QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#638448#5669. Traveling in Jade Citywmw#RE 2ms14132kbC++172.1kb2024-10-13 15:57:012024-10-13 15:57:01

Judging History

你现在查看的是最新测评结果

  • [2024-10-13 15:57:01]
  • 评测
  • 测评结果:RE
  • 用时:2ms
  • 内存:14132kb
  • [2024-10-13 15:57:01]
  • 提交

answer

//
// Created by 조문성 on 2024. 10. 13..
//
#include <bits/stdc++.h>
#define int long long
#define all(v) v.begin(), v.end()
#define prs(v) sort(all(v)); v.erase(unique(all(v)), v.end())
using namespace std;
// using ll = long long;
const int tN = 1 << 20;
int t1[tN + 1], t2[tN + 1];

void update(int i, int k, int op) {
    for (; i < tN; i += i & -i)(op ? t1 : t2)[i] += k;
}

int query(int i, int op) {
    int res = 0;
    for (; i; i -= i & -i)res += (op ? t1 : t2)[i];
    return res;
}

int qry(int l, int r, int op) {
    return query(r, op) - query(l - 1, op);
}

signed main() {
    cin.tie(0)->sync_with_stdio(0);
    int n, k, m, Q;
    cin >> n >> k >> m >> Q;
    vector<int> W1(n + 1), W2(m + 2);
    vector<int> on1(n + 1, 1), on2(m + 2, 1);
    for (int s = 1; s <= n; s++)cin >> W1[s];
    for (int s = 1; s <= m + 1; s++)cin >> W2[s];
    for (int s = 1; s <= n; s++)update(s, W1[s], 1);
    for (int s = 1; s <= m + 1; s++)update(s, W2[s], 0);
    auto dist = [&](int u, int v) {
        if (u > v)swap(u, v);
        int l = qry(u, v - 1, 1);
        int r = qry(1, u - 1, 1) + qry(v, n, 1);
        return min(l, r);
    };
    for (int q = 1; q <= Q; q++) {
        char op;
        cin >> op;
        if (op == 'q') {
            int u, v;
            cin >> u >> v;
            if (u > v)swap(u, v);
            int l = dist(u, v);
            int a = dist(u, 1) + dist(k, v) + qry(1, m + 1, 0);
            int b = dist(u, k) + dist(1, v) + qry(1, m + 1, 0);
            int mn = min({l, a, b});
            if (mn > 1e9)cout << "impossible\n";
            else cout << mn << '\n';
        } else if (op == 'c') {
            int i;
            cin >> i;
            if (on1[i])update(i, -W1[i], 1), update(i, 1e11, 1), on1[i] = 0;
            else update(i, -1e11, 1), update(i, W1[i], -1), on1[i] = 1;
        } else {
            int i;
            cin >> i;
            i++;
            if (on2[i])update(i, -W2[i], 0), update(i, 1e11, 0), on2[i] = 0;
            else update(i, -1e11, 0), update(i, W2[i], 0), on2[i] = 1;
        }
    }
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 14096kb

input:

4 3 1 9
2 3 8 4
1 1
q 3 4
x 0
q 3 4
c 3
q 3 4
c 1
q 3 4
x 0
q 3 4

output:

6
8
9
impossible
6

result:

ok 5 lines

Test #2:

score: 0
Accepted
time: 2ms
memory: 14132kb

input:

4 3 1 9
2 3 8 4
1 1
q 3 4
x 0
q 3 4
c 3
q 3 4
c 1
q 3 4
x 0
q 3 4

output:

6
8
9
impossible
6

result:

ok 5 lines

Test #3:

score: -100
Runtime Error

input:

1000000 999999 1000000 1000000
200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 200 2...

output:


result: