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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#640380#5438. Half MixedwpoemWA 23ms3572kbC++205.9kb2024-10-14 11:33:252024-10-14 11:33:25

Judging History

你现在查看的是最新测评结果

  • [2024-10-14 11:33:25]
  • 评测
  • 测评结果:WA
  • 用时:23ms
  • 内存:3572kb
  • [2024-10-14 11:33:25]
  • 提交

answer

#include <cassert>
#include <cmath>
#include <cstdint>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <algorithm>
#include <bitset>
#include <complex>
#include <deque>
#include <functional>
#include <iostream>
#include <limits>
#include <map>
#include <numeric>
#include <queue>
#include <random>
#include <set>
#include <sstream>
#include <string>
#include <unordered_map>
#include <unordered_set>
#include <utility>
#include <vector>
#include <stack>

#ifdef LOCAL
template <class T, size_t size = std::tuple_size<T>::value> std::string to_debug(T, std::string s = "") requires(not std::ranges::range<T>);
std::string to_debug(auto x) requires requires(std::ostream& os) { os << x; } { return static_cast<std::ostringstream>(std::ostringstream() << x).str(); }
std::string to_debug(std::ranges::range auto x, std::string s = "") requires(not std::is_same_v<decltype(x), std::string>) {
  for (auto xi : x) { s += ", " + to_debug(xi); }
  return "[" + s.substr(s.empty() ? 0 : 2) + "]";
}
template <class T, size_t size> std::string to_debug(T x, std::string s) requires(not std::ranges::range<T>) {
  [&]<size_t... I>(std::index_sequence<I...>) { ((s += ", " + to_debug(get<I>(x))), ...); }(std::make_index_sequence<size>());
  return "(" + s.substr(s.empty() ? 0 : 2) + ")";
}
#define debug(...) std::cerr << __LINE__ << ": (" #__VA_ARGS__ ") = " << to_debug(std::tuple(__VA_ARGS__)) << "\n"
#else
#define debug(x...)
#endif

using i64 = long long;

void solve()
{
#define tests
    int n, m; std::cin >> n >> m;

    // if (8 * n * m > 1LL * n * m * (n + 1) * (m + 1) or (1LL * (n + 1) * (m + 1) * n * m) % 8 != 0) {std::cout << "No\n"; return ;}
	i64 tot{1LL * n * m * (n + 1) * (m + 1) / 4};//所有子矩阵个数
	i64 pure_one{1LL * n * m};
	auto calc = [&](int n, int m) {
		if (n <= 0 or m <= 0) {return 0LL;}
		return 1LL * n * m * (n + 1) * (m + 1) / 4 - 1LL * n * m;
	};
	do {//先选一了第一列,然后再选一列,然后算贡献
		i64 rem{tot - pure_one};//所有子矩阵减去大小为1的子矩阵
		//先处理接在一起的状况
		//1 1 0 0 0 0 0 
		//1 0 1 0 0 0 0
		//1 0 1 0 0 0 0

		//0 1 2 3 4 5 6
		//1 0 0 1 0 0 0
		//1 0 0 1 0 0 0
		int d = 1;
		i64 delta{calc(n, 2) + calc(n, m - d - 1)};
		i64 mixed{rem - delta}, pure{pure_one + delta};
		if (d == m - 1) {debug(mixed, pure);}
		if (mixed == pure) {
			std::cout << "Yes\n";
			for (int i = 0; i < n; i++) {
				for (int j = 0; j < m; j++) {
					if (j == 0 or j == d) {
						std::cout << "1 ";
					} else {
						std::cout << "0 ";
					}
				}
				std::cout << "\n";
			}
			return ;
		}

		for (int d = 2; d < m; d++) {
			i64 delta{calc(n, 1) + calc(n, 1) + calc(n, d - 1) + calc(n, m - d - 1)};
			i64 mixed{rem - delta}, pure{pure_one + delta};
			if (mixed == pure) {
				std::cout << "Yes\n";
				for (int i = 0; i < n; i++) {
					for (int j = 0; j < m; j++) {
						if (j == 0 or j == d) {
							std::cout << "1 ";
						} else {
							std::cout << "0 ";
						}
					}
					std::cout << "\n";
				}
				return ;
			}
		}
	} while (false);
	do {//先选一了第一行,然后再选一行,然后算贡献
		i64 rem{tot - pure_one};//所有子矩阵减去大小为1的子矩阵
		//先处理接在一起的状况
		//1 1 0 0 0 0 0 
		//1 0 1 0 0 0 0
		//1 0 1 0 0 0 0

