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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#635065#3994. Easy JumpdsptWA 0ms1620kbC++231.7kb2024-10-12 18:55:312024-10-12 18:55:32

Judging History

你现在查看的是最新测评结果

  • [2024-10-12 18:55:32]
  • 评测
  • 测评结果:WA
  • 用时:0ms
  • 内存:1620kb
  • [2024-10-12 18:55:31]
  • 提交

answer

#include <stdio.h>
int b[1001]; double p[1001], f[1001][10][7], g[1001][10];
int main()
{
    int n, h, s, t1, t2; scanf("%d%d%d", &n, &h, &s);
    for (int i(1); i <= n; ++i) scanf("%lf", &p[i]), p[i] /= 100;
    int m; scanf("%d", &m); while (m--) { int i; scanf("%d", &i); b[i] = true; }
    scanf("%d%d", &t1, &t2);
    if (t1 >= t2 || !s)
    {
        for (int i(n); i; --i)
        {
            g[i][2] = (t2 + 1) / p[i] + g[i + 1][2] - t2;
            for (int j(3); j <= h; ++j)
                g[i][j] = p[i] * g[i + 1][j] + (1 - p[i]) * g[i][j - 1] + 1;
        }
        printf("%.6f\n", g[1][h]);
    }
    else
    {
        for (int i(n); i; --i)
            if (b[i])
            {
                double d[h + 1], e[h + 1]; for (int j(2); j <= h; ++j) d[j] = 1e9;
                for (int c(2); c <= h; ++c)
                {
                    e[c] = (t1 + 1) / p[i] + f[i + 1][c][s] - t1;
                    for (int j(c + 1); j <= h; ++j) e[j] = p[i] * f[i + 1][j][s] + (1 - p[i]) * e[j - 1] + 1;
                    for (int j(2); j < c; ++j) e[j] = e[c] + (c - j) * t1;
                    for (int j(2); j <= h; ++j) if (e[j] < d[j]) d[j] = e[j];
                }
                for (int j(2); j <= h; ++j) for (int k(0); k <= s; ++k) f[i][j][k] = d[j];
            }
            else
            {
                f[i][2][0] = (t2 + 1) / p[i] + f[i + 1][2][0] - t2;
                for (int k(0); k <= s; ++k) f[i][2][k] = p[i] * f[i + 1][2][k] + (1 - p[i]) * (f[i][2][k - 1] + t1) + 1;
                for (int j(2); j <= h; ++j) for (int k(0); k <= s; ++k)
                    f[i][j][k] = p[i] * f[i + 1][j][k] + (1 - p[i]) * f[i][j - 1][k];
            }
        printf("%.6f\n", f[1][h][s]);
    }
    return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 0ms
memory: 1620kb

input:

1 2 0
50
0
1 2

output:

4.000000

result:

ok found '4.0000000', expected '4.0000000', error '0.0000000'

Test #2:

score: -100
Wrong Answer
time: 0ms
memory: 1616kb

input:

2 3 1
50 50
1 1
1 3

output:

2.500000

result:

wrong answer 1st numbers differ - expected: '6.0000000', found: '2.5000000', error = '0.5833333'