QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#638830#5669. Traveling in Jade Citywmw#RE 2ms13840kbC++202.1kb2024-10-13 17:01:572024-10-13 17:01:59

Judging History

你现在查看的是最新测评结果

  • [2024-10-13 17:01:59]
  • 评测
  • 测评结果:RE
  • 用时:2ms
  • 内存:13840kb
  • [2024-10-13 17:01:57]
  • 提交

answer

//
// Created by 조문성 on 2024. 10. 13..
//
#include <bits/stdc++.h>
#define all(v) v.begin(), v.end()
#define prs(v) sort(all(v)); v.erase(unique(all(v)), v.end())
using namespace std;
using ll = long long;
const int tN = 1 << 20;
ll t1[tN], t2[tN];

void update(int i, ll k, int op) {
    for (; i < tN; i += i & -i)(op ? t1 : t2)[i] += k;
}

ll query(int i, int op) {
    ll res = 0;
    for (; i; i -= i & -i)res += (op ? t1 : t2)[i];
    return res;
}

ll qry(int l, int r, int op) {
    return query(r, op) - query(l - 1, op);
}

const int N = 1'000'000;

int main() {
    cin.tie(0)->sync_with_stdio(0);
    int n, k, m, Q;

    cin >> n >> k >> m >> Q;
    assert(n != 1);

    vector<ll> W1(n + 1), W2(m + 2), S(m + 2);
    vector<int> on1(n + 1, 1), on2(m + 2, 1);
    for (int s = 1; s <= n; s++)cin >> W1[s];
    for (int s = 1; s <= m + 1; s++)cin >> W2[s], S[s] = S[s - 1] + W2[s];
    for (int s = 1; s <= n; s++)update(s, W1[s], 1);
    auto dist = [&](int u, int v) {
        if (u > v)swap(u, v);
        ll l = qry(u, v - 1, 1);
        ll r = qry(1, u - 1, 1) + qry(v, n, 1);
        return min(l, r);
    };
    for (int q = 1; q <= Q; q++) {
        char op;
        cin >> op;
        if (op == 'q') {
            int u, v;
            cin >> u >> v;
            if (u > v)swap(u, v);
            ll c = dist(u, v);
            ll l = qry(1, m + 1, 0);
            ll a = dist(u, 1) + dist(k, v) + (l ? 1e9 : S[m + 1]);
            ll b = dist(u, k) + dist(1, v) + (l ? 1e9 : S[m + 1]);
            ll mn = min({c, a, b});
            if (mn >= 1e9)cout << "impossible\n";
            else cout << mn << '\n';
        } else if (op == 'c') {
            int i;
            cin >> i;
            if (on1[i])update(i, -W1[i], 1), update(i, 1e9, 1), on1[i] = 0;
            else update(i, -1e9, 1), update(i, W1[i], -1), on1[i] = 1;
        } else {
            int i;
            cin >> i;
            i++;
            if (on2[i])update(i, 1, 0), on2[i] = 0;
            else update(i, -1, 0), on2[i] = 1;
        }
    }
}

详细

Test #1:

score: 100
Accepted
time: 2ms
memory: 13840kb

input:

4 3 1 9
2 3 8 4
1 1
q 3 4
x 0
q 3 4
c 3
q 3 4
c 1
q 3 4
x 0
q 3 4

output:

6
8
9
impossible
6

result:

ok 5 lines

Test #2:

score: 0
Accepted
time: 0ms
memory: 13840kb

input:

4 3 1 9
2 3 8 4
1 1
q 3 4
x 0
q 3 4
c 3
q 3 4
c 1
q 3 4
x 0
q 3 4

output:

6
8
9
impossible
6

result:

ok 5 lines

Test #3:

score: -100
Runtime Error

input:

1000000 999999 1000000 1000000
200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 2...

output:


result: