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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#627083#5668. Cell Nuclei DetectionKowerKoint#AC ✓4265ms52292kbC++203.6kb2024-10-10 14:41:042024-10-10 14:41:04

Judging History

你现在查看的是最新测评结果

  • [2024-10-10 14:41:04]
  • 评测
  • 测评结果:AC
  • 用时:4265ms
  • 内存:52292kb
  • [2024-10-10 14:41:04]
  • 提交

answer

#include <bits/stdc++.h>

using namespace std;
using ll = long long;

template <class T>
using V = vector<T>;
template <class T>
using VV = vector<vector<T>>;

struct E {
    int to, rev, cap;
};

template <class C>
struct MaxFlow {
    C flow;
    V<char> dual;
};

template<class C, class E>
struct MFExec {
    static constexpr C INF = numeric_limits<C>::max();
    C eps;
    VV<E>& g;
    int s, t;
    V<int> level, iter;

    C dfs(int v, C f) {
        if(v == t) return f;
        C res = 0;
        for(int& i = iter[v]; i < int(g[v].size()); i++) {
            E& e = g[v][i];
            if(e.cap <= eps || level[v] >= level[e.to]) continue;
            C d = dfs(e.to, min(f, e.cap));
            e.cap -= d;
            g[e.to][e.rev].cap += d;
            res += d;
            f -= d;
            if(f == 0) break;
        }
        return res;
    }

    MaxFlow<C> info;
    MFExec(VV<E>& _g, int _s, int _t, C _eps) : eps(_eps), g(_g), s(_s), t(_t) {
        int N = int(g.size());

        C& flow = (info.flow = 0);
        while(true) {
            queue<int> que;
            level = V<int>(N, -1);
            level[s] = 0;
            que.push(s);
            while(!que.empty()) {
                int v = que.front(); que.pop();
                for(E e : g[v]) {
                    if(e.cap <= eps || level[e.to] >= 0) continue;
                    level[e.to] = level[v] + 1;
                    que.push(e.to);
                }
            }
            if(level[t] == -1) break;
            iter = V<int>(N, 0);
            while(true) {
                C f = dfs(s, INF);
                if(!f) break;
                flow += f;
            }
        }
        for(int i = 0; i < N; i++) info.dual.push_back(level[i] == -1);
    }
};

template <class C, class E>
MaxFlow<C> get_mf(VV<E>& g, int s, int t, C eps) {
    return MFExec<C, E>(g, s, t, eps).info;
}

void solve() {
    int m, n; cin >> m>> n;
    vector<tuple<int, int, int, int>> t(m);
    for(int i = 0; i < m; i++) {
        int x1, y1, x2, y2; cin >> x1 >> y1 >> x2 >> y2;
        t[i] = {x1, y1, x2, y2};
    }
    vector<tuple<int, int, int, int>> d(n);
    map<tuple<int, int, int, int>, int> rd;
    for(int i = 0; i < n; i++) {
        int x1, y1, x2, y2; cin >> x1 >> y1 >> x2 >> y2;
        d[i] = {x1, y1, x2, y2};
        rd[d[i]] = i;
    }
    VV<E> g(m+n+2);
    auto add_edge = [&](int from, int to, int cap) {
        g[from].push_back(E{to, int(g[to].size()), cap});
        g[to].push_back(E{from, int(g[from].size())-1, 0});
    };
    for(int i = 0; i < m; i++) {
        auto [x1, y1, x2, y2] = t[i];
        if(x2 > x1+8) continue;
        if(y2 > y1+8) continue;
        for(int lx = x1-4; lx <= x2; lx++) {
            for(int rx= lx+1; rx <= lx+4; rx++) {
                for(int ly = y1-4; ly <= y2; ly++) {
                    for(int ry = ly+1; ry <= ly+4; ry++) {
                        int dx = min(x2, rx) - max(x1, lx);
                        int dy = min(y2, ry) - max(y1, ly);
                        if(dx < 0 || dy < 0) continue;
                        if(dx*dy*2 >= (x2-x1)*(y2-y1)) {
                            if(rd.count({lx, ly, rx, ry})) {
                                add_edge(i, m+rd[{lx, ly, rx, ry}], 1);
                            }
                        }
                    }
                }
            }
        }
    }
    for(int i = 0; i < m; i++) add_edge(m+n, i, 1);
    for(int i = 0; i < n; i++) add_edge(m+i, m+n+1, 1);
    cout << get_mf(g, m+n, m+n+1, 0).flow << '\n';
}

int main() {
    int t; cin >> t;
    while(t--) solve();
}

详细

Test #1:

score: 100
Accepted
time: 1ms
memory: 3592kb

input:

