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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#630244#8022. WalkerMcggvcWA 1ms4020kbC++172.1kb2024-10-11 17:18:552024-10-11 17:18:55

Judging History

你现在查看的是最新测评结果

  • [2024-10-11 17:18:55]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:4020kb
  • [2024-10-11 17:18:55]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
 
#define double long double
 
double cnm(double n, double p1, double p2, double v1, double v2) {
    double ans = n / v1;
    ans = min(ans, ((n - p2) + n) / v2);
    ans = min(ans, max(p2 / v1 , (n - p2) / v2));
    double tmpx = (p2 / v1 - (n - p2) / v2) / (1.0 / v1 + 2.0 / v2);
    if(tmpx > 0 && tmpx < p2) ans = min(ans, (p2 - tmpx) / v1);
    ans=min(ans,(n-p2+n)/(v1+v2));
    ans=min(ans,max(p2/v1,(n-p2)/v2));
    return ans;
}
 
double nmsl(double l1, double l2, double l3, double l, double v1, double v2) {
    double ans = max((2.0 * l2 + l1) / v1, l3 / v2);
    // ans = min(ans, )
    double tmpx = (2.0 * l3 + l2) / v2 - l1 / v1;
    tmpx /= (2.0 / v1 + 1.0 / v2);
    if(tmpx > 0 && tmpx < l2) ans = min(ans, (2.0 * tmpx + l1) / v1);
    return ans;
}
 
double n, p1, p2, v1, v2;
 
double ans;
inline void Min(double tmp) {
    ans = min(ans, tmp);
}
 
 
 
void solve(){
    cin >> n >> p1 >> v1 >> p2 >> v2;
    if(p1 > p2) {
        swap(p1, p2); swap(v1, v2);
    }
    if(p1 == 0 && p2 == n) {
        printf("%.10Lf\n",n / (v1 + v2));
        return ;
    } else if(p1 == 0) {
        printf("%.10Lf\n",cnm(n, p1, p2, v1, v2));
        return ;
    } else if(p2 == n) {
        printf("%.10Lf\n", cnm(n, 0, n - p1, v2, v1));
        return ;
    }
 
    
 
    //<--   -->
    double l1 = p1, l2 = p2 - p1, l3 = n - p2, l = n;
    // ans = 1e9;
    ans = (l + l3) / v2;
    Min((l + l1) / v1);
    Min((l1 + l3 + l) / (v1 + v2)); //
    Min(max((l1 * 2 + l2) / v1, l3 / v2));
    Min(max((l3 * 2 + l2) / v2, l1 / v1));
 
 
    //--->  <---
    Min(max((l2 + l3) / v1, (l1 + l2) / v2));
    double tmpx = (2.0 * l2 + l3) / v2 - l1 / v1;
    tmpx /= (2.0 / v1 + 2.0 / v2);
    if(tmpx > 0 && tmpx < l2) Min((2.0 * tmpx + l1) / v1);
 
    // --->  ---> 
    Min(nmsl(l1, l2, l3, l, v1, v2));
 
    Min(nmsl(l3, l2, l1, l, v2, v1));
 
    printf("%.10Lf\n", ans);
}
 
signed main(){
    // freopen("data.in", "r", stdin);
    ios::sync_with_stdio(false);
    int T; cin >> T;
    while(T--) solve();
    return 0;
}   

詳細信息

Test #1:

score: 100
Accepted
time: 1ms
memory: 4020kb

input:

2
10000.0 1.0 0.001 9999.0 0.001
4306.063 4079.874 0.607 1033.423 0.847

output:

5001000.0000000000
3827.8370013755

result:

ok 2 numbers

Test #2:

score: 0
Accepted
time: 0ms
memory: 3856kb

input:

1
10.0 1.0 10.0 9.0 0.1

output:

1.1000000000

result:

ok found '1.1000000', expected '1.1000000', error '0.0000000'

Test #3:

score: -100
Wrong Answer
time: 0ms
memory: 3980kb

input:

1
10.0 8.0 10.0 9.0 0.1

output:

1.8000000000

result:

wrong answer 1st numbers differ - expected: '1.2000000', found: '1.8000000', error = '0.5000000'