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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#630335#6744. SquareQzong#AC ✓49ms3904kbC++141.1kb2024-10-11 17:59:072024-10-11 17:59:07

Judging History

你现在查看的是最新测评结果

  • [2024-10-11 17:59:07]
  • 评测
  • 测评结果:AC
  • 用时:49ms
  • 内存:3904kb
  • [2024-10-11 17:59:07]
  • 提交

answer

#include <bits/stdc++.h>
#define int long long 
typedef long long s64;

const s64 inf = 1e18;

int go(s64 x) {
    return (int)(sqrt(2 * x) + 1.5);
}

s64 calc(s64 st, s64 ed) {
    int k = go(st);
    int l = 1, r = 10000000000;
    while (l < r) {
        int mid = (l + r) >> 1;
        if ((__int128) (2 * k + mid - 1) * mid / 2 >= ed - st)
            r = mid;
        else
            l = mid + 1;
    }
    return l;
}

void work() {
    s64 x, y;
    scanf("%lld%lld", &x, &y);

    if (x >= y) {
        printf("%lld\n", x - y);
        return;
    }

	int B = calc(x, y);

	s64 l = 1, r = x;
	while (l < r) {
		s64 mid = (l + r) >> 1;
		s64 k = go(mid);
		if (1ll * (2 * k + B - 1) * B / 2 >= y - mid)
			r = mid;
		else
			l = mid + 1;
	}

	s64 k = go(l);
	s64 ed = l + 1ll * (2 * k + B - 1) * B / 2;

    printf("%lld\n", (x - l) + B + (ed - y));
}

signed main() {
	// freopen("a.in","r",stdin);
	// freopen("a.out","w",stdout);
    int T;
    scanf("%lld", &T);

    while (T --)
        work();

    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3904kb

input:

2
5 1
1 5

output:

4
3

result:

ok 2 number(s): "4 3"

Test #2:

score: 0
Accepted
time: 49ms
memory: 3816kb

input:

100000
1 1
1 2
1 3
1 4
1 5
1 6
1 7
1 8
1 9
1 10
1 11
1 12
1 13
1 14
1 15
1 16
1 17
1 18
1 19
1 20
1 21
1 22
1 23
1 24
1 25
1 26
1 27
1 28
1 29
1 30
1 31
1 32
1 33
1 34
1 35
1 36
1 37
1 38
1 39
1 40
1 41
1 42
1 43
1 44
1 45
1 46
1 47
1 48
1 49
1 50
1 51
1 52
1 53
1 54
1 55
1 56
1 57
1 58
1 59
1 60
1 ...

output:

0
2
1
4
3
2
6
5
4
3
8
7
6
5
4
10
9
8
7
6
5
12
11
10
9
8
7
6
14
13
12
11
10
9
8
7
16
15
14
13
12
11
10
9
8
18
17
16
15
14
13
12
11
10
9
20
19
18
17
16
15
14
13
12
11
10
22
21
20
19
18
17
16
15
14
13
12
11
24
23
22
21
20
19
18
17
16
15
14
13
12
26
25
24
23
22
21
20
19
18
1
0
2
2
1
3
4
3
2
4
6
5
4
3
5
...

result:

ok 100000 numbers