3
2 2
1 1 3 3
3 3 5 5
2 2 4 4
4 4 6 6
2 3
1 1 3 3
3 3 5 5
1 3 3 5
2 1 4 5
3 1 5 3
3 3
1 1 2 2
2 2 3 3
3 3 4 4
1 1 3 3
2 2 4 4
3 3 5 5

output:

0
1
3

result:

ok 3 lines

Test #2:

score: 0
Accepted
time: 0ms
memory: 3520kb

input:

3
2 2
1 1 3 3
3 3 5 5
2 2 4 4
4 4 6 6
2 3
1 1 3 3
3 3 5 5
1 3 3 5
2 1 4 5
3 1 5 3
3 3
1 1 2 2
2 2 3 3
3 3 4 4
1 1 3 3
2 2 4 4
3 3 5 5

output:

0
1
3

result:

ok 3 lines

Test #3:

score: 0
Accepted
time: 2760ms
memory: 33928kb

input:

5
50000 50000
0 0 4 4
4 0 8 4
8 0 12 4
12 0 16 4
16 0 20 4
20 0 24 4
24 0 28 4
28 0 32 4
32 0 36 4
36 0 40 4
40 0 44 4
44 0 48 4
48 0 52 4
52 0 56 4
56 0 60 4
60 0 64 4
64 0 68 4
68 0 72 4
72 0 76 4
76 0 80 4
80 0 84 4
84 0 88 4
88 0 92 4
92 0 96 4
96 0 100 4
100 0 104 4
104 0 108 4
108 0 112 4
112 ...

output:

50000
50000
0
50000
3150

result:

ok 5 lines

Test #4:

score: 0
Accepted
time: 1151ms
memory: 52292kb

input:

5
50000 50000
0 0 1 1
1 0 2 1
2 0 3 1
3 0 4 1
4 0 5 1
5 0 6 1
6 0 7 1
7 0 8 1
8 0 9 1
9 0 10 1
10 0 11 1
11 0 12 1
12 0 13 1
13 0 14 1
14 0 15 1
15 0 16 1
16 0 17 1
17 0 18 1
18 0 19 1
19 0 20 1
20 0 21 1
21 0 22 1
22 0 23 1
23 0 24 1
24 0 25 1
25 0 26 1
26 0 27 1
27 0 28 1
28 0 29 1
29 0 30 1
30 0 ...

output:

50000
25050
12500
16000
8000

result:

ok 5 lines

Test #5:

score: 0
Accepted
time: 1216ms
memory: 16664kb

input:

5
50000 50000
0 0 2 4
4 0 7 1
8 0 10 1
12 0 15 3
16 0 19 1
20 0 22 2
24 0 26 4
28 0 30 4
32 0 36 3
36 0 40 1
40 0 44 1
44 0 47 2
48 0 49 3
52 0 54 1
56 0 59 4
60 0 64 3
64 0 68 3
68 0 70 1
72 0 76 4
76 0 80 3
80 0 84 4
84 0 87 2
88 0 90 1
92 0 94 4
96 0 98 1
100 0 104 1
104 0 107 2
108 0 110 4
112 0...

output:

10594
10779
10618
10381
10779

result:

ok 5 lines

Test #6:

score: 0
Accepted
time: 4265ms
memory: 34292kb

input:

5
50000 50000
0 0 4 4
1 0 5 4
2 0 6 4
3 0 7 4
4 0 8 4
5 0 9 4
6 0 10 4
7 0 11 4
8 0 12 4
9 0 13 4
10 0 14 4
11 0 15 4
12 0 16 4
13 0 17 4
14 0 18 4
15 0 19 4
16 0 20 4
17 0 21 4
18 0 22 4
19 0 23 4
20 0 24 4
21 0 25 4
22 0 26 4
23 0 27 4
24 0 28 4
25 0 29 4
26 0 30 4
27 0 31 4
28 0 32 4
29 0 33 4
30...

output:

50000
50000
50000
50000
49600

result:

ok 5 lines

Test #7:

score: 0
Accepted
time: 0ms
memory: 3768kb

input:

1
4 4
1 1 3 3
2 1 4 3
1 2 3 4
2 2 4 4
2 1 4 3
3 2 5 4
1 2 3 4
2 3 4 5

output:

3

result:

ok single line: '3'