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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#63533#1869. Power Station of ArtlmeowdnTL 12ms151304kbC++172.2kb2022-11-22 15:40:552022-11-22 15:40:58

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2022-11-22 15:40:58]
  • 评测
  • 测评结果:TL
  • 用时:12ms
  • 内存:151304kb
  • [2022-11-22 15:40:55]
  • 提交

answer

#include<bits/stdc++.h>
#define int long long
using namespace std;
#define fi first
#define se second
#define rep(i,a,b) for(int i=(a);i<=(b);i++)
#define per(i,a,b) for(int i=(a);i>=(b);i--)
#define eb emplace_back
#define y1 yylyylyylyyl
typedef pair<int,int> pii;
typedef vector<int> vi;
typedef vector<pii> vp;
typedef unsigned long long ull;
typedef __int128 lll;
 
long long read() {
    long long res=0, w=1; char c=getchar();
    while(!isdigit(c)) {if(c=='-') w=-1; c=getchar();}
    while(isdigit(c)) {res=res*10+c-48, c=getchar();}
    return res*w;
}

const int N=1e6+9;
int T,n,m,col[N],sz[N],cnt,bp[N],a[N],b[N],bx[N],by[N];
vi e[N],s[N],sx[N],sy[N],gx[N],gy[N];
char t[N];

void dfs(int u,int c,int id) {
    col[u]=c, s[id].eb(u), sz[id]++;
    for(auto v:e[u]) {
        if(col[v]!=-1) {
            if(col[u]==col[v]) bp[id]=0;
        } else dfs(v,c^1,id);
    } 
}

signed main() {
    T=read();
    while(T--) {
        n=read(), m=read();
        rep(i,1,m) {
            int u=read(), v=read();
            e[u].eb(v), e[v].eb(u);
        }
        rep(i,1,n) if(col[i]==-1) dfs(i,0,++cnt);

        rep(i,1,n) a[i]=read();
        scanf("%s",t+1);
        rep(i,1,n) b[i]=(t[i]=='B');
        rep(i,1,cnt) {
            for(auto x:s[i]) sx[i].eb(a[x]), bx[i]^=b[x];
            sort(sx[i].begin(),sx[i].end());
            if(bp[i]) {
                for(auto x:s[i]) gx[i].eb(b[x]^col[x]);
            }
        }

        rep(i,1,n) a[i]=read();
        scanf("%s",t+1);
        rep(i,1,n) b[i]=(t[i]=='B');
        rep(i,1,cnt) {
            for(auto x:s[i]) sy[i].eb(a[x]), by[i]^=b[x];
            sort(sy[i].begin(),sy[i].end());
            if(bp[i]) {
                for(auto x:s[i]) gy[i].eb(b[x]^col[x]);
            }
        }

        bool ans=1;
        rep(i,1,cnt) ans&=((sx[i]==sy[i])&(bx[i]==by[i])&(gx[i]==gy[i]));
        if(ans) puts("YES");
        else puts("NO");

        rep(i,1,n) e[i].clear(), col[i]=-1, a[i]=b[i]=0;
        rep(i,1,cnt) sz[i]=bp[i]=bx[i]=by[i]=0;
        rep(i,1,cnt) s[i].clear(), sx[i].clear(), sy[i].clear(), gx[i].clear(), gy[i].clear();
    }
    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 12ms
memory: 151304kb

input:

3
2 1
1 2
3 4
RR
4 3
BB
3 2
1 2
2 3
1 1 1
RBR
1 1 1
BBB
3 3
1 2
2 3
3 1
1 1 1
RBR
1 1 1
BBB

output:

YES
NO
YES

result:

ok 3 lines

Test #2:

score: -100
Time Limit Exceeded

input:

25054
5 10
4 5
4 2
4 3
4 1
5 2
5 3
5 1
2 3
2 1
3 1
12 2 9 10 7
RRRBB
10 2 9 7 12
RRBRB
1 0
4
R
4
R
8 4
4 3
1 5
8 5
6 5
7 2 11 10 9 6 3 5
RBRBBRBR
7 2 10 11 6 5 3 9
RBRBBRBR
7 4
7 2
5 1
5 6
5 4
12 5 9 14 5 12 12
RRBRBRR
14 12 9 5 12 12 5
RBBRBRB
10 1
4 6
5 3 2 9 7 3 11 11 6 8
RRRBRRBBBR
5 3 2 3 7 9 1...

output:

YES
YES
NO
YES
YES
YES
YES
YES
YES
NO
YES
NO
YES
NO
NO
YES
YES
YES
NO
YES
YES
YES
YES
NO
YES
YES
NO
YES
NO
YES
YES
YES
YES
YES
YES
YES
NO
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
NO
YES
YES
NO
YES
YES
YES
YES
NO
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
NO
YES
YES
YES
NO
YES
NO
...

result: