QOJ.ac
QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#631822 | #7900. Gifts from Knowledge | Pepinot | RE | 0ms | 3552kb | C++20 | 2.2kb | 2024-10-12 10:27:25 | 2024-10-12 10:27:25 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
#define int long long
#define pb push_back
#define fi first
#define se second
const int mod = 1e9 + 7;
int n, m;
struct DSU{
vector<int> fa;
DSU(int n) : fa(n) {
for(int i = 0; i < n; i++){
fa[i] = i;
}
}
int find(int x){
if (fa[x] != x) fa[x] = find(fa[x]);
return fa[x];
}
void merge(int x, int y){
if(find(x) != find(y)){
fa[find(x)] = find(y);
}
}
};
void solve(){
int res = 0;
cin >> n >> m;
vector<vector<int>> a(n + 5, vector<int>(m + 5));
for(int i = 1; i <= n; i++){
for(int j = 1; j <= m; j++){
char ch;
cin >> ch;
a[i][j] = ch - '0';
}
}
DSU d(2 * n + 5);
for(int j = 1; j <= m / 2; j++){
vector<int> vec[2];
for(int i = 1; i <= n; i++){
if(a[i][j]) vec[0].pb(i);
if(a[i][m - j + 1]) vec[1].pb(i);
}
if(vec[0].size() + vec[1].size() > 2){
cout << 0 << '\n';
return;
}
// for(int x = 0; x < 2; x++)
// for(int y = 0; y < vec[x].size(); y++)
// for(int z = y + 1; z < vec[x].size(); z++){
// int u = vec[x][y], v = vec[x][z];
// d.merge(u + n, v);
// d.merge(u, v + n);
// }
// if(vec[0].size()+vec[1].size()==2){
if(vec[0].size() && vec[1].size()){
int u = vec[0][0], v = vec[1][0];
d.merge(u, v);
d.merge(u + n, v + n);
}
else{
if(vec[0].size()){
int u = vec[0][0], v = vec[0][1];
d.merge(u, v);
d.merge(u + n, v + n);
}
else{
int u = vec[1][0], v = vec[1][1];
d.merge(u, v);
d.merge(u + n, v + n);
}
}
// }
}
if(m % 2 == 1){
int j = (m + 1) / 2;
vector<int> vec;
for(int i = 1; i <= n; i++)
if(a[i][j]) vec.pb(i);
if(vec.size() > 1){
cout << 0 << '\n';
return;
}
}
for(int i = 1; i <= n; i++)
if(d.find(i) == d.find(i + n)){
cout << 0 << '\n';
return;
}
int cnt = 0;
for(int i = 1; i <= 2 * n; i++)
if(d.find(i) == i) cnt++;
cnt /= 2;
res = 1;
for(int i = 1; i <= cnt; i++){
res = res * 2 % mod;
}
cout << res << '\n';
}
signed main(){
ios::sync_with_stdio(0);cin.tie(0);
int T = 1;
cin >> T;
while (T--)
solve();
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 3552kb
input:
3 3 5 01100 10001 00010 2 1 1 1 2 3 001 001
output:
4 0 2
result:
ok 3 number(s): "4 0 2"
Test #2:
score: -100
Runtime Error
input:
15613 10 10 0000000000 0000000000 0000000000 0000000000 0000000000 0000000000 0000000000 0000000000 0000000000 0000000000 15 8 00000000 00000000 00000000 00000000 00000000 00000000 00000000 00000000 00000000 00000000 00000000 00000000 00000000 00000000 00000000 1 5 00000 5 9 000000000 000000000 0000...