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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#630017#7103. Red Black Treeucup-team3160#AC ✓1549ms20820kbC++142.1kb2024-10-11 16:01:232024-10-11 16:01:24

Judging History

你现在查看的是最新测评结果

  • [2024-10-11 16:01:24]
  • 评测
  • 测评结果:AC
  • 用时:1549ms
  • 内存:20820kb
  • [2024-10-11 16:01:23]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;

const int N = 100005, M = N * 2;
int T, n, m, q;

int e, head[N], nxt[M], to[M];
ll d[M];
void adde(int x, int y, ll z)
{
	e++;
	to[e] = y;
	nxt[e] = head[x];
	d[e] = z;
	head[x] = e;
}

int col[N], dd[N];
ll val[N], dep[N];
int f[N][20];
void dfs(int x, int fa)
{
	f[x][0] = fa;
	for (int i = 1; i < 20; i++)
		f[x][i] = f[f[x][i - 1]][i - 1];
	if (col[x]) val[x] = 0;
	for (int i = head[x]; i; i = nxt[i])
	{
		int v = to[i];
		if (v == fa) continue;
		val[v] = val[x] + d[i];
		dep[v] = dep[x] + d[i];
		dd[v] = dd[x] + 1;
		dfs(v, x);
	}
}

int lca(int x, int y)
{
	if (dd[x] < dd[y]) swap(x, y);
	for (int i = 19; i >= 0; i--)
		if (dd[x] - dd[y] >= (1 << i))
			x = f[x][i];
	if (x == y) return x;
	for (int i = 19; i >= 0; i--)
		if (f[x][i] != f[y][i])
		{
			x = f[x][i];
			y = f[y][i];
		}
	return f[x][0];
}

int tt[N];

int main()
{
	scanf("%d", &T);
	while (T--)
	{
		scanf("%d%d%d", &n, &m, &q);
		for (int i = 1; i <= n; i++) col[i] = 0;
		int x, y;
		ll z;
		for (int i = 1; i <= m; i++)
		{
			scanf("%d", &x);
			col[x] = 1;
		}
		e = 0;
		for (int i = 1; i <= n; i++)
			head[i] = 0;
		for (int i = 1; i < n; i++)
		{
			scanf("%d%d%lld", &x, &y, &z);
			adde(x, y, z);
			adde(y, x, z);
		}
		dd[1] = 0;
		dep[1] = 0;
		dfs(1, 0);
		while (q--)
		{
			scanf("%d", &x);
			for (int i = 1; i <= x; i++)
				scanf("%d", &tt[i]);
			ll L = 0, R = 1e15;
			while (L != R)
			{
				ll mid = (L + R) >> 1;
				//printf("erfen %lld\n", mid);
				int l = -1;
				for (int i = 1; i <= x; i++)
				{
					int now = tt[i];
					if (val[now] > mid)
					{
						if (l == -1) l = now;
						else l = lca(l, now);
					}
				}
				bool ok = true;
				for (int i = 1; i <= x; i++)
				{
					int now = tt[i];
					if (val[now] > mid && dep[now] - dep[l] > mid)
					{
						//printf("fail %d %d\n", now, l);
						ok = false;
					}
				}
				if (ok) R = mid;
				else L = mid + 1;
			}
			printf("%lld\n", L);
		}
	}
	return 0;
}

这程序好像有点Bug,我给组数据试试?

詳細信息

Test #1:

score: 100
Accepted
time: 2ms
memory: 10040kb

input:

2
12 2 4
1 9
1 2 1
2 3 4
3 4 3
3 5 2
2 6 2
6 7 1
6 8 2
2 9 5
9 10 2
9 11 3
1 12 10
3 3 7 8
4 4 5 7 8
4 7 8 10 11
3 4 5 12
3 2 3
1 2
1 2 1
1 3 1
1 1
2 1 2
3 1 2 3

output:

4
5
3
8
0
0
0

result:

ok 7 lines

Test #2:

score: 0
Accepted
time: 1549ms
memory: 20820kb

input:

522
26 1 3
1
1 4 276455
18 6 49344056
18 25 58172365
19 9 12014251
2 1 15079181
17 1 50011746
8 9 2413085
23 24 23767115
22 2 26151339
26 21 50183935
17 14 16892041
9 26 53389093
1 20 62299200
24 18 56114328
11 2 50160143
6 26 14430542
16 7 32574577
3 16 59227555
3 15 8795685
4 12 5801074
5 20 57457...

output:

148616264
148616264
0
319801028
319801028
255904892
317070839
1265145897
1265145897
1072765445
667742619
455103436
285643094
285643094
285643094
317919339
0
785245841
691421476
605409472
479058444
371688030
303203698
493383271
919185207
910180170
919185207
121535083
181713164
181713164
181713164
181...

result:

ok 577632 lines

Extra Test:

score: 0
Extra Test Passed