vis[sta[i]] = 1;
}
top = m;
// cout << "q = " << q << " jud = " << jud << '\n';
for(int i = m - 1; i; i --){
int LCA = lca(sta[i], sta[top]);
// cout << "TEST!! " << sta[i] << " " << sta[top] << " " << maxn[sta[i]] << " " << maxn[sta[top]] << '\n';
if(LCA == sta[i]){
sta[top] = sta[i];
continue;
}
if(LCA == sta[top]){
if(maxn[sta[top]] < maxn[sta[i]])
jud = 0;
maxn[sta[top]] = maxn[sta[i]];
}
else{
if(maxn[sta[top]] < maxn[sta[i]])
jud = 0;
sta[++top] = LCA;
maxn[sta[top]] = maxn[sta[i]];
}
}
if(jud) cout << "Yes\n";
else cout << "No\n";
for(int i = 1; i <= top; i ++)
maxn[sta[i]] = vis[sta[i]] = 0;
// sort(sta + 1, sta + 1 + m, [](int x, int y){
// return idx[x] < idx[y];
// });
// siz = m;
// for(int i = 1; i < m; i ++){
// int LCA = lca(sta[i], sta[i + 1]);
// if(!is[LCA]){
// sta[++siz] = LCA;
// is[LCA] = 1;
// }
// if(!nex[sta[i]])
// }
// for(int i = 1; i <= siz; i ++){
// is[sta[i]] = nex[sta[i]] = L[sta[i]] = R[sta[i]] = in[sta[i]] = 0;
// }
}
return 0;
}
/*
6
1 1 3 2 4
10
4 3 6 2 5
1 4
3 2 4 5
5 2 5 4 6 3
3 1 4 2
3 5 6 3
5 4 5 2 6 1
4 4 3 2 5
4 4 6 2 3
3 3 2 6
*/
详细
Test #1:
score: 0
Wrong Answer
time: 0ms
memory: 11892kb
input:
6 1 1 3 2 4 10 4 3 6 2 5 1 4 3 2 4 5 5 2 5 4 6 3 3 1 4 2 3 5 6 3 5 4 5 2 6 1 4 4 3 2 5 4 4 6 2 3 3 3 2 6
output:
No Yes No No No No No No No Yes
result:
wrong answer expected YES, found NO [3rd token]