QOJ.ac

QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#626394#5422. Perfect PalindromezhoudashuaiAC ✓28ms3824kbC++141.3kb2024-10-10 07:48:212024-10-10 07:48:23

Judging History

你现在查看的是最新测评结果

  • [2024-10-10 07:48:23]
  • 评测
  • 测评结果:AC
  • 用时:28ms
  • 内存:3824kb
  • [2024-10-10 07:48:21]
  • 提交

answer

#include<iostream>
#include<string.h>
#include<algorithm>
#include<math.h>
#include<vector>
#include<map>
#include<queue>
#include<set> 
#include<stack>
#include<bitset>
#include<unordered_map>
#include<iomanip>
#include<cassert>
#define fi first
#define se second
#define endl '\n'
#define pb push_back
#define ep emplace_back 
#define debug(x) cout<<x<<'\n'
#define RES cout<<res<<'\n'
#define ANS cout<<ans<<'\n'
#define YES	cout<<"YES"<<'\n'
#define NO cout<<"NO"<<'\n'
#define Yes	cout<<"Yes"<<'\n'
#define No cout<<"No"<<'\n'
#define me(a,x) memset(a,x,sizeof(a))
#define L(i,j,k) for(int i=(j);i<=(k);++i)
#define R(i,j,k) for(int i=(j);i>=(k);--i)
#define r23 cout<<233<<endl;return;
#define int long long 
using namespace std;
typedef long long ll;
typedef pair<int,int> PII;
typedef pair<PII,int> PIII;
typedef unsigned long long ull;
const int N=1e5+5,P=131,mod=998244353;
int qmi(int a,int b){
	int res=1;
	while(b){
		if(b&1)res=res*a%mod;
		a=a*a%mod;
		b>>=1;
	}
	return res;
}
int inv(int a,int b){
	return qmi(a,b-2);
}

void solve(){
	string s;cin>>s;
	map<char,int> mp;
	int res=0;
	for(int i=0;s[i];i++){
		mp[s[i]]++;
		res=max(res,mp[s[i]]);
	}
	cout<<s.size()-res<<endl;
}
signed main(){
	ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
	int T=1;
	cin>>T;
	while(T--){
		solve();
	}
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 0ms
memory: 3772kb

input:

2
abcb
xxx

output:

2
0

result:

ok 2 number(s): "2 0"

Test #2:

score: 0
Accepted
time: 28ms
memory: 3824kb

input:

11107
lfpbavjsm
pdtlkfwn
fmb
hptdswsoul
bhyjhp
pscfliuqn
nej
nxolzbd
z
clzb
zqomviosz
u
ek
vco
oymonrq
rjd
ktsqti
mdcvserv
x
birnpfu
gsgk
ftchwlm
bzqgar
ovj
nsgiegk
dbolme
nvr
rpsc
fprodu
eqtidwto
j
qty
o
jknssmabwl
qjfv
wrd
aa
ejsf
i
npmmhkef
dzvyon
p
zww
dp
ru
qmwm
sc
wnnjyoepxo
hc
opvfepiko
inuxx...

output:

8
7
2
8
4
8
2
6
0
3
7
0
1
2
5
2
4
6
0
6
2
6
5
2
5
5
2
3
5
6
0
2
0
8
3
2
0
3
0
6
5
0
1
1
1
2
1
8
1
7
5
3
4
4
1
8
5
5
8
8
6
3
0
2
3
2
1
5
0
0
9
3
3
4
8
4
0
4
2
6
6
0
8
7
4
3
9
3
4
2
5
8
8
8
6
1
4
4
2
7
2
8
6
4
4
8
7
8
4
9
3
8
0
7
7
2
6
0
0
5
4
0
7
5
4
2
1
6
7
5
2
4
4
7
3
3
2
5
4
8
5
0
3
5
1
2
3
0
4
7
...

result:

ok 11107 numbers