		//0 1 2 3 4 5 6
		//1 0 0 1 0 0 0
		//1 0 0 1 0 0 0
		int d = 1;
		i64 delta{calc(2, m) + calc(n - 1 - d, m)};
		i64 mixed{rem - delta}, pure{pure_one + delta};
		if (mixed == pure) {
			std::cout << "Yes\n";
			for (int i = 0; i < n; i++) {
				for (int j = 0; j < m; j++) {
					if (i == 0 or i == d) {
						std::cout << "1 ";
					} else {
						std::cout << "0 ";
					}
				}
				std::cout << "\n";
			}
			return ;
		}

		for (int d = 2; d < n; d++) {
			i64 delta{calc(1, m) + calc(1, m) + calc(d - 1, m) + calc(n - 1 - d, m)};
			i64 mixed{rem - delta}, pure{pure_one + delta};
			if (mixed == pure) {
				std::cout << "Yes\n";
				for (int i = 0; i < n; i++) {
					for (int j = 0; j < m; j++) {
						if (i == 0 or i == d) {
							std::cout << "1 ";
						} else {
							std::cout << "0 ";
						}
					}
					std::cout << "\n";
				}
				return ;
			}
		}
	} while (false);
	do {//先选一了第一列,然后再选一列,然后算贡献
		i64 rem{tot - pure_one};//所有子矩阵减去大小为1的子矩阵
		//先处理接在一起的状况
		//1 1 0 0 0 0 0 
		//1 0 1 0 0 0 0
		//1 0 1 0 0 0 0

		//0 1 2 3 4 5 6
		//1 0 0 1 0 0 0
		//1 0 0 1 0 0 0
		for (int d = 0; d < m; d++) {
			i64 delta{calc(n, 1) + calc(n, d) + calc(n, m - d - 1)};
			i64 mixed{rem - delta}, pure{pure_one + delta};
			if (mixed == pure) {
				std::cout << "Yes\n";
				for (int i = 0; i < n; i++) {
					for (int j = 0; j < m; j++) {
						if (j == d) {
							std::cout << "1 ";
						} else {
							std::cout << "0 ";
						}
					}
					std::cout << "\n";
				}
				return ;
			}
		}
	} while (false);

	do {//先选一了第一行,然后再选一行,然后算贡献
		i64 rem{tot - pure_one};//所有子矩阵减去大小为1的子矩阵
		//先处理接在一起的状况
		//1 1 0 0 0 0 0 
		//1 0 1 0 0 0 0
		//1 0 1 0 0 0 0

		//0 1 2 3 4 5 6
		//1 0 0 1 0 0 0
		//1 0 0 1 0 0 0
		for (int d = 0; d < n; d++) {
			i64 delta{calc(1, m) + calc(d, m) + calc(n - d - 1, m)};
			i64 mixed{rem - delta}, pure{pure_one + delta};
			if (mixed == pure) {
				std::cout << "Yes\n";
				for (int i = 0; i < n; i++) {
					for (int j = 0; j < m; j++) {
						if (i == d) {
							std::cout << "1 ";
						} else {
							std::cout << "0 ";
						}
					}
					std::cout << "\n";
				}
				return ;
			}
		}
	} while (false);

	std::cout << "No\n";

}
 
signed main()
{
    std::cin.tie(nullptr)->sync_with_stdio(false);
    int _{1};
#ifdef tests
    std::cin >> _;
#endif
    while(_--) solve();
    return 0;
}


詳細信息

Test #1:

score: 100
Accepted
time: 0ms
memory: 3572kb

input:

2
2 3
1 1

output:

Yes
1 0 1 
1 0 1 
No

result:

ok OK, Accepted. (2 test cases)

Test #2:

score: -100
Wrong Answer
time: 23ms
memory: 3516kb

input:

5382
1 1
1 2
2 1
1 3
2 2
3 1
1 4
2 3
3 2
4 1
1 5
2 4
3 3
4 2
5 1
1 6
2 5
3 4
4 3
5 2
6 1
1 7
2 6
3 5
4 4
5 3
6 2
7 1
1 8
2 7
3 6
4 5
5 4
6 3
7 2
8 1
1 9
2 8
3 7
4 6
5 5
6 4
7 3
8 2
9 1
1 10
2 9
3 8
4 7
5 6
6 5
7 4
8 3
9 2
10 1
1 11
2 10
3 9
4 8
5 7
6 6
7 5
8 4
9 3
10 2
11 1
1 12
2 11
3 10
4 9
5 8
6 ...

output:

No
No
No
Yes
1 0 1 
No
Yes
1 
0 
1 
Yes
1 0 0 1 
Yes
1 0 1 
1 0 1 
Yes
1 1 
0 0 
1 1 
Yes
1 
0 
0 
1 
No
Yes
1 0 0 1 
1 0 0 1 
Yes
1 0 1 
1 0 1 
1 0 1 
Yes
1 1 
0 0 
0 0 
1 1 
No
No
No
Yes
1 0 0 1 
1 0 0 1 
1 0 0 1 
Yes
1 0 1 
1 0 1 
1 0 1 
1 0 1 
No
No
Yes
0 0 1 0 0 0 0 
No
Yes
1 1 1 1 1 
0 0 0 0 0...

result:

wrong answer Wrong Verdict (test case 106)