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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#632518#7757. Palm IslandtsaiWA 1ms4028kbC++14848b2024-10-12 13:30:352024-10-12 13:30:39

Judging History

你现在查看的是最新测评结果

  • [2024-10-12 13:30:39]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:4028kb
  • [2024-10-12 13:30:35]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
const int N=2005;
int n, a[N], b[N];
void solve(){
	scanf("%d", &n);
    for(int i = 1; i <= n; i++) scanf("%d", &a[i]);
    for(int i = 1; i <= n; i++){
        int tmp; scanf("%d", &tmp);
        b[tmp] = i;
    }
	deque<int>q;
    for(int i = 1; i <= n; i++) q.push_back(b[a[i]]);
    int rem = n % 2; n = n - n % 2;
	for(int i = 1; i <= n; i+=2){
		int fir = i, sec = i + 1;
		while(q.front() != fir) q.push_back(q.front()), q.pop_front(), printf("1");
		q.pop_front();
		while(q.front() != sec) q.push_back(q.front()), q.pop_front(), printf("2");
		q.pop_front();
		printf("11"); q.push_back(1), q.push_back(2);
	}
	if(rem) printf("1");
}

int main(){
	int t;
	scanf("%d",&t);
	while(t--){
		solve();
		if(t) printf("\n");
	}
	
	return 0;	
}

詳細信息

Test #1:

score: 100
Accepted
time: 1ms
memory: 3800kb

input:

2
3
1 2 3
2 3 1
4
1 2 3 4
2 1 3 4

output:

1111
1221111

result:

ok Correct. (2 test cases)

Test #2:

score: -100
Wrong Answer
time: 0ms
memory: 4028kb

input:

200
3
3 1 2
2 3 1
4
2 4 1 3
2 1 4 3
4
1 4 2 3
2 1 3 4
5
4 3 2 1 5
2 4 5 3 1
5
2 1 5 4 3
5 2 4 1 3
4
4 3 1 2
1 2 4 3
3
1 2 3
3 1 2
4
1 4 2 3
2 1 4 3
4
1 3 2 4
1 4 3 2
3
3 2 1
1 3 2
3
2 3 1
1 3 2
4
1 4 3 2
3 1 2 4
3
1 2 3
1 3 2
3
3 2 1
2 3 1
5
5 1 3 2 4
2 4 5 1 3
4
4 3 1 2
1 4 3 2
4
1 3 4 2
2 4 3 1
3
...

output:

11111
21112211
1121112211
1122111122111
1122111222111
111111
11111
1121111
221111
11111
112111
1121112211
2111
12111
11111111
1121111
111221112211
1111
1111
11122111111
111221111
11221112211
11121112211
121112211
11122112111
1111
2111222111
11111111
111221111
211111
2111
111221112211
12111
112211111...

result:

wrong answer On Case#20: After your operations, a[1] = 5 but a[1] = 3. (test case 20)