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QOJ
| ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
|---|---|---|---|---|---|---|---|---|---|
| #640896 | #5. 在线 O(1) 逆元 | masterhuang | 100 ✓ | 4471ms | 20280kb | C++20 | 349b | 2024-10-14 16:45:54 | 2024-11-05 22:05:46 |
Judging History
answer
#include "inv.h"
#include<bits/stdc++.h>
using namespace std;
const int N=1<<22|5,mod=998244353;
int n=N-5,I[N];
void init(int p)
{
I[1]=1;
for(int i=2;i<=n;i++) I[i]=mod-1ll*(mod/i)*I[mod%i]%mod;
}
int inv(int x)
{
if(x<=n) return I[x];int q=mod/x,r=mod%x;
if(r<x/2) return mod-1ll*q*inv(r)%mod;
return 1ll*(q+1)*inv(x-r)%mod;
}
详细
Pretests
Final Tests
Test #1:
score: 10
Accepted
time: 24ms
memory: 20280kb
Test #2:
score: 20
Accepted
time: 458ms
memory: 20256kb
Test #3:
score: 30
Accepted
time: 2304ms
memory: 20208kb
Test #4:
score: 20
Accepted
time: 3657ms
memory: 20136kb
Test #5:
score: 20
Accepted
time: 4471ms
memory: 20264kb