QOJ.ac
QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#639651 | #6744. Square | Nyans | AC ✓ | 76ms | 3720kb | C++14 | 1.1kb | 2024-10-13 21:08:12 | 2024-10-13 21:08:13 |
Judging History
answer
#include <bits/stdc++.h>
using i64 = long long;
i64 go(i64 x) {
return floor(sqrtl(x * 2) + 1.5);
}
i64 find(i64 x, i64 y) {
i64 lo = 1, hi = 10000000000;
while (lo < hi) {
i64 mid = (lo + hi) / 2;
i64 k = go(x);
if ((__int128)(k + k + mid - 1) * mid / 2 >= y - x) {
hi = mid;
} else {
lo = mid + 1;
}
}
return lo;
}
void solve() {
i64 x, y; std::cin >> x >> y;
if (x >= y) {
std::cout << x - y << "\n";
return;
}
i64 B = find(x, y);
i64 lo = 1, hi = x;
while (lo < hi) {
i64 mid = (lo + hi) / 2;
i64 k = go(mid);
if (mid + (__int128)(k + k + B - 1) * B / 2 >= y) {
hi = mid;
} else {
lo = mid + 1;
}
}
i64 k = go(lo);
i64 ans = x - lo + B + lo + (__int128)(k + k + B - 1) * B / 2 - y;
std::cout << ans << "\n";
}
int main() {
std::ios::sync_with_stdio(false);
std::cin.tie(nullptr);
int T; std::cin >> T;
while (T--) {
solve();
}
return 0;
}
详细
Test #1:
score: 100
Accepted
time: 0ms
memory: 3720kb
input:
2 5 1 1 5
output:
4 3
result:
ok 2 number(s): "4 3"
Test #2:
score: 0
Accepted
time: 76ms
memory: 3716kb
input:
100000 1 1 1 2 1 3 1 4 1 5 1 6 1 7 1 8 1 9 1 10 1 11 1 12 1 13 1 14 1 15 1 16 1 17 1 18 1 19 1 20 1 21 1 22 1 23 1 24 1 25 1 26 1 27 1 28 1 29 1 30 1 31 1 32 1 33 1 34 1 35 1 36 1 37 1 38 1 39 1 40 1 41 1 42 1 43 1 44 1 45 1 46 1 47 1 48 1 49 1 50 1 51 1 52 1 53 1 54 1 55 1 56 1 57 1 58 1 59 1 60 1 ...
output:
0 2 1 4 3 2 6 5 4 3 8 7 6 5 4 10 9 8 7 6 5 12 11 10 9 8 7 6 14 13 12 11 10 9 8 7 16 15 14 13 12 11 10 9 8 18 17 16 15 14 13 12 11 10 9 20 19 18 17 16 15 14 13 12 11 10 22 21 20 19 18 17 16 15 14 13 12 11 24 23 22 21 20 19 18 17 16 15 14 13 12 26 25 24 23 22 21 20 19 18 1 0 2 2 1 3 4 3 2 4 6 5 4 3 5 ...
result:
ok 100000 numbers