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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#626745#5114. Cells Coloringyzj123TL 3ms27856kbC++203.4kb2024-10-10 12:19:172024-10-10 12:19:20

Judging History

你现在查看的是最新测评结果

  • [2024-10-10 12:19:20]
  • 评测
  • 测评结果:TL
  • 用时:3ms
  • 内存:27856kb
  • [2024-10-10 12:19:17]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
//#define int long long
#define int short
const long P = 80001;
const long E = 2000001;
struct FlowGraph {
    int s, t, vtot, etot, head[P], dis[P], cur[P];
    struct edge {
        int v, nxt;
        int f;
    } e[E * 2];
    inline void addedge(int u, int v, int f) {
        e[etot] = {v, head[u], f}; head[u] = etot ++;
        e[etot] = {u, head[v], 0}; head[v] = etot ++;
    }
    bool bfs() {
        for (int i = 1; i <= vtot; i ++) {
            dis[i] = 0;
            cur[i] = head[i];
        }
        std::queue<int> q;
        q.push(s);
        dis[s] = 1;
        while (! q.empty()) {
            int u = q.front();
            q.pop();
            for (int i = head[u]; ~i; i = e[i].nxt) {
                if (e[i].f && ! dis[e[i].v]) {
                    int v = e[i].v;
                    dis[v] = dis[u] + 1;
                    if (v == t) return true;
                    q.push(v);
                }
            }
        }
        return false;
    }

    inline int dfs(int u, int m) {
        if (u == t) return m;
        int flow = 0;
        for (int i = cur[u]; ~i; cur[u] = i = e[i].nxt) {
            if (e[i].f && dis[e[i].v] == dis[u] + 1) {
                int f = dfs(e[i].v, std::min(m, e[i].f));
                e[i].f -= f;
                e[i ^ 1].f += f;
                m -= f;
                flow += f;
                if (! m) break;
            }
        }
        if (! flow) dis[u] = -1;
        return flow;
    }

    inline int dicnic() {
        int flow = 0;
        while (bfs()) {
            flow += dfs(s, std::numeric_limits<int>::max());
        }
        return flow;
    }
    inline void init(int _s, int _t, int _vtot) {
        s = _s;
        t = _t;
        vtot = _vtot;
        etot = 0;
        for (int i = 1; i <= vtot; i ++) {
            head[i] = -1;
        }
    }
};
inline long read()
{
	long res = 0, bj = 1;
	char ch = getchar();
	while (ch < '0' || ch > '9')
	{
		if (ch == '-') bj = -1;
		ch = getchar();
	}
	while (ch >= '0' && ch <= '9')
	{
		res = res * 10 + ch - '0';
		ch = getchar();
	}
	return res * bj;
}
char a[255][255];
signed main()
{
    int n, m;
	long long c, d;
    n = read();
    m = read();
    c = read();
    d = read();
    int num = 0;
    for (int i = 1; i <= n; i ++) {
		scanf("%s", a[i] + 1);
    }
	FlowGraph g;
    int s = n + m + 1, t = s + 1;
    g.init(s, t, t);
    for (int j = 1; j <= n; j ++) {
		for (int k = 1; k <= m; k ++) {
			if (a[j][k] == '.') {
				g.addedge(j, n + k, 1);
				num ++;
			}
		}
	}
   	long long ans = 1ll * num * d;
	int op = std::max(n, m);
    int now = 0, i = 1;
	
    while (i <= op) {
    	for (int j = 1; j <= n; j ++) {
    		g.addedge(s, j, 1);
		}
		for (int j = 1; j <= m; j ++) {
			g.addedge(n + j, t, 1);
		}
		int res = g.dicnic();
		if (! res) {
			break;
		}
		now += res;
		long long it = ans;
		ans = std::min(ans, 1ll * (num - now) * d + 1ll * i * c);
		if (ans == it) break; 
		i ++;
	}
    std::cout << ans << '\n';
    return 0;
}
/*
13 20 823772868 410753944
.....*......**......
.......*............
...............*....
......*.............
...................*
*........*.*..*.....
.....*.............*
..*..........*.*....
.......*............
...**...........**.*
....................
**......**.......*..
.*.............*....
*/

詳細信息

Test #1:

score: 100
Accepted
time: 3ms
memory: 27856kb

input:

3 4 2 1
.***
*..*
**..

output:

4

result:

ok 1 number(s): "4"

Test #2:

score: 0
Accepted
time: 0ms
memory: 27480kb

input:

3 4 1 2
.***
*..*
**..

output:

2

result:

ok 1 number(s): "2"

Test #3:

score: -100
Time Limit Exceeded

input:

250 250 965680874 9042302
..**.*****..**..**.*****..***..***.**......*.***.*...***.*....*.**.*.**.*.*.****...*.******.***.************....**.*..*..***.*******.*.***.*..**..****.**.*.*..***.****..**.....***.....*.****...*...*.***..****..**.*.*******..*.*******.*.*.*.****.*.***
....**.*******.*.******...

output:


result: