QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#627834 | #7757. Palm Island | 53Dawns | WA | 1ms | 3844kb | C++23 | 1.7kb | 2024-10-10 17:19:06 | 2024-10-10 17:19:06 |
Judging History
answer
#include <bits/stdc++.h>
// #include <bits/extc++.h>
#pragma GCC optimize (1)
#pragma GCC optimize (2)
#pragma GCC optimize (3)
// #define int long long
#define IOS ios::sync_with_stdio(0),cin.tie(0)
// using namespace __gnu_pbds;
using namespace std;
const int N=2e5+10,M=1e6+10,mod=1e9+7;
int n;
map<int,int>mp;
void f1() {
for(int i = 1 ; i <= n ; i++) {
mp[i]--;
if(mp[i] == 0)
mp[i] = n;
}
}
void f2() {
for(int i = 1 ; i <= n ; i++) {
if(mp[i] == 1) continue;
mp[i]--;
if(mp[i] == 1)
mp[i] = n;
}
}
void sol(int cases) {
cin >> n;
std::vector<int> a(n+1);
mp.clear();
for(int i = 1 ; i <= n ; i++) {
cin >> a[i];
mp[a[i]] = i;
}
std::vector<int> b(n+1);
for(int i = 1 ; i <= n ; i++) {
cin >> b[i];
}
std::vector<int> ans;
while(mp[b[1]] != 1) {
f1();
ans.push_back(1);
}
for(int i = 1 ; i <= n - 1; i++) {
int u = mp[b[i]];
int v = mp[b[i+1]];
while(mp[b[i+1]] != 2) {
ans.push_back(2);
f2();
}
f1();
ans.push_back(1);
}
// for(auto x : ans) {
// cout << x;
// }
// cout << endl;
// for(int i = 1 ; i <= n ; i++) {
// cout << mp[i] << " ";
// }
// cout << endl;
while(mp[b[1]] != 1) {
f1();
ans.push_back(1);
}
for(auto x : ans) {
cout << x;
}
cout << endl;
}
signed main(){
IOS;
int t=1;
cin>>t;
for(int i=1;i<=t;++i){
sol(i);
}
return 0;
}
Details
Tip: Click on the bar to expand more detailed information
Test #1:
score: 100
Accepted
time: 0ms
memory: 3584kb
input:
2 3 1 2 3 2 3 1 4 1 2 3 4 2 1 3 4
output:
1111 1221111
result:
ok Correct. (2 test cases)
Test #2:
score: -100
Wrong Answer
time: 1ms
memory: 3844kb
input:
200 3 3 1 2 2 3 1 4 2 4 1 3 2 1 4 3 4 1 4 2 3 2 1 3 4 5 4 3 2 1 5 2 4 5 3 1 5 2 1 5 4 3 5 2 4 1 3 4 4 3 1 2 1 2 4 3 3 1 2 3 3 1 2 4 1 4 2 3 2 1 4 3 4 1 3 2 4 1 4 3 2 3 3 2 1 1 3 2 3 2 3 1 1 3 2 4 1 4 3 2 3 1 2 4 3 1 2 3 1 3 2 3 3 2 1 2 3 1 5 5 1 3 2 4 2 4 5 1 3 4 4 3 1 2 1 4 3 2 4 1 3 4 2 2 4 3 1 3 ...
output:
11111 21212111 1121212111 1122122121111 1122121221211 111111 11111 1121111 221111 11111 112111 1121212111 2111 12111 11111111 1121111 111221212111 1111 1111 11122121121111 111221111 11221212111 11121212111 121212111 11122112122111 1111 2121221211 11121121111 111221111 211111 2111 111221212111 12111 ...
result:
wrong answer On Case#2: After your operations, a[2] = 4 but a[2] = 1. (test case 2)