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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#629676 | #8242. V-Diagram | MiniLong | TL | 1ms | 8064kb | C++14 | 3.4kb | 2024-10-11 14:11:48 | 2024-10-11 14:11:48 |
Judging History
answer
#include <bits/stdc++.h>
#define _rep(i, x, y) for(int i = x; i <= y; ++i)
#define _req(i, x, y) for(int i = x; i >= y; --i)
#define _rev(i, u) for(int i = head[u]; i; i = e[i].nxt)
#define pb push_back
#define fi first
#define se second
#define mst(f, i) memset(f, i, sizeof f)
using namespace std;
#ifdef ONLINE_JUDGE
#define debug(...) 0
#else
#define debug(...) fprintf(stderr, __VA_ARGS__), fflush(stderr)
#endif
typedef long long ll;
typedef pair<int, int> PII;
namespace fastio{
#ifdef ONLINE_JUDGE
char ibuf[1 << 20],*p1 = ibuf, *p2 = ibuf;
#define get() p1 == p2 && (p2 = (p1 = ibuf) + fread(ibuf, 1, 1 << 20, stdin), p1 == p2) ? EOF : *p1++
#else
#define get() getchar()
#endif
template<typename T> inline void read(T &t){
T x = 0, f = 1;
char c = getchar();
while(!isdigit(c)){
if(c == '-') f = -f;
c = getchar();
}
while(isdigit(c)) x = x * 10 + c - '0', c = getchar();
t = x * f;
}
template<typename T, typename ... Args> inline void read(T &t, Args&... args){
read(t);
read(args...);
}
template<typename T> void write(T t){
if(t < 0) putchar('-'), t = -t;
if(t >= 10) write(t / 10);
putchar(t % 10 + '0');
}
template<typename T, typename ... Args> void write(T t, Args... args){
write(t), putchar(' '), write(args...);
}
template<typename T> void writeln(T t){
write(t);
puts("");
}
template<typename T> void writes(T t){
write(t), putchar(' ');
}
#undef get
};
using namespace fastio;
#define multitest() int T; read(T); _rep(tCase, 1, T)
namespace Calculation{
const ll mod = 998244353;
ll ksm(ll p, ll h){ll base = p % mod, res = 1; while(h){if(h & 1ll) res = res * base % mod; base = base * base % mod, h >>= 1ll;} return res;}
void dec(ll &x, ll y){x = ((x - y) % mod + mod) % mod;}
void add(ll &x, ll y){x = (x + y) % mod;}
void mul(ll &x, ll y){x = x * y % mod;}
ll sub(ll x, ll y){return ((x - y) % mod + mod) % mod;}
ll pls(ll x, ll y){return ((x + y) % mod + mod) % mod;}
ll mult(ll x, ll y){return x * y % mod;}
}
using namespace Calculation;
const int N = 3e5 + 5;
typedef long double lb;
const lb eps = 1e-12;
ll n, a[N], L[N], R[N];
lb pre[N], suf[N];
bool check(lb mid){
_rep(i, 1, n) pre[i] = pre[i - 1] + (lb)a[i] - mid;
_req(i, n, 1) suf[i] = suf[i + 1] + (lb)a[i] - mid;
int pos = 0;
_rep(i, 2, n - 1){
if(!L[i] || !R[i]) continue;
pos = i;
break;
}
lb minx = 0;
_rep(i, 0, pos - 2) minx = min(minx, pre[i]);
lb res = pre[n] - minx;
minx = 0;
_rep(i, pos + 2, n) minx = min(minx, suf[i]);
res -= minx;
if(res > -eps) return 1;
return 0;
}
int main(){
multitest(){
read(n);
_rep(i, 1, n) read(a[i]);
_rep(i, 2, n){
if(a[i] < a[i - 1]) L[i] = !L[i - 1] ? i - 1 : L[i - 1];
else L[i] = 0;
}
_req(i, n - 1, 1){
if(a[i] < a[i + 1]) R[i] = !R[i + 1] ? i + 1 : R[i + 1];
else R[i] = 0;
}
lb l = 0, r = 1e9, res = 0;
while(r - l > eps){
lb mid = (l + r) / 2.00;
if(check(mid)) l = mid + eps, res = mid;
else r = mid - eps;
}
printf("%.12Lf\n", res);
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 1ms
memory: 8064kb
input:
2 4 8 2 7 10 6 9 6 5 3 4 8
output:
6.750000000000 5.833333333333
result:
ok 2 numbers
Test #2:
score: -100
Time Limit Exceeded
input:
100000 3 948511478 739365502 813471668 3 881046825 27458122 398507422 3 987554257 399092415 924260278 3 984128569 125199021 716360525 3 529589236 45783262 313507287 3 645443456 85994112 226010681 3 914820717 228360911 572267310 3 418958362 56703604 195276041 3 64461646 26764720 26995581 3 914535039 ...