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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#626654#8049. Equal SumsdsptRE 0ms1632kbC++231019b2024-10-10 11:26:022024-10-10 11:26:03

Judging History

你现在查看的是最新测评结果

  • [2024-10-10 11:26:03]
  • 评测
  • 测评结果:RE
  • 用时:0ms
  • 内存:1632kb
  • [2024-10-10 11:26:02]
  • 提交

answer

#include <stdio.h>
const int p(998244353);
int b[501][2], c[501][2], a[501][501][1003];
#define f(i, j, k) a[i][j][k + 501]
void add(int &x, const int y) { x = x + y < p ? x + y : x + y - p; }
int main()
{
    int n, m; scanf("%d%d", &n, &m);
    for (int i(1); i <= n; ++i) scanf("%d%d", &b[i][0], &b[i][1]);
    for (int i(1); i <= m; ++i) scanf("%d%d", &c[i][0], &c[i][1]);
    f(0, 0, 0) = 1; f(0, 0, 1) = p - 1;
    for (int i(0); i <= n; ++i)
    {
        for (int j(0); j <= m; ++j)
        {
            for (int k(-500); k <= 500; ++k)
            {
                add(f(i, j, k), f(i, j, k - 1));
                if (k < 0) add(f(i + 1, j, k + b[i + 1][0]), f(i, j, k)), add(f(i + 1, j, k + b[i + 1][1] + 1), p - f(i, j, k));
                else       add(f(i, j + 1, k - c[j + 1][1]), f(i, j, k)), add(f(i, j + 1, k - c[j + 1][0] + 1), p - f(i, j, k));
            }
            if (i && j) printf("%d ", f(i, j, 0));
        }
        if (i) putchar('\n');
    }
    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 1632kb

input:

2 3
1 2
2 3
1 4
2 2
1 3

output:

2 0 0 
3 4 4 

result:

ok 6 numbers

Test #2:

score: -100
Runtime Error

input:

500 500
19 458
1 480
7 485
50 461
12 476
15 461
48 466
40 453
46 467
9 458
27 478
26 472
46 459
29 490
6 500
17 487
48 484
28 472
28 459
25 480
4 491
29 481
36 460
2 491
44 499
22 473
20 458
4 483
27 471
2 496
11 461
43 450
2 478
37 466
15 459
42 482
7 451
19 455
2 453
47 475
48 450
1 474
46 471
9 4...

output:

411 79401 9145270 673005095 180581065 984223118 586589234 293043270 404363796 865361724 665487988 118838806 926189944 226338288 521479857 808644951 786041288 340769021 177100 21 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 ...

result: